similar to: retrieve path analysis coefficients (package agricolae)

I have used the correlation analysis (pearson) in the agricolae package to analyse my data and got unexpectedly low p-values (therefore making many more highly significant correlations in my data than I had expected). I am wondering if the p-values given should be subtracted from 1 to give the real p-value, because for each variable compared against itself has a p-value of 1 and I thought it

Dear all, W2k, R 2.5.1 I am trying out the AMMI function in the agricolae package, to analyse the dependence of environment for a certain cultivar. The function responds to four basic variables: ENV Environment GEN Genotype REP Replication Y Response My question concerns the 'REP' term. When I normally do an analysis of variance, the replication would refer to repeated observations

Cada vez que intento cargar el paquete "agricolae" me da el siguiente mensaje: Error: package or namespace load failed for 'agricolae' in loadNamespace(i, c(lib.loc, .libPaths()), versionCheck = vI[[i]]): there is no package called 'spData' He intentado todo actualizar los paquetes, volverlos a instalar pero no hay forma. Si sabeis la solución ?? Un saludo. Juan

Dear List, I'm stuck on what seems like a simple indexing problem, I'd be very grateful to anyone willing to help me out. I queried a dataframe which returns a character vector called "plot". I have another dataframe from which I want to subset or select only those rows that match "plot". I've tried subset, and also the "which" command. plot

Hi there, I am doing multiple comparisons for data that is not normally distributed. For this purpose I tried both functions kruskal{agricolae} and kruskalmc{pgirmess}. It confuses me that these functions do not yield the same results although they are doing the same thing, don't they? Can anyone tell my why this happens and which function I can trust? kruskalmc() tells me that there are no

Hola a todos Estoy trabajando con el package agricolae para realizar pruebas de medias y obtengo un error que no entiendo al trabajar las interacciones. Os explico: Poseo un Diseño Completamente al Azar para el arreglo de tratamientos factorial de la forma 2*2*4. El modelo consta de 6228 observaciones, el esquema para el anova es: A= 2 niveles={2,5} B= 4 niveles={F1,F2,F3,F4} C= 2

Dear list, After searching many old posts, I can't find the solution to a simple problem. can someone tell me how to create a character string with multiple backslashes, as in: file_dir <- c("C:\files\data\") I need to create this string and then paste it to many files names for batch processing in another software program. R won't accept the backslash and removes

Dear list, I'm trying to write my first looping function in R. After many hours of searching help files and previous posts, I'm at wits end. Please forgive my programming ignorance...any help is greatly appreciated. I need to sort through a vector (x) and identify the point at which 2 successive values become smaller than the previous value. I've written a "while"

Dear list, I'm trying to download a text file directly from the internet using the RCurl package and the command getURL. Duncan Lang graciously helped me solve the first step in this problem using the following command: ################# txtfile <- getURL('ftp://ftp.wcc.nrcs.usda.gov/data/snow/snow_course/table/history/idaho/13e19.txt', ftp.use.epsv = FALSE) #################

Dear list, I am trying to download a text file from an ftp site using download.file(). I used the following code: url <- "ftp://ftp.wcc.nrcs.usda.gov/data/snow/snow_course/table/history/idaho/13e19.txt" dest <- "c:/test/downloadtest.txt" download.file(url, dest) I get this error message, indicating that R is unable to open the connection: trying URL

Dear list, I would like to plot 2 series of numbers with very different ranges/scales as lines on the same plot. I assumed this is commonly done and easy, but I have not found any help files (e.g. axis() or matplot() that show how. I've searched many old posts to no avail. I'll be very grateful for any suggestions on how this is done. Best, Zack

Hi, Being a R-newbie I am wondering how to calculate a correlation coefficient (preferably with an associated p-value) for data like: > d[,1] [1] 25.5 25.3 25.1 NA 23.3 21.5 23.8 23.2 24.2 22.7 27.6 24.2 ... > d[,2] [1] 0.0 11.1 0.0 NA 0.0 10.1 10.6 9.5 0.0 57.9 0.0 0.0 ... Apparently corr(d) from the boot-library fails with NAs in the data, also cor.test cannot cope with a

Dear list, I've recently installed R on a 64 bit machine with 8 GB of RAM. I set this computer up as a dual-boot system, with windows XP 64 and Ubuntu 7.10. I downloaded the Linux 64 bit version of R and installed it. I'm trying to run rather large Random forest models and was running into severe memory limitations with my old windows 32 bit machines. When I run Random Forest models

Greetings R list, I am stuck on a simple syntax problem. I want to list all files in a directory, excluding files of a certain type. I have tried pattern matching as follows: a <- list.files(data, full.name = TRUE, pattern != ".xml") # exclude all .xml files The warning returns that my syntax is incorrect. I have read the regexpr help files and search old posts to no

Hola Javier, gracias por contestar tan rapido (tarde en la noche) ... olvide decir que, obviamente, he revisado la internet buscando y no encuentro ni siquiera la tabla de analisis de varianza del diseño ... habia revisado el paquete agricolae porque este trae diseños parecidos pero no exactamente lo que necesito. Sigo buscando, muchas gracias, Eric. On 29/04/15 22:57,

Dear all! W2k, R 2.5.1 I am working with an ongoing malting barley variety evaluation within Sweden. The structure is 25 cultivars tested each year at four sites, in field trials with three replicates and 'lattice' structure (the replicates are divided into five sub blocks in a structured way). As we are normally keeping around 15 varieties from each year to the next, and take in 10 new

Dear list, Below I've written a clunky for loop that counts NA's in a row, replacing all with NA if there are more than 3 missing values, or keeping the values if 4 or more are present. This is sample code from a very large dataframe I'm trying to clean up. I know there are many simpler more elegant solutions to this little problem. Would someone be willing to show me how to

Dear R wizards, I have a folder containing 1000 files. For each file, I need to extract the first row of each file, paste it to a new file, then write out that file. Then I need to repeat this operation for each additional row (row 2, then row 3, etc) for 23 rows in each file. I can do this with a for loop (as below). Is there a way to use some of the indexing power of R to get around this

Hello everybody, I use the sweetpotato database included in R package: data(sweetpotato) This dataset contains two variables: yield(continous variable) and virus(factor variable). Due to Levene test is significant I cannot assume homogeneity of variances and I apply Welch test in R instead of one-way ANOVA followed by Tukey posthoc. Nevertheless, the problems come from when I apply posthoc

Genial !! Gracias Carlos, voy a leer la vignette. A todo esto, alguien se acuerda de esas paginas para buscar paquetes y funciones de R ? Se que una estaba en CRAN, pero las otras tambien eran muy buenas porque las use un par de veces, pero no las puedo encontrar en los mails de la lista. Saludos y gracias, eric. On 30/04/15 09:22, Carlos Ortega wrote: > Hola, > >