Displaying 20 results from an estimated 8000 matches similar to: "replication time series using permutations of the each "y" values"
2011 Aug 01
2
GLM & ANOVA
Hola a todos,
Estoy trabajando con modelos lineales generalizados (GLM), en
particular con las funciones glm y anova.glm de R. Tengo una pregunta
que es más bien técnica en el sentido estadístico (y un poco Off Topic
y probablemente un tanto naive). No tengo claro si es correcto decir
análisis de varianza o de devianza al utilizar GLMs, veo que en el
help de  anova.glm dice análisis de
2007 Jul 16
1
question about ar1 time series
Hello everybody,
I recently wrote a "program" that to generate AR1 time series, here the code:
#By Jomopo. Junio-2007, Leioa, Vizcaya
#This program to create the AR1 syntetic series (one by one)
#Where the mean is zero, but the variance of the serie AR1 and
#the coef. of AR1 are be changed. If var serie AR1 = 1 then is standarized!
#Final version for AR1 time series program
#Mon Jul
2008 Apr 16
1
save a graph in horizontal way (using pdf())
Hello everybody,
I want to save a graphic using the "pdf environment",  everything in order,
but I can not
to save the graph in "horizontal" way. I have read the manual (to plot,
par),  the FAQ, google, but nothing I found that can help me. Anyone can say
me a hint?
Thanks a lot,
--
Josue
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2008 Aug 01
1
Solving Yis[i] = a*cos((2*pi/T)*(times[i] - Tau)) + ...
Hi everybody,
I am reading the Lomb paper (Lomb, 1976) and I found an interesting
equation, and I wish to resolve it using R. I am wondering if anybody has a
hint. The equation is:
Yis[i] = a*cos((2*pi/T)*(Times[i] - Tau))  + b*sin((2*pi/T)*(Times[i] -
Tau)) ... (1)
Where T and Tau are constants.  I know the "Times" and "Tis" values (in fact
these values come from a Time
2009 Mar 31
1
Lomb periodograms
Hi,
I have recently used the CTS package in order to use the Lomb-Scargle periodogram (spec.ls) function. I have noticed an issue that I hoped you may be able to explain. If a regularly spaced time series has two points removed, one at either side of a single data point (thus making an irregularly spaced time series), a spectrum with a very large peak at the highest frequencies is produced. An
2009 Oct 23
2
Wavelets
Hi all,
I am trying to do wavelets and I got  an error message saying "The
length of data is not a power of 2"
Is there a way of handing  that? or should the data length be  exactly
the power of  2?
I am using   R version 2.9.2 (2009-08-24)
The is  library(wavethresh).
wds <- wd(ds$v,filter.number=1)
Thanks
2010 Jun 19
7
urgente
Hola, quisiera que me dijeran como puedo mandarle unos datos al R, de una aplicación en java. 
"La educación es lo que queda cuando uno se olvida de todo lo que aprendió en la escuela." 
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2014 Apr 19
1
lag() not returning a time series object
Dear all,
Before I file this as a bug, I wanted to check if I didn't miss something.
The help page of lag() says that the function returns a time series object.
It actually does return something that looks like a ts object (the
attribute tsp is set). But when using a vector, the class "ts" is not added
to the result:
> avec <- 1:10
> lag(avec)
 [1]  1  2  3  4  5  6  7  8 
2014 Oct 15
3
Ayuda prueba de significancia funcion nls()
Hola, estoy haciendo un estudio de la desaceleración de la mortalidad y
tengo dudas con la función nls(), adjunto un archivo donde he redactado mi
inquietud.
saludos cordiales
Boris Polanco
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2009 Oct 12
2
Error: cannot allocate vector of size 1.2 Gb
Dear List,
today I turn to you with a next problem. I'm trying to compare species
richness between various datasets (locations) using species accumulation
curves (Chapter 4, page 54 in Tree diversity
analysis<http://www.worldagroforestry.org/treesandmarkets/tree_diversity_analysis.asp>by
Kindt & Coe). To accomplish this I'm using package
BiodiversityR. My data is comprised of
2005 May 25
2
Placing A Legend in Titlle of a Plot
Hello,
I am trying to place a legend in the title area of a plot.  I can not 
seem to find a way to get legend() to do this.  Nor can I use the 
title() function.  Does anyone know a way to do this?  I would greatly 
appreciate any advice.
