similar to: (no subject)

Displaying 20 results from an estimated 1000 matches similar to: "(no subject)"

2010 May 11
1
merge two data frames
Dear group, I have these 2 following data frame: allcon <- structure(list(DESCRIPTION = structure(1:17, .Label = c("COFFEE C Jul/10", "COPPER May/10", "CORN Jul/10", "CORN May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "HENRY HUB NATURAL GAS May/10", "ROBUSTA COFFEE (10)
2010 May 20
6
writing function
Dear group, I am trying to write functions, but as a beginner, everything is not so obvious. Let's say I want the results in a list of elemts like this : tot1, tot2, etc Here is a function: toto <- function(x,y) { for(i in x:y){ paste(c("tot",i),collapse="")<-(i*2) } } If I type this : >toto(1,5) I get this message error: Error in paste(c("tot",
2010 May 11
2
Regex and gsub
Dear group, Here is my df : df3 <- structure(list(DESCRIPTION = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10", "WHEAT Jul/10", "SPCL HIGH GRADE ZINC USD",
2010 May 11
1
merging data frame
Dear group, I have 3 data frames I would like to merge. Here they are: pose16 <- structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11
2010 Aug 04
3
merge two data frames
Dear list, here are my two data frames: av <- structure(list(DESCRIPTION = c("COFFEE C Sep/10", "COPPER Sep/10", "CORN Dec/10", "CRUDE OIL miNY Sep/10", "GOLD Aug/10", "HENRY HUB NATURAL GAS Sep/10", "PALLADIUM Sep/10", "SILVER Sep/10", "SOYBEANS Nov/10", "SPCL HIGH GRADE ZINC USD", "SUGAR
2010 Apr 23
2
read.csv data frame thousands separator
Dear group, Here is my df, trades1 : trades1 <- structure(list(Instrument.Long.Name = c("CORN", "CORN", "CORN", "CORN", "CORN", "SOYBEANS", "SOYBEANS", "SOYBEANS", "SOYBEANS", "SOYBEANS", "SOYBEANS", "STANDARD LEAD USD", "STANDARD LEAD USD", "SPCL
2010 Apr 30
1
read.csv and blank character in object name of my data.frame
Dear group, Here is my data frame: position100415 <- structure(list(DESCRIPTION = structure(1:9, .Label = c(" SUGAR NO.11 Jul/10 ", " SUGAR NO.11 May/10 ", "CORN May/10 ", "COTTON NO.2 Jul/10 ", "CRUDE OIL miNY May/10 ", "ROBUSTA COFFEE (10) Jul/10 ", "SILVER May/10 ", "SOYBEANS Jul/10 ", "WHEAT May/10
2010 Apr 28
1
gsub,regex and replacing
Dear group, I need to modify some characters in a data frame. I want to use gsub and the regex functionalities to do this. Here is the data frame (df): DESCRIPTION prix quantity 1 CORN Jul/10 -1.5 0 2 CORN May/10 -1082.0 -3 3 ROBUSTA COFFEE (10) Jul/10 11084.0 8 4 SOYBEANS Jul/10 1983.5
2010 Apr 28
3
data frame move columns
Dear group, Here is my df: avprix <- structure(list(DESCRIPTION = c("CORN Jul/10", "CORN May/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SPCL HIGH GRADE ZINC USD", "STANDARD LEAD USD"), prix = c(-1.5, -1082, 11084, 1983.5, -2464, -118), quantity = c(0, -3, 8, 2, -1, 0), fees = c(-8.64, -30.24, -26.4, -25.92, -37.5,
2010 May 12
1
data frame subscription
Dear group, Here is my df : pose16 <- structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10",
2010 Apr 29
3
convert Factor as numeric
Dear group, I know this issue has been already covered, and before you reply I must say I have read the R-FAQ and search the mailing list archive. I still can't manage to change my factor to numeric as I couldn't find any clear answer. Here is my df : Pose1 <- structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L, 8L), .Label = c(" SUGAR NO.11 May/10 ", "COTTON
2010 Apr 14
6
sum specific rows in a data frame
I have a data frame called "pose": DESCRIPTION QUANITY CLOSING.PRICE 1 WHEAT May/10 1 467.75 2 WHEAT May/10 2 467.75 3 WHEAT May/10 1 467.75 4 WHEAT May/10 1 467.75 5 COTTON NO.2 May/10 1 78.13 6 COTTON NO.2 May/10 3 78.13 7 COTTON NO.2 May/10 1 78.13
2010 May 27
1
switch function
Dear group, Here is my df : trades <- structure(list(Trade.Status = c("DEL", "INS", "INS"), Instrument.Long.Name = c("SUGAR NO.11", "CORN", "CORN"), Delivery.Prompt.Date = c("Jul/10", "Jul/10", "Jul/10"), Buy.Sell..Cleared. = c("Sell", "Buy", "Buy"), Volume = c(1L, 2L, 1L),
2010 Jun 01
1
data frame manipulation ddply
Dear group, Here is my data frame: futures <- structure(list(DESCRIPTION = c("CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "LIVE CATTLE Aug/10", "LIVE CATTLE Aug/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11
2010 Jun 01
1
data frame manipulation with zero rows
Dear group, Here is the kind of data.frame I obtain every day with my function : futures <- structure(list(DESCRIPTION = c("CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "LIVE CATTLE Aug/10", "LIVE CATTLE Aug/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10", "SUGAR
2010 May 26
1
data frame manipulation change elements meeting criteria
Dear group, Here is my df : trade <- structure(list(Trade.Status = c("DEL", "INS", "INS"), Instrument.Long.Name = c("SUGAR NO.11", "CORN", "CORN"), Delivery.Prompt.Date = c("Jul/10", "Jul/10", "Jul/10"), Buy.Sell..Cleared. = c("Sell", "Buy", "Buy"), Volume = c(1L, 2L,
2010 Apr 23
3
substract start from the end of the vector
Dear group, Here is my df : df <- structure(list(DESCRIPTION = c("PRM HGH GD ALUMINIUM USD 09/07/10 ", "PRM HGH GD ALUMINIUM USD 09/07/10 ", "PRIMARY NICKEL USD 04/06/10 " ), CREATED.DATE = structure(c(18361, 18361, 18325), class = "Date"), QUANITY = c(-1L, 1L, 1L), CLOSING.PRICE = c("2,415.90", "2,415.90",
2010 May 21
1
select elements in a list
Dear group, Here is a list : l <- list("100415", "100416", "100419", "100420", "100421", "100422", "100423", "100426", "100427", "100428", "100429", "100430", "100503", "100504", "100505", "100506", "100507",
2010 Apr 15
1
sum rows in a data.frame...solution
Found this solution. It is maybe not the most elegant way, but it does the job. > a=as.data.frame(substr(lme$DESCRIPTION,1,14)) > colnames(a)=c("DESCRIPTION") > lme=as.data.frame(c(a,lme[,2:3])) > lme DESCRIPTION CLOSING.PRICE POSITION 1 PRIMARY NICKEL 25,755.7100 0 2 PRIMARY NICKEL 25,760.8600 0 3 PRM HGH GD ALU 2,415.9000 0
2010 Apr 27
1
save a data frame in environment
Dear group, Here is my function : position<-function(x) { pose<-read.csv2((paste(c("LSCPos",x,".csv"),collapse="")),dec=".",sep=",",as .is=T,h=T,skip=1)[,c(4,8,14,15)] pose$CREATED.DATE<-as.Date(pose$CREATED.DATE,"%d/%m/%y") futures<-pose[-grep("USD",pose[,1]),]