Displaying 20 results from an estimated 1000 matches similar to: "(no subject)"
2010 May 11
1
merge two data frames
Dear group,
I have these 2 following data frame:
allcon <-
structure(list(DESCRIPTION = structure(1:17, .Label = c("COFFEE C Jul/10",
"COPPER May/10", "CORN Jul/10", "CORN May/10", "COTTON NO.2 Jul/10",
"CRUDE OIL miNY May/10", "GOLD Jun/10", "HENRY HUB NATURAL GAS May/10",
"ROBUSTA COFFEE (10)
2010 May 20
6
writing function
Dear group,
I am trying to write functions, but as a beginner, everything is not so
obvious.
Let's say I want the results in a list of elemts like this :
tot1, tot2, etc
Here is a function:
toto <-
function(x,y)
{
for(i in x:y){
paste(c("tot",i),collapse="")<-(i*2)
}
}
If I type this :
>toto(1,5)
I get this message error:
Error in paste(c("tot",
2010 May 11
2
Regex and gsub
Dear group,
Here is my df :
df3 <-
structure(list(DESCRIPTION = c("COPPER May/10", "COTTON NO.2 Jul/10",
"CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10",
"SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10",
"WHEAT Jul/10", "SPCL HIGH GRADE ZINC USD",
2010 May 11
1
merging data frame
Dear group,
I have 3 data frames I would like to merge.
Here they are:
pose16 <-
structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L,
6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10",
"CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10",
"SOYBEANS Jul/10", "SUGAR NO.11
2010 Aug 04
3
merge two data frames
Dear list,
here are my two data frames:
av <-
structure(list(DESCRIPTION = c("COFFEE C Sep/10", "COPPER Sep/10",
"CORN Dec/10", "CRUDE OIL miNY Sep/10", "GOLD Aug/10", "HENRY HUB
NATURAL GAS Sep/10",
"PALLADIUM Sep/10", "SILVER Sep/10", "SOYBEANS Nov/10", "SPCL HIGH
GRADE ZINC USD",
"SUGAR
2010 Apr 23
2
read.csv data frame thousands separator
Dear group,
Here is my df, trades1 :
trades1 <-
structure(list(Instrument.Long.Name = c("CORN", "CORN", "CORN",
"CORN", "CORN", "SOYBEANS", "SOYBEANS", "SOYBEANS", "SOYBEANS",
"SOYBEANS", "SOYBEANS", "STANDARD LEAD USD", "STANDARD LEAD USD",
"SPCL
2010 Apr 30
1
read.csv and blank character in object name of my data.frame
Dear group,
Here is my data frame:
position100415 <-
structure(list(DESCRIPTION = structure(1:9, .Label = c(" SUGAR NO.11 Jul/10
",
" SUGAR NO.11 May/10 ", "CORN May/10 ", "COTTON NO.2 Jul/10 ",
"CRUDE OIL miNY May/10 ", "ROBUSTA COFFEE (10) Jul/10 ", "SILVER May/10 ",
"SOYBEANS Jul/10 ", "WHEAT May/10
2010 Apr 28
1
gsub,regex and replacing
Dear group,
I need to modify some characters in a data frame. I want to use gsub and the
regex functionalities to do this.
Here is the data frame (df):
DESCRIPTION prix quantity
1 CORN Jul/10 -1.5 0
2 CORN May/10 -1082.0 -3
3 ROBUSTA COFFEE (10) Jul/10 11084.0 8
4 SOYBEANS Jul/10 1983.5
2010 Apr 28
3
data frame move columns
Dear group,
Here is my df:
avprix <-
structure(list(DESCRIPTION = c("CORN Jul/10", "CORN May/10",
"ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SPCL HIGH GRADE ZINC USD",
"STANDARD LEAD USD"), prix = c(-1.5, -1082, 11084, 1983.5, -2464,
-118), quantity = c(0, -3, 8, 2, -1, 0), fees = c(-8.64, -30.24,
-26.4, -25.92, -37.5,
2010 May 12
1
data frame subscription
Dear group,
Here is my df :
pose16 <-
structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L,
6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10",
"CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10",
"SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10",
2010 Apr 29
3
convert Factor as numeric
Dear group,
I know this issue has been already covered, and before you reply I must say
I have read the R-FAQ and search the mailing list archive.
