similar to: setting up dates

Dear R People: I have a zoo object with its date index as a factor. > xAle1.zoo$index Error in xAle1.zoo$index : $ operator is invalid for atomic vectors > str(xAle1.zoo) Class 'zoo' atomic [1:32] 1253 1316 1038 1157 1710 1489 1159 1142 945 1245 ... ..- attr(*, "index")= Factor w/ 32 levels "04/16/09","04/17/09",..: 1 2 3 4 5 6 7 8 9 10 ... >

Everything is ok on Firefox, IE, and iPad. Thanks, Erin On Tue, Jan 8, 2013 at 7:58 PM, Erin Hodgess <erinm.hodgess at gmail.com> wrote: > Dear R People: > > Has anyone used R2HTML in web files that were on the Blackboard LMS, please? > > I'm starting to do these but wanted to know if there were any > potential pitfalls. > > Thanks, > Erin > > > --

Thank you! On Thu, Aug 17, 2017 at 4:55 PM, Bert Gunter <bgunter.4567 at gmail.com> wrote: > r-package-devel is probably a better place to post this, especially if > you do not get a satisfactory reply here. This list is about R > programming, as you presumably know; your query is not. > > Cheers, > Bert > > > Bert Gunter > > "The trouble with having

Hello again: Here is a solution to the dates without leading zeros: pou1 <- function(x) { #Note: x is a data frame #Assume that Column 1 has the date #Column 2 has station #Column 3 has min #Column 4 has max library(stringr) w <- character(length=nrow(x)) z <- str_split(x[,1],"/") for(i in 1:nrow(x)) { u <-

Dear R People: So thanks to your help, I have the following: > dog3.df <- read.delim("c:/Users/erin/Documents/dog1.txt",header=FALSE,sep="\t") > dog3.df V1 V2 1 1/1/2000 dog 2 1/1/2000 cat 3 1/1/2000 tree 4 1/1/2000 dog 5 1/2/2000 cat 6 1/2/2000 cat 7 1/2/2000 cat 8 1/2/2000 tree 9 1/3/2000 dog 10 1/3/2000 tree 11 1/6/2000 dog 12 1/6/2000

Dear R People: I have a monthly time series which runs from January 1998 to December 2010. When I use tsp I get the following: > tsp(ibm$ts) [1] 1998.000 2010.917 12.000 Is there an easy way to convert this to a seq.Date object, please? I would like to have something to the effect of 1998/01/01 .... 2010/12/01 Thanks, Erin -- Erin Hodgess Associate Professor Department of Computer

Dear R People: I have a data frame with the two following date columns: > a.df[1:10,c(1,6)] DATE DEATH 1207 2009-04-16 2009-05-06 1514 2009-04-16 2009-05-06 2548 2009-04-16 2009-05-08 3430 2009-04-16 2009-05-09 3851 2009-04-16 2009-05-09 3945 2009-04-16 2009-05-09 7274 2009-04-16 2009-05-12 7532 2009-04-16 2009-05-12 7651 2009-04-16 2009-05-12 8495 2009-04-16 2009-05-13 >

r-package-devel is probably a better place to post this, especially if you do not get a satisfactory reply here. This list is about R programming, as you presumably know; your query is not. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic

Dear R People: Is there a way to "guarantee" that breaks=n will give you exactly n breaks, please? I'm fairly certain that the answer is "no", but thought I'd check. Thanks, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: erinm.hodgess at gmail.com

Dear R People: I have dates as factors in the following: > poudel.df$DATE [1] 1/2/2011 1/4/2011 1/4/2011 1/4/2011 1/6/2011 1/7/2011 1/8/2011 [8] 1/9/2011 1/10/2011 Levels: 1/10/2011 1/2/2011 1/4/2011 1/6/2011 1/7/2011 1/8/2011 1/9/2011 > I want them to be "regular" dates which can be sorted, etc. But when I did this: > as.character(poudel.df$DATE) [1]

Dear R People: Is there a way to find which objects are functions via ls(), please? I'm sure that there is, but I'm not sure how. Thanks, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: erinm.hodgess at gmail.com

Dear R People: The aggregate function works very well on regular time series. Is there a version for zoo or its that would take daily data and convert it to monthly, please? Thanks in advance, Sincerely, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: erinm.hodgess at gmail.com

Dear R People: Suppose I have the following: "pi/2" and I would like it to be 1.57..... Using as.numeric, here is my result: > as.numeric("pi/2") [1] NA Warning message: NAs introduced by coercion > Is there a way to produce the numeric result, please? Thanks, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of

Dear R People: I have a question, please: I want to install a package from R CMD INSTALL and I have a boatload of configure args. I want to put them into a file. How do I point the R CMD INSTALL to that file, please? Thanks, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: erinm.hodgess at gmail.com

Dear R People: Is it possible to run R on an iPad, please? For some reason, I'm thinking that you can't have Fortran, C, etc., so you can't do it. But I thought I would check anyway. Thanks, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: erinm.hodgess at gmail.com

Dear R People: Hello again! I found something unusual in the behavior of the "endpoints" function from the xts package: > x1 <- ts(1:24,start=2008,freq=12) > dat <- seq(as.Date("2008/01/01"),length=24,by="months") > library(zoo);library(xts) > x2 <- zoo(1:24,order=dat) > #Here is the surprise: > endpoints(as.xts(x1),'quarters')

Hello I would like to build R from source and use the PGI compiler, rather than the GCC compiler. I saw the instructions for the Intel compiler in the R Installation Manual, but I didn't see the PGI. I tried a few times without instructions, but without success. Any suggestions would be most welcome. Also, I hope this is the right group for the question. Sincerely, Erin -- Erin

Dear R People: I have generated the following table: > table(zza$DEATH,zza$GENDER) F M 2009-04-21 0 1 2009-04-22 4 2 2009-04-24 6 0 2009-04-25 1 3 2009-04-26 2 0 2009-04-28 3 0 2009-04-29 2 2 However, instead of total counts in the F and M columns, I would like percents. How would I do this, please? thanks, Erin -- Erin

Dear R People: I have the following code that I use to convert a monthly zoo object to a data.frame, and it works perfectly: library(tseries) z <- get.hist.quote(instrument=inst1, start=start1,end=end1, quote=quot1,comp = "m") y <- as.ts(aggregate(z, as.yearmon, tail, 1)) y.df <- data.frame(y=y,time=time(y)) y.df$x <- ts(y.df[,1]) tsp(y.df$x) <-

If you are writing a new package I don't see why you should restrict yourself to S3 or S4 classes. Your "new package" can certainly build on other packages. (Why not?) As I wrote in my previous email, if you are dealing with time series you might want to consider appropriate classes already defined in other packages, such as those obtained via library(fpp3) In my work, I deal with