similar to: library ts

Dear list, I am using R.2.11.1 version on a PC. I downloaded successfully gplots_2.8.0 but I could not find where to download caTools > library("gplots") Loading required package: caTools Error: package 'caTools' could not be loaded In addition: Warning message: In library(pkg, character.only = TRUE, logical.return = TRUE, lib.loc = lib.loc) : there is no package called

Hi I got the following error using as.xts Error in xts(x, order.by = order.by, frequency = frequency, ...) : NROW(x) must match length(order.by) Here is how the data looks like > d1 <- read.csv(file.path(dataDir,"AppendixA-FishCountsTable-2009.csv"), as.is=T) > d1[1:3,] dive_id date time species count size site depth level TRANSECT VIS_M 1 62 10/12/2009

Hi, Here is my data, the first 10 rows > u=regCond_all[1:10,] > dput(u) structure(c(999, 999, 999, 999, 999, 999, 999, 999, 999, 999, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 99, 1.9, 2, 1.97, 1.99, 1.83, 1.78, 1.6, 1.52, 1.52, 1.36, 10.53, 9.88, 9.88, 10.53, 10.53, 10.53, 5.26, 9.88, 10.53, 10.53, 5.4, 5.57, 5.46, 5.34, 5.5, 5.59, 5.62, 5.76, 6.23, 6.19,

Hi, I was trying to run the following, where the labels on the x axis are dates and need to be converted to characters. It did not work. Any help would be appreciated. Thanks. > text(axTicks(1),par("usr)[3]-2,srt=45,adj=1,labels=as.character(c("2008-01-08","2008-08-10","2008-08-22","2008-09-03", "2008-09-15")), xpd=T, cex=0.8) Error:

Hello, I would like to convert date as a factor to represent time in a repeated measure situation in the following code. How would I do that? > d <- read.csv(file.path(dataDir,"data.csv"), as.is=T,stringsAsFactors = FALSE) > d[1:2,] id date a b c y 1 1 8/6/2008 Red 15 B 22 2 1 8/6/2008 Green 15 B

Hello, This should be pretty simple but I cannot get it right. Please point to the right code. Thanks. > last <- read.csv(file.path(dataDir,"plot1.csv"), as.is=T,stringsAsFactors = FALSE) > last date r_wvht 1 8/6/2008 0.9766667 2 8/8/2008 0.7733333 3 8/11/2008 1.4833333 4 8/13/2008 1.5766667 5 8/14/2008 1.3900000 6 8/18/2008 0.7800000 7 8/20/2008

I was wondering why I get <NA> instead of the timestamp in the following. Thanks. > dataDir <- file.path(wd) > localRaw <- read.csv(file.path(dataDir,"LOCAL.csv"), as.is=T,stringsAsFactors = FALSE) > localRaw[1:2,] Year Month Day hour minute second Temp1mab Temp7mab Temp14mab Salinity1mab 1 2009 10 5 0 0 0 11.288 13.675 13.743 33.513

Hello, I have the following design, counts were collected at different transects, different depths and different sites at different times. Time is continuous and assumed to be random, all the others are categorical fixed where transect is nested within depth which is nested within site. I would like an expert opinion about the following code where intercept is modeled as random (I am not sure

hi, When I type library(ts) (I am working on an ubuntu machine), I get the following error: > library(ts) Error in library(ts) : there is no package called 'ts' I did a few google searches and it seems like ts is no longer available....is that correct? It seemed to me that I would need to download Rmetrics instead....is that the replacement for ts. Please let me know how I can get

Hello, I looked in the R-help but could not find an archive addressing the following. I would like to convert a character to numeric after reading a file with RDS extension. After using as.numeric, I checked if it is numeric. It was not converted. Please help. Here is my code >Report <- readRDS(file="RDS/Report.RDS") > Report[1:2,] dive_id date

"vector[s]" should be plural in line 54 ... cheers Ben Bolker ---- Index: ts.Rd =================================================================== --- ts.Rd (revision 75540) +++ ts.Rd (working copy) @@ -54,7 +54,7 @@ } \details{ The function \code{ts} is used to create time-series objects. These - are vector or matrices with class of \code{"ts"} (and additional

Hello, I have the following loop for two data sets: diveData_2008 and diveData_2009. It uses two other data: diveCond_all and fishTable. The problem is at the point to identify the dive_id for the given index (index is timestamp). It keeps on saying for the1st loop Error in fishReport$dive_id[i] <- dive_id : replacement has length zero for the 2nd loop Error in fishReport$dive_id[i + j] <-

Well, I upgraded to a later release and have been having good luck (R vers. 0.65.0) I haven't upgraded my Red-Hat linux from 5.2 so I had to compile from source , ... so far so good. My problem is with the time series functions [library(ts)]. I'm trying to use the autocorrelation function-acf() and am having problems with it. mainly an error ERROR -Couldn't find function

Hello, I am trying to get a library for statistical computing. For example, I have to compute the ARIMA parameters of time series and I?d like to do that out of my C/C++ or Fortran source code. The thing I already managed is how to get the standalone library "Rmath", but in this library the ts-modul is not included. Thus, my question is: How can I get a library including the

I am running R 1.2.2 under Linux. When using the function stl in the ts library, how can I save the seasonal component? What I would like was something like: library(ts) data(nottem) data.stl <- stl(nottem, "per") x <- data.stl$sea This what I get: > x NULL I would, however, like to store in x the seasonal component. Thanks in advance. Francisco. -- Francisco

Hello, I have two time series objects, 1 is yearly (population) and the other is quarterly (bankruptcy statistics). I would like to produce a quarterly time series object that consists of bankruptcy/population. Is there a pre-built function to intelligently divide these time series: br.ts = ts(data=br.df[,-1], frequency = 4, start=c(2001,1), end=c(2008,2)) distPop.ts = ts(data=distPop.df[,-1],

Hi, I have two questions about ts. (1) How do I subset a ts object and still preserve the time index? for example: > x=ts(1:10, frequency = 4, start = c(1959, 2)) # the ts object > x Qtr1 Qtr2 Qtr3 Qtr4 1959 1 2 3 1960 4 5 6 7 1961 8 9 10 I don't want the 1st 2 elements, so I could subset like this: > x[3:length(x)] [1] 3 4 5 6 7 8 9 10

The following seems confused (0.65 snapshot) > x <- ts(1:20) > window(x, 1, 1) Time Series: Start = c(1, 1) End = c(1, 1) Frequency = 1 [1] 1 Warning message: Not returning a time series object in: [.ts(x, i) (it of class ts, as the print method shows). Under 0.64.2 it is even more confusing: > x <- ts(1:20) > window(x, 1, 1) Warning: Not returning a time series object

I'm trying to convert a column of a table into a ts object. The data is monthly, so I want the ts frequency to be 12. I did this ... > filings.ts = as.ts(Filings.100K, frequency=12) > filings.ts Time Series: Start = 1 End = 311 Frequency = 1 [1] 246.9336 305.6789 ... ... > tsp(filings.ts) [1] 1 311 1 > tsp(filings.ts) <- c(1,311,12) Error in attr(x, "tsp")

>>>>> On Fri, 02 Jul 1999, Adrian Trapletti <Adrian.Trapletti@wu-wien.ac.at> said: Adrian> There seems to be a problem with plot.ts (R Version 0.64.2) > x<-cbind(1:10,2:11) > x<-as.ts(x) > plot(x) Adrian> Error: subscript (20) out of bounds, should be at most 10 This is definitely a bug --> CC: R-bugs ALL NOTE : This is *not* new