I still can't manage to change my factor to numeric as I couldn't find any
clear answer.
Here is my df :
Pose1 <-
structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L,
8L), .Label = c(" SUGAR NO.11 May/10 ", "COTTON
2010 Apr 14
6
sum specific rows in a data frame
I have a data frame called "pose":
DESCRIPTION QUANITY CLOSING.PRICE
1 WHEAT May/10 1 467.75
2 WHEAT May/10 2 467.75
3 WHEAT May/10 1 467.75
4 WHEAT May/10 1 467.75
5 COTTON NO.2 May/10 1 78.13
6 COTTON NO.2 May/10 3 78.13
7 COTTON NO.2 May/10 1 78.13
2010 May 27
1
switch function
Dear group,
Here is my df :
trades <-
structure(list(Trade.Status = c("DEL", "INS", "INS"), Instrument.Long.Name =
c("SUGAR NO.11",
"CORN", "CORN"), Delivery.Prompt.Date = c("Jul/10", "Jul/10",
"Jul/10"), Buy.Sell..Cleared. = c("Sell", "Buy", "Buy"), Volume = c(1L,
2L, 1L),
2010 Jun 01
1
data frame manipulation ddply
Dear group,
Here is my data frame:
futures <-
structure(list(DESCRIPTION = c("CORN Jul/10", "CORN Jul/10",
"CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "LIVE CATTLE Aug/10",
"LIVE CATTLE Aug/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10",
"SUGAR NO.11 Jul/10", "SUGAR NO.11
2010 Jun 01
1
data frame manipulation with zero rows
Dear group,
Here is the kind of data.frame I obtain every day with my function :
futures <-
structure(list(DESCRIPTION = c("CORN Jul/10", "CORN Jul/10",
"CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "LIVE CATTLE Aug/10",
"LIVE CATTLE Aug/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10",
"SUGAR
2010 May 26
1
data frame manipulation change elements meeting criteria
Dear group,
Here is my df :
trade <-
structure(list(Trade.Status = c("DEL", "INS", "INS"), Instrument.Long.Name =
c("SUGAR NO.11",
"CORN", "CORN"), Delivery.Prompt.Date = c("Jul/10", "Jul/10",
"Jul/10"), Buy.Sell..Cleared. = c("Sell", "Buy", "Buy"), Volume = c(1L,
2L,
2010 Apr 23
3
substract start from the end of the vector
Dear group,
Here is my df :
df <-
structure(list(DESCRIPTION = c("PRM HGH GD ALUMINIUM USD 09/07/10 ",
"PRM HGH GD ALUMINIUM USD 09/07/10 ", "PRIMARY NICKEL USD 04/06/10 "
), CREATED.DATE = structure(c(18361, 18361, 18325), class = "Date"),
QUANITY = c(-1L, 1L, 1L), CLOSING.PRICE = c("2,415.90", "2,415.90",
2010 May 21
1
select elements in a list
Dear group,
Here is a list :
l <-
list("100415", "100416", "100419", "100420", "100421", "100422",
"100423", "100426", "100427", "100428", "100429", "100430",
"100503", "100504", "100505", "100506", "100507",
2010 Apr 15
1
sum rows in a data.frame...solution
Found this solution. It is maybe not the most elegant way, but it does the
job.
> a=as.data.frame(substr(lme$DESCRIPTION,1,14))
> colnames(a)=c("DESCRIPTION")
> lme=as.data.frame(c(a,lme[,2:3]))
> lme
DESCRIPTION CLOSING.PRICE POSITION
1 PRIMARY NICKEL 25,755.7100 0
2 PRIMARY NICKEL 25,760.8600 0
3 PRM HGH GD ALU 2,415.9000 0
2010 Apr 27
1
save a data frame in environment
Dear group,
Here is my function :
position<-function(x)
{
pose<-read.csv2((paste(c("LSCPos",x,".csv"),collapse="")),dec=".",sep=",",as
.is=T,h=T,skip=1)[,c(4,8,14,15)]
pose$CREATED.DATE<-as.Date(pose$CREATED.DATE,"%d/%m/%y")
futures<-pose[-grep("USD",pose[,1]),]