similar to: Summing over intervals

Displaying 20 results from an estimated 10000 matches similar to: "Summing over intervals"

2009 May 31
7
[mapstraction commit] r11 - Added functionality to automatically load scripts needed.
Author: robert.moran Date: Sun May 31 11:13:23 2009 New Revision: 11 Modified: trunk/source/mxn.core.js trunk/source/mxn.js trunk/source/mxn.yahoo.core.js trunk/tests/index.htm Log: Added functionality to automatically load scripts needed. Allowed mapstraction default constructor to have provider omitted (will use first loaded provider). Minor change to yahoo implementation -
2005 Jan 28
2
Direct sum of matrices
Hi R users: How can I built a direct sum function of matrices in R? I mean A(mxn), B(pxq), C(rxs),... X<-ds(A,B,C,...) X = [ A, 0, 0 0, B, 0 0, 0, C] ((m+p+r+...) x (n+q+s+...)) Thank you for your help. Kenneth -- Using Opera's revolutionary e-mail client: http://www.opera.com/m2/
2010 Apr 25
3
Noobie question on aggregate tapply and by
I have a 43MB dataframe ( 5 variables) and I'm trying to summarize subsets of the data. I've RTFM ( not very clear) and looked at a variety of samples but cant seem to figure out how to make these functions work. A sample of what I want to do would be this: ids<-seq(1,50) years<-c(rep(5,10),rep(6,10),rep(7,10),rep(8,20))
2010 Apr 30
6
addListener
I am trying to use the marker method addlistener(). A simplified version of what I''m trying to do: var map; var marker; map = new mxn.Mapstraction(''myMap'',''google''); map.setCenterAndZoom(new mxn.LatLonPoint(45.559242,-122.636467), 15); marker = new mxn.Marker(new mxn.LatLonPoint(45.559242,
2011 Jan 04
5
Webkit - can't find variable: mxn
In my app (v2.0.15) and on the mapstraction demo the first time I load the page in Safari I get the error "Can''t find variable: mxn" and the map doesn''t load. http://mapstraction.appspot.com/ mapstraction.googlecode.com/svn/trunk/source/mxn.core.js:6ReferenceError: Can''t find variable: mxn I''ve seen a few old posts in the list archives about similar
2011 Sep 12
5
Hourly data with zoo
I have date data as a numeric and hourly data in 0 to 2300 hours in a dataframe. d <- rep(20110101,24) h <- seq(from = 0, to = 2300, by = 100) df <- data.frame(LST_DATE = d, LST_TIME = h, data = rnorm(24, 0, 1)) S <- chron(dates. = as.character(df$LST_DATE), times. = paste(as.character(df$LST_TIME/100), ":0:0", sep = ""), format =
2010 Jun 05
5
Matrix to Vector
Given a matrix of m*n, I want to reorder it as a vector, using a row major transpose. so: > m<-matrix(seq(1,48),nrow=6,byrow=T) > m [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,] 1 2 3 4 5 6 7 8 [2,] 9 10 11 12 13 14 15 16 [3,] 17 18 19 20 21 22 23 24 [4,] 25 26 27 28 29 30 31 32 [5,] 33 34 35 36 37
2010 Aug 11
2
Sweeping a zoo series
Given a long zoo matrix, the goal is to "sweep" out a statistic from the entire length of the sequences. longzoomatrix<-zoo(matrix(rnorm(720),ncol=6),as.yearmon(outer(1900,seq(0,length=120)/12,"+"))) cnames<-c(12345,23456,34567,45678,56789,67890) colnames(longzoomatrix)<-cnames longzoomatrix[1:24,] 12345 23456 34567 45678
2009 Nov 19
5
speaking about mxn at #geomob
Fellow mapstractors, I''m speaking about mapstraction tonight at a London neogeo event - #geomob http://gmdlondon.ning.com/events/geomob-november basically I''ll jus be explaining what mxn is, how ift can be used, and a brief history of the project and trying to encourage more people to contribute. My slides are here: http://www.slideshare.net/lokku/mapstraction-2537688 let me
2012 Apr 02
2
Error in gamma(delta + (complex(0, 0, 1) * (x - mu))/alpha) : unimplemented complex function
I am trying to obtain the grafic of a pdf . but this error keeps showing . Here is the code MXN.fd = function(x,alpha,beta,mu,delta) { A = (2*cos(beta/2))^(2*delta) B = 2*alpha*pi*gamma(2*delta) C = (beta*(x-mu))/alpha D = abs(gamma(delta + (complex(0,0,1)*(x-mu))/alpha)^2) M = A/B*exp(C)*D M plot(x,M,type="l",lwd=2,col="red") } alpha = 0.02612297 beta = -0.50801886 mu =
2011 Jul 27
2
Elegant way to subtract matrix from array
there are really two related problems here I have a 2D matrix A <- matrix(1:100,nrow=20,ncol =5) S <- matrix(1:10,nrow=2,ncol =5) #I want to subtract S from A. so that S would be subtracted from the first 2 rows of #A, then the next two rows and so on. #I have a the same problem with a 3D array # where I want to subtract Q for every layer (1-10) in Z # I thought I solved this one
2010 Aug 30
4
Implementation of openBubble for openlayers
Hello, I''m back with another problem, the method Marker.openBubble isn''t implemented yet. I tried to hack a solution but I encountered some problems. When the popup is created in the toProprietary method from Marker in mxn.openlayers.core.js, I keep a reference on it with a this.infoPopup = popup. Later in the openBubble method, I do :
2009 Oct 22
6
Mapstraction V2 Geocoder?
