similar to: gapped sequence data summary

mydata <- read.table(textConnection(" Id cat1 location item_values p-values sequence a111 1 3002737 100 0.01 1 a112 1 3017821 102 0.05 2 a113 2 3027730 103 0.02 3 a114 2 3036220 104 0.04 4 a115 1 3053984 105 0.03 5 a118 1 3090500 106 0.02 8 a119 1 3103304

Hi, I am a beginner with R, and I think the answer to my question will seem obvious, but after searching and trying without success I've decided to post to the list. I am working with data loaded from a csv filewith these fields: order_id, item_value As an order can have multiple items, an order_id may be present multiple times in the CSV. I managed to compute the total value and the

https://bugs.freedesktop.org/show_bug.cgi?id=101404 Bug ID: 101404 Summary: GTX 970M (GM204-A) not powered off when not in use (DynPwr in stead of DynOff) Product: xorg Version: unspecified Hardware: Other OS: Linux (All) Status: NEW Severity: normal Priority: medium

I am trying to figure out how to write a conditional statement that will execute only if a specified variable is not empty. Right now my view looks like this: <dt>Building Regulations</dt> <% for link in @cat1 %> <dd><a href="<%= link.url %>"><%= link.title %></a></dd> <% end %> Action: @cat1 = Link.find(:all, :conditions

Hello, I can get the median for each factor, but I'd like another column to go with each factor. The nm column is a long name for the lvls column. So unique work except for the order can get messed up. Example: x =

This is driving me nuts:-) I''ve brought it down to a simplified case where I''m rendering this rjs template: page.insert_html :top, ''cat1'', "<li>Some list item</li>" According to FireBug, this is what I''m actually getting in the browser: try { new Insertion.Top("cat1", "<li>Some list

Hi, I am having some difficulties with matrix operations. It is a little hard to explain it so please bear with me. I have a very large data set, large enough that it needs to be split in parts in order to deal with. I can work things on these "parts" but the problem lies in adding together these parts for the final answer. So that been said, let's say that i split the data in 2

Hello, I'm looking for a solution for the following problem: 1) I have a folder with several csv files; each contains a set of measurement values 2) The measurements of each file belong to a position in a two dimensional matrix (lets say "B02.csv" belongs to position 2,2 3) The size of the matrix is fix 4) I cannot assure to have a csv file for each position 5) Each position

Hi, this appeared on Red Hat bugzilla and I''m not sure if customer presumption is correct `ip -6 route add 10::a120/124 via 10::a111` returns RTNETLINK answers : invalid argument His expected result is that route table to subnet 10::a120/124 should be added <snip> I know RFC3587 described prefix 001b is the unicast global address range assigned by IANA, and all other unicast

Hi there, I am confused about fucntion call. After defining a function, I called it within another function. dt<-cars; #a copy of R internal dataset "cars" created; dt$cat1<-ifelse(dt$speed<20,0,1); dt$ind<-ifelse(dt$speed<15,1,2); #group variable; freqtot <- function(data,var){ attach(data,warn.conflicts=FALSE) x1 <- data.frame(table(var))

http://bugzilla.mindrot.org/show_bug.cgi?id=422 Summary: /bin/sh: ./ssh-keygen: file or directory not found Product: Portable OpenSSH Version: 3.5p1 Platform: ix86 OS/Version: Linux Status: NEW Severity: normal Priority: P2 Component: Build system AssignedTo: openssh-unix-dev at mindrot.org

Hi, I have two data sets; one is a population and the other a sample of that population. I am trying to plot both on the same trellis display. # Example data set with two numerical attributes and two categorical pop <- data.frame(var1=rnorm(2000, 2000, 500), var2=rnorm(2000, 2000, 500)) cat<-(runif(2000)<=.5)+0 for(i in 1:length(cat)){ if(cat[i] == 0){ pop[i,"cat1"] =

Hi, I have the following dataset and I would like to create a dotplot with confidence limits: CAT1 CAT2 MEAN Lower Upper 1 1 1 0.619 0.392 0.845 2 1 10 1.774 1.030 2.518 3 1

I need to apply a yearly inflation factor to some wages and supply some simple sums by work category. I have gone at it with a brute force "for" loop approach which seems okay as it is a small dataset. It looks a bit inelegant and given all the warnings in the Intro to R, etc, about using loops I wondered if anyone could suggest something a bit simpler or more efficent? Example:

Dear list, I have a vector (array, table row, whatever is best) of frequency values for categories (or bins), and I need to find the median category. Trivial to do by hand, but I was wondering if there is a means to do it in R in an elegant way. The obvious medioan(vector) returns the median frequency for the binns, and that is not what I want. i.e,: freq cat1 1 cat2 10

This is... odd. >From my workstation, where I'm directly logged in, if I ssh to any CentOS 7 box, as myself, and try to run man, it fails. Example 1: man dd man: cannot write to /var/cache/man/cat1/dd.1.gz in catman mode dd. Example 2: man dd man: can't chmod (null): Bad address man: can't unlink (null): Bad address dd. In all cases, if I sudo -s to root, I have no trouble

Hello all, I have been meaning to learn R for a while and have just subscribed to this list. I am planning to give R a shot at one of my live projects. I am looking to explore graphical features of R on my data below. Sample Data: Cat1 - Cat2 - Cat3 - Cat4 - NumPeople - Salary H - L - H - L - 100 - 50000 L - L - L - L - 40 - 30000 - H - H - - 100 - 45000 Cat1 through Cat4 are

Hi. Whenever I notice a typo someplace, I fix it in a local "typo tree". Attached is 2 patches from that tree, one against OpenBSD and the other against Portable. Is it worth fixing these? -Daz. -- Darren Tucker (dtucker at zip.com.au) GPG key 8FF4FA69 / D9A3 86E9 7EEE AF4B B2D4 37C9 C982 80C7 8FF4 FA69 Good judgement comes with experience. Unfortunately, the experience

There is a problem with the last line of DISPLAY files in Syslinux 5.01. *** syslinux.cfg start *** DEFAULT cat1 PROMPT 1 F1 help.txt LABEL cat1 COM32 cat.c32 APPEND help.txt *** syslinux.cfg end *** *** help.txt start *** LINE 1 OF help.txt LINE 2 OF help.txt LINE 3 OF help.txt *** help.txt end *** Note that the last line in "help.txt" is "LINE 3 OF help.txt" and

Dear all, I am a relative novice with R, so please forgive any terrible errors... I am working with a GLM that describes a response variable as a function of a categorical variable with three levels and a continuous variable. These two predictor variables are believed to interact. An example of such a model follows at the bottom of this message, but here is a section of its summary table: