similar to: Garch in the mean

Hi, Can we attach a more descriptive "label" (I may use the wrong terminology, which would explain why I found nothing on the FAQ) to variable names, and later have an easy way to switch to these labels in plots? I fear this is not possible and one must enter this by hand as ylab and xlab when making plots. Thanks in advance, Denis Chabot

hello, i was trying to predict values for a garch, so i did: predict(fitgarch,n.ahead = 20) but this doesn't work. Someone can tell me how to get the 20 values ahead of a garch model. thanks in advance _________________________________________________________________ O Windows Live ajuda-o a manter-se em contacto com todos os seus amigos, num só local.

Dear all- Package /fGarch/ version 2100.78 in R version 2.8.1 (2008-12-22) running on linux 2.6.22.9-91.fc7 In trying to fit garch models in above environment. I am getting "reasonable" fitted coefficients, but the fitObject@fitted are all the same. This is true even for the help page example: library(fGarch) R> X.timeSeries = as.timeSeries(msft.dat) R> head( +

? stato filtrato un testo allegato il cui set di caratteri non era indicato... Nome: non disponibile URL: <https://stat.ethz.ch/pipermail/r-help/attachments/20101020/415e917c/attachment.pl>

Dear R users, I hope this email finds you well, My name is Mariam and I am currently using R in my thesis project. I is about modeling investors' sentiment. My R skills are very modest and I am trying to solve a Garch in mean equation using the "rgarch" package. The main issue I am facing is with the mean equation, and I need a code for it or a lead on how to edit already existing

I have been following the discussions on 'Reasons not to answer very basic questions in a straightforward way' with interest as someone who is also new to R and has had similar experiences. As such it with sadness that I note that most seem to agree with the present approach to the responses to basic questions. I must thank those respondants to my own questions who have been helpful, but

Dear All, Sorry to bother. I'd like to estimate GARCH-M( GARCH IN THE MEAN) model. And find that a package called rgarch could help. But I always can't instal rgarch package successfully. I posted my problems and got some suggestions but still failed. Does any one knows other method that could do GARCH-M model? I appreciate your time and help! Cheers, Xi -- View this message in context:

I wonder if someone could explain how the following R idiom works (it's used in glm.fit). start <- coef start[fit$pivot] <- coef coef is a vector of coefficients, set by .Fortran("dqrls", ...). fit$pivot is a vector of integer indexes (indicating how dqrls permuted the columns of x). If coef has n elements, fit$pivot is a permutation of seq(1,5). start[fit$pivot]

I am trying to apply a permuation-based MANOVA (Anderson 2001) to a set of morphological data from three ecomorphs of fish reared under two different conditions and measured at two points during ontogeny. I will supply a distance matrix based on Procrustes distances calculated outside of vegan. I have not found an example of a design such as this for adonis. However, I have designed my factors

Hi I am using the ugarchspec function from the rgarch package to fit a mean variance model jointly. Following is the code I'm using: > spec = ugarchspec(variance.model = list(model="eGARCH", garchOrder=c(1,1)), mean.model = list(armaOrder=c(1,1))) On doing this, I get the following error: Error in ugarchspec(variance.model = list(model = "eGARCH", garchOrder = c(1,

I am sorry to ask this group but the maintainer of this package did not leave an email address. Has anyone used or is using the 'rugarch' package with time-series data (ts)? I try to fit a GARCH model to my data using the following: > gf <- ugarchfit(data=l[["MEN"]]$series, spec=spec) and I get: Error in .extractdata(data) : rgarch-->error: class of

Yes, you're right. In fact, it's just an adaptation of a matlab command and the author advises using N^4 replications that's why it's the default in the function. The bistochastic matrix is not my subject of interest, but I need it to perform some random tranformation of a vector of incomes. Florent Bresson ----- Message d'origine ---- De : Richard M. Heiberger <rmh at

Thanks, I tried someting like this, but computation takes times for large matrices btransf <- function(y,X=length(y)^4) { N <- length(y) bm <- matrix(rep(1/N,N^2),N,N) for(j in 1:X){ coord <- sample(1:N,4,replace=T) d <- runif(1,0,min(bm[coord[1],coord[2]],bm[coord[3],coord[4]]))

CentOS Errata and Bugfix Advisory 2013:0881 Upstream details at : https://rhn.redhat.com/errata/RHBA-2013-0881.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: 60a09c375423f65a3d62d65a7b2590991095aa89f655f21eee07f4c4665fe91d nmap-5.51-3.el6.i686.rpm 24eb30224cb24a84ef007ab57b438b89ccc006c6bf657a598d3ed19dabf08c11

Send CentOS-announce mailing list submissions to centos-announce at centos.org To subscribe or unsubscribe via the World Wide Web, visit http://lists.centos.org/mailman/listinfo/centos-announce or, via email, send a message with subject or body 'help' to centos-announce-request at centos.org You can reach the person managing the list at centos-announce-owner at centos.org When