similar to: Labels for matplot x axis

Hi, I’m new to R (just installed today) and I’m trying to figure out how to do stratified randomisation using it. My google search expedition has lead me to believe that blockrand package will most probably be the answer to it. I’ve played around with blockrand for awhile and tried the sample code: library(blockrand) ##stratified by sex male <- blockrand(n=100,

I'm wondering if anyone knows of a way to capture system messages, for instance when I do the following: > system("../DBScripts/getEODData.sh") .//LSE_20091230.txt: 154.80 kB 207.24 kB/s ./Fundamentals//LSE.txt: 420.58 kB 301.47 kB/s ./Fundamentals//MLSE.txt: 3.42 kB 16.20 kB/s

When I run the following code in a loop I get an error after about 125 times saying too many open files... if(inherits(atmpt, "try-error")){ output <- paste(yahooSymbol,"\n",sep="") write(output, file = "data", append = TRUE, sep = "") } else { I've tried various things to close the file after write opens it, and

Consider the following.... > fileLines V1 V2 V3 V4 V5 V6 V7 V8 1 AB 20091224 156.0 156.0 154.00 154.00 55 1198 2 AB.C 20091224 156.0 156.0 156.00 156.00 0 0 3 ABF10 20091224 156.0 156.0 156.00 156.00 55 444 4 ABH10 20091224 156.0 156.0 156.00 156.00 0 749 5 ABH11 20091224 157.2 157.2 157.20 157.20 0 0 6 ABH12

Hello, All: ????? Roughly a decade ago, I added "matplot.Date" and "matplot.POSIXct" to the "fda" package, so we could get reasonable labeling of the horizontal axis when "x" was class "Date" or "POSIXct".? I also added a local version of "matplot.default" that just changes the defaults for "xlab" and

> > Maybe I'm missing something really obvious here, but I was unable to > > create a matrix out of POSIXct object(s). > > Perhaps that deserves a separate discussion...? > Can you provide an example? ------ #date and time objects x = Sys.Date () + 1:16 y = as.POSIXct (x) #matrices str (matrix (x, 4, 4) ) str (matrix (y, 4, 4) ) ------ Creating a matrix from a Date

>>>>> Spencer Graves >>>>> on Mon, 27 Jan 2020 23:02:28 -0600 writes: > ????? Thanks for the reply. > On 2020-01-27 19:56, Abby Spurdle wrote: >> Maybe I'm missing something really obvious here, but I was unable to >> create a matrix out of POSIXct object(s). >> Perhaps that deserves a separate discussion...? yes,

On 2020-01-28 05:13, Martin Maechler wrote: >>>>>> Spencer Graves >>>>>> on Mon, 27 Jan 2020 23:02:28 -0600 writes: <snip> > > Still, as Abby mentioned, turning a simple function into the > default method of an S3 generic is easy to do, but comes with a > bit of cost, not just S3 dispatch which typically is negligable in > graphics,

So I've got a 154 column wide xts time series object and I want to plot the 154 series on a single plot and have the added benefit of the time series dates on the x axis. Any suggestions for plotting functions, maplot works but does not give dates on the axis and I can't seem to get plot to give me more than one series. Nick [[alternative HTML version deleted]]

I have the following code fileList <-list.files(path = ".", pattern = "[^a-z].txt$", all.files = FALSE, full.names = FALSE, recursive = FALSE, ignore.case = FALSE) for (x in 1:length(fileList)){ fileLines <- data.frame(read.table(fileList[x])) print(string) } the lines of the file all have the following format... AB,20091224,156,156,154,154,55,1198 Can I access

Hi all, I've got an xts time series of stock symbols and closing prices. > head(x) symbol close 2010-01-04 "AFB" "13.46" 2010-01-04 "AKP" "12.80" 2010-01-04 "APX" " 8.78" 2010-01-04 "AYN" "13.15" 2010-01-04 "BAF" "13.50" 2010-01-04 "BBF" "12.86" >

I am working on a new package, one in which the user needs to specify the role that different variables play in the analysis. Where I'm stumped is the best way to have users specify those roles. Approach #1: Separate formula for each special component First I thought to have users specify each formula separately, like: new.function(formula=y~X1+X2+X3, weights=~w,

Hi list, I know that points involving NAs are not plotted in 'matplot', but when I plot them as lines, I still want the lines to connect all the points (i.e. not broken where there are NAs).? Please see the example below.? How can I achieve this in 'matplot'?? If I can't, any good alternatives so I don't have to use 'plot' + 'lines' and loop through all the

Hello R users -- I am using matplot to prepare graphs and cannot find a way to use (for example) box(lwd=3) within the matplot command and instead have been setting the box line width after drawing the graph, by using box(lwd = 3). Looking over the ?par options and the matplot() help I do not see a way to set box width within matplot. Is there such an option? Thanks for suggestions,

Hi, Matplot works with x being Date class but not POSIXt. Here is the example with R version 2.5.0 Under development (unstable) (2006-12-06 r40129) Example: x <- Sys.Date() - c(1:10) y <- cbind(1:10, 10:1) class(x) ## [1] "Date" matplot(x, y) x <- strptime(as.character(x), format="%Y-%m-%d") ## [1] "POSIXt" "POSIXlt" matplot(x, y) Error in

Hi, I apologise in advance for the na?ve question. I have large matrices that I want to plot. I currently use color2D.matplot. However, these matrices contain many values of no interest (i.e. where there is no data, the figure -999 is automatically displayed). Is there any way of removing these from the matrices to be plotted by matplot? An obvious possibility is setting them all to 0, but that

I am using color2D.matplot to plot a matrix about 400 by 200. The values in the matrix are 0:5 and NA. The resulting plot is not color, but shaded b/w. I tried to figure out how to add colors, I would like something like c(blue, green, red, cyan, green) #example motifx <- matrix(NA, nrow=100,ncol=20) motifx[,1:5] <- 1 motifx[,6:10] <- 2 motifx[,11:15] <- 3 motifx[,15:19] <- 4

Hi, I finally came up with a nice colored matrixplot, using the color2D.matplot function of the plotrix package. But I can't assign xtics and ytics to this plot. I made sure that the matrix has correct colnames() and rownames(). Here's what I do: a=matrix(1:16, 4, 4) colnames(a) <- c("X1", "X2", "X3", X4) rownames(a) <- c("Y1",

n <- 63 a <- 1:n x <- a-1 y <- outer(x,a) matplot(x,y,type='l') Warning message: In matplot(x, y, type = "l") : default 'pch' is smaller than number of columns and hence recycled Why is it complaining if I specifically ask for type="l", so no pch involved? Annoyance or feature? The fix (if needed) is simple. In the matplot code change: if

????? Thanks for the reply. On 2020-01-27 19:56, Abby Spurdle wrote: > Maybe I'm missing something really obvious here, but I was unable to > create a matrix out of POSIXct object(s). > Perhaps that deserves a separate discussion...? ????? Can you provide an example? ????? The standard matplot application that concerns me is with matplot(x, y, ...) where x has class Date or