Displaying 20 results from an estimated 2000 matches similar to: "Stacked Histogram, multiple lines for dates of news stories?"
2017 Aug 28
5
"Improvement with the R code"
Hello,
I am trying to implement a formula
aij= transition from state S_i to S_j/no of transition at state S_i
Code I have written is working with three state {1,2,3 }, but if the number
of states become={1,2,3,4,......n} then the code will not work, so can some
help me with this.
For and some rows of my data frame look like
2017 Aug 28
0
"Improvement with the R code"
Hi,
I think you overthought this one a little bit, I don't know if this is the
kind of code you are expecting but I came up with something like that:
generate_transition_matrix <- function(data, n_states) {
#To be sure I imagine you should check n_states is right at this point
transitions <- matrix(0, n_states, n_states)
#we could improve a little bit here because at
2009 Jul 09
3
Looking for recommendations for blocking hacking attempts
Hello:
I have been looking into projects that will automatically
restrict hacking attempts on my servers running CentOS 5.
I think the two top contenders are:
DenyHosts - http://denyhosts.sourceforge.net
Fail2ban - http://www.fail2ban.org
>From what I see, DenyHosts only blocks based on failed
SSH attempts whereas Fail2ban blocks failed attempts
for other access as well.
The main benefit
2012 Aug 14
2
igraph: Turn multiple edges into weights
Dear all,
I have some network data - about 300 vertices and several thousand edges. I
am looking for a way to turn multiple edges into weights of the edges. I
looked around and - surprisingly? - haven't found anything. Is there an
easy way to do this?
Best, Jonas
[[alternative HTML version deleted]]
2007 Feb 20
1
Reshape (pivot) question
Hi R-users,
I have a data set like this (first ten rows):
id patient_id date code class eala ID1564262 1562 6.4.2006 12:00 5555 1
NA ID1564262 1562 6.4.2006 12:00 5555 1 NA ID1564264 1365 14.2.2006 14:35
5555 1 50 ID1564265 1342 7.4.2006 14:30 2222 2 50 ID1564266 1648 7.4.200614:30
2222 2 50 ID1564267 1263 10.2.2006 15:45 2222 2 10 ID1564267 1263
10.2.200615:45
3333 3 10 ID1564269 5646
2012 Jul 11
3
Subset based on multiple values
I'm stuck on a seemingly simple problem. I'm trying to subset the data by
several numbers and it cuts out half of the rows. Here is the sample code:
test <- as.matrix(c(1,1,1,1,3,3,7,7,7,7))
Count <- tapply(test[,1], test[,1], length) # count for each value
spp <- unique(test[,1])
Count1 <- as.data.frame(cbind(Count,spp))
Max <- max(Count)
Count1$sppMax <-
2001 Mar 16
1
combine dataset
Hi,
I have two data sets look like below:
==========================
state count1 percent1
CA 19 0.34
TX 22 0.35
FL 11 0.24
OR 34 0.42
GA 52 0.62
MN 12 0.17
NC 19 0.34
state count2 percent2
FL 22 0.35
MN 22 0.35
CA 11 0.24
TX 52 0.62
==========================
How to combine these two data set and make it look
like below?
2009 Sep 19
2
Counting observations of a combined factor
#I have a dataset with two factor. I want to combine those factors into
a single factor and count the number of data values for each new factor.
The following gives a comparable dataframe:
a <- rep(c("a", "b"), c(6,6))
b <- rep(c("c", "d"), c(6,6))
df <- data.frame(f1=a, f2=b, d=rnorm(12))
df
# I use the 'interaction' function to combine
2002 Jun 18
3
FINDNEXT problem, w2k and linux smbfs
I have inconsistent directory listing on share mounted on linux from windows 2k.
Some time not all files appear in the directory listing.