Hey all, I''m wondering about your thoughts on upgrading the Geocoder to use Mapstraction V2. Currently it uses the old syntax (i.e., for LatLonPoint, etc.): http://mapstraction.appspot.com/#geocoding Moving from V1 to V2 is fairly simple changes to the code. However, I wonder whether we want to update the way the geocoder is structured, as well? Some options: 1) Roll geocoding
2003 Mar 12
7
R help
Dear friends, I work with Matlab and now a bit in trouble with getting used to R. Could you give me some help with the following questions: 1. how to generate the random matrix mxn with constant mean and variance, say N(0,1)? 2. how to create a code (function), say “myfunction”, and make it available for use every time I run R? 3. how to make a package, say “e1071”, available for use
2010 Jul 30
2
Summing by index
# build a sample data frame illustrating the problem ids<-c(rep(1234,5),rep(5436,3),rep(7864,4)) years<-c(seq(1990,1994,by=1),seq(1991,1993,by=1),seq(1990,1993,by=1)) data<-seq(14,25,by=1) data[6]<-NA DF<-data.frame(Id=ids,Year=years,Data=data) DF Id Year Data 1 1234 1990 14 2 1234 1991 15 3 1234 1992 16 4 1234 1993 17 5 1234 1994 18 6 5436 1991 NA 7
2010 May 05
1
extracting a matched string using regexpr
Given a text like I want to be able to extract a matched regular expression from a piece of text. this apparently works, but is pretty ugly # some html test<-"</tr><tr><th>88958</th><th>Abcdsef</th><th>67.8S</th><th>68.9\nW</th><th>26m</th>" # a pattern to extract 5 digits > pattern<-"[0-9]{5}" #
2006 Jul 06
3
Comparing two matrices [Broadcast]
It might be a bit faster to do matrix indexing: R> tbm <- as.matrix(tb) # turn it into a character matrix R> tmat[cbind(match(tbm[,2], rownames(tmat)), match(tbm[,1], colnames(tmat)))] <- 1 > tmat Apple Orange Mango Grape Star A 1 1 1 0 0 O 1 1 0 0 0 M 0 0 1 0 0 G 0 0 0 0 0 S 1 1 1 0
2006 Jul 06
3
Comparing two matrices
hi: I have matrix with dimensions(200 X 20,000). I have another file, a tab-delim file where first column variables are row names and second column variables are column names. For instance: > tmat Apple Orange Mango Grape Star A 0 0 0 0 0 O 0 0 0 0 0 M 0 0 0 0 0 G 0 0 0 0 0 S 0 0 0 0 0
2010 Aug 09
3
New build 2.0.5
Just applied some changes from Adam and Dylan and uploaded a new build. Good stuff guys, thanks. Get 2.0.5 here: http://github.com/mapstraction/mxn/downloads Derek -- Derek Fowler m. +44 (0) 7966 512 369 e. dezfowler at gmail.com -------------- next part -------------- An HTML attachment was scrubbed... URL:
2005 Apr 15
4
function corresponding to map of perl
Is there a function in R that corresponds to the function ``map'' of perl? It could be called like: vector.a <- map( vector.b, FUN, args.for.FUN ) It should execute for each element ele.b of vector.b: FUN( vector.b, args.for.FUN) It should return a vector (or data.frame) of the results of the calls of FUN. It nearly works using: apply( data.frame( vector.b ), 1, FUN,