Displaying 20 results from an estimated 10000 matches similar to: "Re : help to replace variable value"
2010 May 26
1
Factor to Numeric
Dear All,
I have a data frame with State and 12 Months as column. I want to convert
all the 12 month column from factor to numeric.
any help will be greatly appreciated.
> str(data)
'data.frame': 33 obs. of 9 variables:
$ State : Factor w/ 33 levels "Andaman and Nicobar Islands",..: 1 2 3 4
5 6 7 8 9 10 ...
$ April : Factor w/ 21 levels
2010 Mar 11
3
Help function "?" in R 2.10.1
Hello everyone,
I have versions 2.7.2 and 2.10.1 installed on a machine that has no
access to internet.
In 2.7.2 I can use ? to get help on functions, which in 2.10.1 that
does not work, all I see is "starting httpd help server...done" and
then nothing.
Have I downloaded 2.10.1 incorrectly (=forgot to tick some box for
local help file repository) or is the internet help now the
2010 May 18
3
"Re: Change class factor to numeric"
sorry I had a mistake sending my question without a subject. I do resend again. Please excuse me.
> Hello
> I have a data array with soil variables (caperf), in which the variable "clay" is factor (as I see entering str(caperf)) . I need to do a regression model, so I need to have arcilla (=clay) as a numeric variable. For that I have entered
>
>
2010 May 20
2
Overlap of leaf labels
Hi,
I have tried looking at the archives but havent found any answer that works
till now (Sorry if i have missed anything)
I am a newbie to R and i am trying to carry out hierarchical clustering
using hclust -> as.dendrogram and then plotting the results as a dendrogram
using the plot function plot(object).
My question is :
In the function "plot", can one decrease the leaf label
2011 May 04
1
Str info. Thanks for helping
It looks from str(SA) that Response IPS1 is a data.frame of class "anova", which probably cannot be coerced to vector.
Maybe you can use unlist() instead of as.vector()
Or something like
SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even maybe with unlist()
Without a better REPRODUCIBLE example, I cannot tell more (maybe some others
2010 May 19
3
save in for loop
Dear users,
My problem concerns save() within a for loop.
Here is my code:
for (i in 1:4) {
temp <- data.frame(a=(i+1):(i+10), b=LETTERS[(i+1):(i+10)])
filename <- paste("file", i, sep="")
assign(filename, temp)
save(filename, file=paste(filename, ".rda", sep=""))
}
As you can see, save() doesn't work as I would like: (1) the object
2011 Feb 28
3
Problems using unique function and !duplicated
Hi, I am trying to simultaneously remove duplicate variables from two or more
variables in a small R data.frame. I am trying to reproduce the SAS
statements from a Proc Sort with Nodupkey for those familiar with SAS.
Here's my example data :
test <- read.csv("test.csv", sep=",", as.is=TRUE)
> test
date var1 var2 num1 num2
1 28/01/11 a 1 213 71
2
2010 Nov 01
2
number of items to replace is not a multiple of replacement length
Hey all,
I am writing a function in which I will have a matrix of 4 columns and a
variable amount of rows.
The first to columns will always contain be of the Character type, the third
and fourth columns
can be a variation of data types, usually characters and integers, but
sometimes lists or matrices.
At one point the code makes, for each row, a copy of that row, then it makes
some adjustments
2010 Dec 08
5
Summing up Non-numeric column
Dear All
If I have the following dataset
V1 V2
x y
y x
z b
a c
b j
d l
c o
How do I use R command to get the total number of different letter in column
"V1"
column "V1" has 7 different letters.
Thank you
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2010 Dec 13
7
descriptive statistics
Hi. In a data set I have a variable that takes values from 1 to 14. For each
subgroup of values of this variable, I would like to obtain some descriptive
statistics of other variables present in the data set. I've been trying with
a "for" loop but I couldn't get nothing. Could you please suggest me some
lines?
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2011 Apr 20
2
user input
Dear users,
I have looked on different sources and found different functions to
prompt the user to provide input. However, I couldn't find one that does
exactly what I'm looking for.
select.list() and menu() are nice because a graphic window appears to
prompt the user. However, the user can only choose from a predefined
list of choices. readline() and scan() are more free in the
2010 May 20
6
writing function
Dear group,
I am trying to write functions, but as a beginner, everything is not so
obvious.
Let's say I want the results in a list of elemts like this :
tot1, tot2, etc
Here is a function:
toto <-
function(x,y)
{
for(i in x:y){
paste(c("tot",i),collapse="")<-(i*2)
}
}
If I type this :
>toto(1,5)
I get this message error:
Error in paste(c("tot",
2010 May 20
1
use object within rda file in for loop
Dear users,
I would like to process all the lists from all *.rda files that I have
in one folder.
Up to now, I can load all the *.rda files without any problem.
The problem is when I want to access the list saved within each *.rda
file (only one list per rda file).
Here is my code:
fpath <- "D:/R"
listnames <- list.files(path=fpath, pattern=glob2rx("*.rda"),
2010 Mar 31
1
position of mismatches in all.equal()?
Dear R users,
I would like to compare two dataframes, actually their categorical
variables (as factors) only (there are 12, from column 1 to 12).
The reason I do that is that I got 2 datasets from two different methods
and I would like to be sure that each method used the same data (3D
images) to extract 2 different sets of 3D parameters. Is it clear so far?
So I thought about using
2010 Aug 17
2
dims error
Greetings,
I am a very novice user with R, and in the course of running a linking procedure :
P.old<- function (a, c, b, xi){
#a contains a parameters
#c contains c parameters
#b contains b parameters
#xi is a one column vector containing quadrature points for xi(=theta-gamma)for one item
tmp <- a*(xi-b)
2010 Nov 17
2
Extract elements that starts with...
Hi
I got an table that contains this colum and i wonder if there is any nice
way to extract all rows that contains all dose that start with A02, so all
the rows that have A020 and A021 etc etc...
| A010 |
| A010 |
| A010 |
| A020 |
| A020 |
| A020 |
| A020 |
| A020 |
| A021 |
| A021 |
Thx for your help
//Joel
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2010 Mar 07
1
Some hints for the R beginner
There is now a document called "Some hints
for the R beginner" whose purpose is to get
people up and running with R as quickly as
possible.
Direct access to it is:
http://www.burns-stat.com/pages/Tutor/hints_R_begin.html
JRR Tolkien wrote a story (sans hobbits) called
'Leaf by Niggle' that has always resonated
with me. I offer you an imperfect, incomplete
tree (but my roof is
2010 Nov 17
1
Give me all operator
Hello is there in R any operator that give you all the data of a matrix
for example in matlab
x(2,3) returns the 2ndth row and 3rdth column
x(2,:) returns all the columns of the 2nd row.
In R now I would like to print all the
CRagent[[i]][2]
CRagent[[:]][2] doesnot work of course. Other option is to make a loop with an index i that spans from 1:last element of CRagent[[]] but this is not
2010 May 21
1
select elements in a list
Dear group,
Here is a list :
l <-
list("100415", "100416", "100419", "100420", "100421", "100422",
"100423", "100426", "100427", "100428", "100429", "100430",
"100503", "100504", "100505", "100506", "100507",
2010 Jun 17
1
Column name defined by function variable
Hi all,
probably a simple problem for you but I am stuck.
This simple function adds columns (with differing length) to data frames:
add.col <- function(df, new.col) {
n.row <- dim(df)[1]
length(new.col) <- n.row
cbind(df, new.col)
}
Now I would like to extend that method. A new parameter 'name' shouild
allow people to pass in a name for that new column. Is that possible
and