If reading directory listing multiple times (60-200 times) files listed originally would have one or two files missing in one of consecutive lists. The same problem appear as well if you are making backup of Windows files from multiple directories, there are
2009 Oct 29
1
operation with if/else on a dataframe
Hi to all,
I have this dataframe (I show the first six rows)
>head(table)
A R Fold.Change P.Value
Count1 Count2
1 ENSRNOE00000000002_at 0 1.13 0.60 1
1
2 ENSRNOE00000000009_at 0 -1.04 0.73 3
3
3 ENSRNOE00000000020_at 0 -1.08
2004 Jul 07
1
Histograms, density, and relative frequencies
R-users,
I have been using R for about 1 year, and I have run across a
couple of graphics problem that I am not quite sure how to address. I have
read up on the email threads regarding the differences between density and
relative frequencies (count/sum(count) on the R list, and I am hoping that
someone could provide me with some advice/comments concerning my
approach. I will admit
2009 Nov 14
2
formatting dates in axis labels (ggplot2)
I'm having trouble figuring out how to format Date variables when used
as axis labels in graphs.
The particular case here is an attempt to re-create Nightingale's
coxcomb graph with ggplot2,
where I'd like the months to be labeled as "Mar 1885", "Apr 1885", using
a date format
of "%b %Y" applied to label the dates, or really anything other than
2017 Aug 28
0
"Improvement with the R code"
Ok, I assumed you wanted to compute a matrix M for all states such that
M[i][j]= transition from state i to state j / number of transition from
state i
but from what you just answered it looks like you want to compute a matrix
M for a set of states S such that:
M[S_i][S_j]= transition from state S_i to state S_j / number of transition
from state S_i where S_i is in the set S
?
2017-08-28
2010 Jul 19
2
Grouping and stacking bar plot for categorical variables
Hi all,
I have a series of cateogiral variables that look just like this:
welfare=sample(c("less", "same", "more"), 1000, replace=TRUE)
education=sample(c("less", "same", "more"), 1000, replace=TRUE)
defence=sample(c("less", "same", "more"), 1000, replace=TRUE)
egp=sample(c("salariat",
2007 Oct 19
0
calculating power of log rank test
hie
Im trying to calculate the power of the logrank test for different values of rho .I was just wandering whether the following programme would do it. any suggestions are welcome
s=50
number=1
count1=0;count2=0;count3=0;count4=0;count5=0;count6=0;count7=0;count7=0;
count8=0;count9=0
while(s!=0){
n=20
n1=n/2
2017 Aug 28
0
"Improvement with the R code"
Chuck (Is it fine to call you Chuck?) has far more R jutsu than I do
obviously.
I don't know much about pmin and factor but it might worth looking into if
you want to manipulate states by names (I assume this is why one might want
to use it?)
generate_transition_matrix <- function(data, states)
prop.table(table(head(data, -1), tail(data, -1)), 1)[states,]
2010 Apr 14
3
Problem with recode -Error in parse(text = range[[1]][1]) : unexpected end of input in " c(0"
Dear colleagues,
in the help archive there was a previous person who encountered a
problem with the "recode" command in the car library. I'm not sure if
that was solved, there was no posting to that effect, but I'm having
the same problem.
I'm trying to recode a numeric variable with values from 0-100 into a
binary variable with values (0,1).
The following command:
2008 Feb 14
0
help in simplyfiying programme
my program given below can some one make it presentable. I trying to simulate survival data and calculate the power. I think i could have done better.
s=10
number=0
count1=0;count2=0;count3=0;count4=0;count5=0;count6=0;count7=0;count8=0;
count9=0;
count11=0;count22=0;count33=0;count44=0;count55=0;count66=0;count77=0;
count88=0;count99=0;
while(s!=0){
n=100
n1=n/2
n2=n/4
2010 May 27
2
help calculating variable based on factor level of another
Dear colleagues,
I want to calculate the value of x2 based on the value of x1. x1 is a
factor with three separate levels. I want to make sure that missing
values remain as NA in X2, but non-missing values take on a value of
either 0 or 1 dependending on the value in x1.
This is the code I'm working with...Can any one help?
I've seen some other requests on a topic like this, but not
2009 Jan 03
2
R Stacked Histogram
I've seen this asked, but never fully answered.
Is it possible to plot stacked histograms in R?
I have four data sets that I would like to show combined vertically in histogram format.
Is this possible?
Thank you for any feedback you can provide.
P.S. I know I can show the four sets side by side, but I want to combine them, but still uniquely identify each. Thanks again.