similar to: FW: recoding problem

Hi, I have attached the data files to this note. I use this code: library(zoo) z1 <- read.zoo("baltimorefludata.txt", format = "%m/%d/%Y", header = TRUE) z2 <- read.zoo("baltimorew.txt", format = "%Y%m%d", header = TRUE) z3<-merge(z1,z2) write.table(z3, "fluweatherdata_baltimore2.txt", sep="\t") R is writing the other data

Hi There, I get the following error from the code pasted below: Error in storage.mode(test) <- "logical" : object 'HGBmt12_Natl_Ave_or_Facility' not found library(RODBC) library(car) setwd("c://temp//cms") a07.connect <- odbcConnectAccess2007("DFC.accdb") sqlTables(a07.connect) ##provides list of tables## dataset <-

Hi, I am trying to get the following two timeseries (these are small subsets of the whole thing) into R so I can merge them using zoo. Timeseries 1=[ Date Count 9/28/2003 1505 10/5/2003 1535

Hi Y'all, I have some data in a table with 2 columns. There are two values: "Reduction" and "No Reduction. " I am trying to make a new variable change which recode the combinations from column 1 and 2 into a single number. Here is a snippet from the table: [1,] "NoReduction" "NoReduction" [2,] "Reduction"

Dear List, how can I obtain the value of r suqared for a non-linear model? For linear models it can be found in the summary() of the model but for non-linear models I just don't know. Please help! Anna

Dear folks, I have a question about the image() function in R. I found the following link talking about this but the replies didn't help with my situations. http://r.789695.n4.nabble.com/question-on-image-function-td839275.html#a839276 To be simple, I will keep using the example in the above link. Suppose the data are like x y mcpvalue 0.4603578

Dear friends, My dataset is like the following: x y mcpvalue 0.4603578 0.6247629 1.001 0.4603715 0.6247788 1.001 0.4603852 0.6247948 1.001 0.4110561 0.5664841 0.995 The x and y variables are unsorted. I use the function image(x,y,mcpvalue) to generate a plot, but the error is that "increasing 'x' and

Hi, I am trying to do a lasso regression using the lars package with the following data (see attached): FastestTime WinPercentage PlacePercentage ShowPercentage BreakAverage FinishAverage Time7Average Time3Average Finish 116.90 0.14 0.14 0.29 4.43 3.29 117.56 117.77 5.00 116.23 0.29 0.43 0.14 6.14 2.14 116.84 116.80 2.00 116.41 0.00 0.14 0.29 5.71 3.71 117.24

I've data that look like: Outcome V1_AA V1_EU V1_NA V2_AA V2_EU V2_NA 0 0.046 1.001 0.954 0.045 1.001 0.954 0 0.007 1 0.993 0.007 1 0.993 1 1.774 0.217 0.009 1.774 0.217 0.009 1 0.004 1.996 0 0.004 1.996 0 1

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Hello everyone, I use latex() (Hmisc) for report generation and thus have been affected by the problem with rounding decimals described, for example, in this post: http://thread.gmane.org/gmane.comp.lang.r.general/73287/focus=73287 In short, numbers often are printed with 15 or so decimals even if there far less significant digits. The problem has been confirmed by Frank Harrell and Thomas

Hi, I have numerical variable that I want to recode into categories '0' and '1 and more' and do analysis with that data. I have tried various of possibilities to do so, but I am sucked and nothing is working. recode(Q12, "0='A';1:30='B'") cut(Q12, breaks=c(0,1,30), lables=c('0', '1 and more')) cat(Q12, "0=0;1-33=1") What should

Hi, I can't for the life of me find how to do this in base R, but I'd be surprised if it's not possible. I'm just trying to replace multiple columns at once in a data frame. #load example data data(api) #this displays the three columns and eight rows i'd like to replace apiclus1[ apiclus1$meals > 98 , c( "pcttest" , "api00" , "sch.wide" ) ]

Dear All, I am trying to recode a variable using the functions provided by "memisc" package. Actually I am following the examples on page 9-10 of the vignette: -------------------------------------------------------------------------- d.fig <- within(d.fig,{ sev <- recode(sev, 1 -> 0.9, 2 -> 1.0, 3 -> 1.1, 4 ->

Dear R users, I have a very simple question. What is the easiest way to recode data in one of the columns of a data frame and put it into a new column? For example, here is a simple data frame: var1 1 1 2 2 3 3 How do I add a new column to data - 'var2' in which I group values in 'var1', for example: var1 var2 1 1 4 2 2 4 3 3 5 It's got to

Thank you all for your help, it worked! Op 23 mei 2018 om 19:27 heeft marta azores <martazores at gmail.com<mailto:martazores at gmail.com>> het volgende geschreven: Try that code NewDF<-DF[!DF$Anxiolytics==1,] 2018-05-23 10:14 GMT+00:00 Lisa van der Burgh <lisavdburgh at hotmail.com<mailto:lisavdburgh at hotmail.com>>: Hi all, I have a very general question and I

Hello everyone, I can not get the name of the recoding file of agents calls. I set agents.conf as following: ; Enable recording calls addressed to agents. It's turned off by default. recordagentcalls=yes ; ; The format to be used to record the calls (wav, gsm, wav49) ; By default its "wav". ;recordformat=gsm ; ; Insert into CDR userfield a name of the the created recording ; By

Hello all. Thanks for FLAC. It's served me well for the past few years. Is there a program out there to truncate a FLAC file without decoding/recoding it ? Preferably command-line (I already know at what point I want to truncate it). Thanks in advance. -- Andr? Majorel <URL:http://www.teaser.fr/~amajorel/> Do not use this account for regular correspondence. See the URL above for

>From: "Stuart Leask" <stuart.leask at nottingham.ac.uk> > >Hi there. When I wished to recode two variables in SPSS, I could use the >command RECODE: > >recode VAR1 VAR2 VAR3 etc. (1=0) (2=1) (3,MISSING=SYSMIS) (else=0). > >In R, I can 'hand-crank' each variable (using ifelse, or if the data is in a >matrix by logical tests, or no doubt numerous

hi R-listers, I would like some help recoding a variable. I have a dataframe 'cause' that translates between a set of codes: acc nds - - 1 2 3 4 5 8 ... ... the desired result for dataframe 'p': a - 1 5 5 would be: a b - - 1 2 5 8 5 9 I have tried: transform(p, b=cause$nds[cause$acc==p$a]) but for some reason it complains about the difference in length between the