similar to: Obtaining the unmerged cases from one of the two data set

See FAQ #4 on the sqldf github home page. On Fri, Aug 11, 2017 at 9:21 AM, Mangalani Peter Makananisa <pmakananisa at sars.gov.za> wrote: > Dear all, > > I recently read the book " R data preperation and manipulation using sqldf package" by Djoni Darmawikarta > However, I have a problem with manipulation of dates using this package, I do not get the expected results.

Dear all, I recently read the book " R data preperation and manipulation using sqldf package" by Djoni Darmawikarta However, I have a problem with manipulation of dates using this package, I do not get the expected results. Do I need to install some packages to be able to subset the data by dates in sqldf? I am not getting Djoni Darmawikarta email address. Please see the practice

A better thanks would be to post the solution that met your needs... particularly since in spite of our efforts it appears we may not have understood your problem. A small sample data set generated with dput along with your code would be helpful in making sure others learn along with you. -- Sent from my phone. Please excuse my brevity. On July 11, 2017 12:56:45 AM PDT, Mangalani Peter

Thank you very much for the support. I have just used the reshape library and my problem was solved. Kind regards, Peter -----Original Message----- From: Jeff Newmiller [mailto:jdnewmil at dcn.davis.ca.us] Sent: 10 July 2017 03:52 PM To: r-help at r-project.org; Mangalani Peter Makananisa; r-help at r-project.org Cc: Vito Ricci (vito_ricci at yahoo.com) Subject: Re: [R] dplyr help I am

I am pretty sure that this is not a question about dplyr... it is a question about tidyr. Look at the help file ?tidyr::spread. If I understand your question (I may not, because you gave no example of input/output data), the answer is no, the column names come from the column named by the key parameter and the values that fill those columns come from the column named by the value parameter.

> On Sep 11, 2017, at 1:05 AM, Mangalani Peter Makananisa <pmakananisa at sars.gov.za> wrote: > > Hi all, > > I am trying to create a new variable called Fiscal Year (FY) using case expression in sqldf and I am getting a null FY , see the code below . > > Please advise me as to how I can do this mutation. > > library(zoo) > library(lubridate) >

2018-03-3 in your code should be 2018-03-31. The line then'201415' needs to be fixed. When posting please provide minimal self-contained examples. There was no input provided and library statements not relevant to the posted code were included. Fixing the invalid date and bad line, getting rid of those library statements that are unnecessary and providing some test input, it works

Sent from Samsung tablet. Dear all, ? I recently read the book ? R data preperation and manipulation using sqldf package? ?by Djoni Darmawikarta? However, I have a problem with manipulation of dates using this package, I do not get the expected results. Do I need to install some packages ?to be able to subset the data by dates in sqldf? ? I am not getting Djoni Darmawikarta?email address. ?

Dear R-Gurus, I am trying to read in data with 24,349,113 rows to R-3.3.3 (64 bit) and have used the library "data.table" and It managed to read 23,347,070 rows and the remainder was 2,043 rows only. Could you please advise me as to which library/R-commands is suitable to read the full data in to R? Kind regards, Mangalani Peter Makananisa (5786) South African Revenue Service

Dear R Gurus, I am currently working on the two dataset ( A and B), they both have the same fields: ID , REGION, OFFICE, CSTART, CEND, NCYCLE, STATUS and CB. I want to merge the two data set by ID. The problem I have is that the in data A, the ID's are unique. However in the data set B, the ID's are not unique, thus some repeat themselves. How do I the merge or retrieve the

Hi all, I am trying to create a new variable called Fiscal Year (FY) using case expression in sqldf and I am getting a null FY , see the code below . Please advise me as to how I can do this mutation. library(zoo) library(lubridate) library(stringr) library(RH2) library(sqldf) cr$ReportDate = as.Date(cr$ReportDate, format ='%Y-%m-%d') > cr2 = sqldf(" select

HI all, Is it possible to use one column spread on multiple columns values. example spread( Key_col, value1:value7) spreading Key_col to variable value1, value2, ....... Value7 Please advise, Kind regards Mangalani Peter Makananisa (5786) South African Revenue Service (SARS) - HO +2782 456 4669 / +2712 422 7357 Please Note: This email and its contents are subject to our email legal notice

Dear all, I'm using garchFit from fSeries package and I am not getting the desired results (error message : could not find function "garchFit" ). Would you please advise as to how I can build an ARIMA(p, d, q) - GARCH(p,q) model using R see the attached data and R-output. Thanking you in advance Kind regards Mangalani Peter Makananisa Statistical Analyst South

Dear all, Please help me with the R code which compute SCHEFFE TEST Thanking you in advance Kind regards Mangalani Peter Makananisa Statistical Analyst South African Revenue Service (SARS) Segmentation and Research : Data Modelling Tel: +2712 422 7357 Cell: +2782 456 4669 Fax:+2712 422 6579 Please Note: This email and its contents are subject to our email legal notice

Dear R gurus, I am currently using the chron package for date manipulation in R and I am able to control the date which take the format - 1998/07/03, and - 2006-09-15 (date without time) Library(chron) As.Date(2006-09-15, format = '%Y-%m-%d') However I have a problem with the date containing only the year and month (i.e. 2006-09, 2007/08, 200609).

Hi something like dcast(temp2, minuty~pokus) ? > dput(temp2) structure(list(pokus = structure(c(1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 5L, 5L, 6L, 6L, 7L, 7L, 8L, 8L ), .Label = c("T42", "T43", "T44", "T45", "T46", "T47", "T48", "T49"), class = "factor"), minuty = structure(c(2L,

Hopefully this is an easy problem... I'm trying to add a partitioned rank column to a data frame where the rank is calculated separately across a partition by categories, the way you could easily do in SQL. I found this solution in the archives that looked like it might work: http://tolstoy.newcastle.edu.au/R/e11/help/10/09/8675.html The example has a data frame with several car companies,

I have the data similar to the following in a data frame: LastName Department Salary 1 Johnson IT 56000 2 James HR 54223 3 Howe Finance 80000 4 Jones Finance 82000 5 Norwood IT 67000 6 Benson Sales 76000 7 Smith Sales 65778 8 Baker HR 56778 9 Dempsey HR 78999 10 Nolan

How do you label Xtick and Ytick marks with Currency symbols: $2000 instead of 2000? I would like to add dollar symbols to tickmarks on boxplots, histograms and back-to-back histograms. My Examples (requiring the lattice and Hmisc packages): data(case0102, package="Sleuth2") str(case0102) boxplot(Salary~Sex, case0102) histogram(~ Salary | Sex, data=case0102) require(Hmisc) #

Hi, netters, First of all, thanks a lot for all the prompt replies to my earlier question about "merging" data frames in R. Actually that's an equivalence to the "join" clause in mysql. Now I have another question. Suppose I have a data frame X with lots of columns/variables: Name, Age,Group, Type, Salary. I wanna do a subtotal of salaries: aggregate(X$Salary,