Thanks
Josue Samayoa
Center for Biomolecular Science & Engineering
School of Engineering
Division of Physical & Biological Sciences
University of
2010 Jul 01
2
calculation on series with different time-steps
Hello,
I have two series, one with stream stage measurements every 5 minutes, and
the other with barometric pressure measurements every hour.  I want to
subtract each barometric pressure measurement from the 12 stage measurements
closest in time to it (6 stage measurements on either side of the hour).
I want to do something like the following, but I don't know the syntax.
"If the
2013 Dec 24
1
OT - Merry Christmas and a Happy and Prosperous 2014
Dear Ladies and Gentlemen how are you?
I would like to wish everyone and all their families, may God continue to
bless and always illuminating your steps, that this Christmas the joy of
our Lord Jesus invade your home and participate in their family on this
Christmas.
May God bless you always!
Merry Christmas and a Happy and Prosperous 2014.
With Best Regards!
Josue
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2010 Dec 21
2
Warning message when items of Hmisc are masked by loading a package.
I've noticed that I get a warning message every time a package masks
some functions from Hmisc. The warning message says :
Warning message:
In identical(get(., i), get(., lib.pos)) : ignoring non-pairlist attributes
This happens with eg:
library(plyr)
library(xtable)
I think I've seen this passing by before, but I'm not sure any more.
Just thought I'd mention it.
Cheers
Joris
2010 Jun 18
3
Non-procedural access to columns of a matrix
Hi,
I would like to have an index for a column in a matrix encoded in a
cell of the same matrix.
For example:
x = matrix(c(11,12,13,1,
21,22,23,3,
31,32,33,2),byrow=T,ncol=4)
In this case, column 4 is the index. I then access the column
specified in the index by:
> for (i in 1:3) print(x[i,x[i,4]])
[1] 11
[1] 23
[1] 32
>
> for (i in 1:3) {x[i,x[i,4]] <- x[i,x[i,4]] + 5}
> x
    
2017 Mar 28
2
`[` not recognized as a primitive in certain cases.
?typeof? is your friend here:
> typeof(`[`)
[1] "special"
> typeof(mc[[1]])
[1] "symbol"
> typeof(mc2[[1]])
[1] "special"
so mc[[1]] is a symbol, and thus not a primitive.
- Lukas
> On 28 Mar 2017, at 14:46, Michael Lawrence <lawrence.michael at gene.com> wrote:
> 
> There is a difference between the symbol and the function (primitive
>
2010 Jun 18
2
Extract estimates from each dataset: MI package
Dear All,
I am currently using the MI package (Su, Gelman, Hill and Yajima) to make
multiple Imputations of my dataset with missing values. After fitting a
model, I can use display(model) to visualize the pooled estimates as well as
estimates of each imputed dataset. I can visualize these also by typing
print(model).
However I would like to know how I can extract estimates of single imputed
2018 Jan 31
3
Best practices in developing package: From a single file
On 31/01/2018 6:33 AM, Joris Meys wrote:
> 3. given your criticism, I'd like your opinion on where I can improve 
> the documentation of https://github.com/CenterForStatistics-UGent/pim. 
> I'm currently busy updating the help files for a next release on CRAN, 
> so your input is more than welcome.
After this invitation I sent some private comments to Joris.  I would 
say his
2016 Sep 06
2
The use of match.fun
Dear gurus,
I was utterly surprised to learn that one of my examples illustrating the
need of match.fun() doesn't give me the expected result.
center <- function(x,FUN) FUN(x)
center(1:10, mean)
mean <- 4
center(1:10, mean)
Used to give me the error message "could not find function FUN". Now it
just works, even though I didn't expect it to. I believe this is at least
2010 Jun 24
2
count data with a specific range
I would like to prepare the data for barplot. But I only have the data frame
now.
x1=rnorm(10,mean=2)
x2=rnorm(20,mean=-1)
x3=rnorm(15,mean=3)
data=data.frame(x1,x2,x3)
If there a way to put data within a specific range? The expected result is
as follows:
 range       x1                  x2                    x3
-10-0        2                      5                     1  (# points in
this