similar to: writing function : can't find an object

Dear group, I have this command line in a function: zz<-merge(transform(merge(value,allcon,all.y=T),SHORTDESCRIPTION=NULL,VALUE= NULL,PL=-VALUE*pl,quantity=NULL),PosB,all.x=T,sort=F) I want to cut it in 2 lines (just for convenient purpose). Here is what I did : zz<-merge(transform(merge(value,allcon,all.y=T),SHORTDESCRIPTION=NULL, +

Dear group, I have these 2 following data frame: allcon <- structure(list(DESCRIPTION = structure(1:17, .Label = c("COFFEE C Jul/10", "COPPER May/10", "CORN Jul/10", "CORN May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "HENRY HUB NATURAL GAS May/10", "ROBUSTA COFFEE (10)

Dear group, Here is my environment : > ls() [1] "l" "PLglobal" "Pos100415" "Pos100416" "Pos100419" "Pos100420" "position" "select" "Trad100415" "Trad100416" "Trad100419" "Trad100420" "trade" "y" With objects : > l [1]

To everyone on the list: do *NOT* attempt to do echo cancellation with signals sampled using different clocks. This will *NOT* work. Just a 0.1% difference between the two sampling rates (it's sometimes worse than that) means that the impulse response drifts by 8 samples every second. There's just no way to efficiently track this. Or at least no way that doesn't involve something 100x

Hi, How can I partitioned an example vector like this > print(myvector) [1] 30.9 60.1 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 into the following pairwise partition: PAIR1 part1 = 30.9 part2 = 60.1 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 PAIR2 part1 = 30.9 60.1 part2 = 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 .... PAIR9 part1 = 30.9

> To everyone on the list: do *NOT* attempt to do echo cancellation with > signals sampled using different clocks. This will *NOT* work. Just a > 0.1% difference between the two sampling rates (it's sometimes worse > than that) means that the impulse response drifts by 8 samples every > second. There's just no way to efficiently track this. Or at least no > way that

Dear group, Here are my objects in my environment: > ls() [1] "Pos100415" "Pos100416" "posA" "pose15" "pose16" "pose16t" "position" "trade" "x" I need to pass the object "Pos100415" to a function. This element is a data.frame, obtained through a function: Pos(x)<-myfun(x)

Dear group, I am trying to write functions, but as a beginner, everything is not so obvious. Let's say I want the results in a list of elemts like this : tot1, tot2, etc Here is a function: toto <- function(x,y) { for(i in x:y){ paste(c("tot",i),collapse="")<-(i*2) } } If I type this : >toto(1,5) I get this message error: Error in paste(c("tot",

I'd like to remove duplicated rows within a matrix, with missing data being treated as wildcards. For example > x <- matrix((1:3), 5, 3) > x[4,2] = NA > x[3,3] = NA > x [,1] [,2] [,3] [1,] 1 3 2 [2,] 2 1 3 [3,] 3 2 NA [4,] 1 NA 2 [5,] 2 1 3 I would like to obtain [,1] [,2] [,3] [1,] 1 3 2 [2,] 2 1 3

Dear group, Here is my function : position<-function(x) { pose<-read.csv2((paste(c("LSCPos",x,".csv"),collapse="")),dec=".",sep=",",as .is=T,h=T,skip=1)[,c(4,8,14,15)] pose$CREATED.DATE<-as.Date(pose$CREATED.DATE,"%d/%m/%y") futures<-pose[-grep("USD",pose[,1]),]

Hello folks With a small delay, the September release of xk-c is there. Have fun! Cheers Sergey ========================================= Akshay S Dinesh (2): typofix tel-sarala key layout Whitelist Indian keyboard layouts. #101532 Baurzhan Muftakhidinov (2): Enable level3 ralt_switch by default in Kazakh (ext) layout. Extend more keys in Kazakh (ext) layout. Jonas