similar to: question about graph

Hello all, I want to define a vector like w[k+1]=w[k]*a/(b+k) for k=1,...,N-1 without use loop. Is it posible to do in R? Regards khazaei

Hi, I have some vector v1,v2,...,vk, with different lengths. I want to consider these vectors as a matrix with k rows. Can you please guide me how I can do it? Regards khazaei

Hi, At each iteration in my program,I need to generate tree vectors,X1,X2,X3, from exponential distribution with parameters a1,a2,a3. Can you help me please how can I do it such that it take a little time? thank you khazaei

-------------------------------------------------------------------------- Hello all My computer is MacBook and I want to draw a plot in R, for example for x <- c(1,3,6,9,12) y <- c(1.5,2,7,8,15) I use this command plot(x,y). but it dosn't work. Could you please help me? thank you khazaei

Hi, I used the apply()function to compute the maximum of the each row of the matrix, but in my application sometime the matrix has just one row, and the apply() dosen't work. Could you please give me some hints? thank you khazaei

Hi, I have a matrix with m rows and n column and a vector with n elements. I want to divid each rows of the matrix by vector direcly. could you please hint me? Thank you khazaei

Hi, all How can generate a sample from truncated inverse gamma distribution in R? thanks

Hello all how can sample from f(x)~x^(a-1)*ind(0,min(b,-log(u)) in R? where a and b is positive constand and 0<u<1 thanks khazaei

Hi, I am runing R on my mac and I get this error: R(206,0xa01ad720) malloc: *** mmap(size=4000002048) failed (error code=12) *** error: can't allocate region *** set a breakpoint in malloc_error_break to debug R(206,0xa01ad720) malloc: *** mmap(size=4000002048) failed (error code=12) *** error: can't allocate region *** set a breakpoint in malloc_error_break to debug Is there any an

Full_Name: Alessandra Iacobucci Version: 2.5.1 OS: Mac OS X 10.4.11 Submission from: (NULL) (193.48.71.92) Hi, I am making some intensive simulations for the testing of a Population Monte Carlo algorithm. This involves also a study of the CPU times in two different case. What I am trying to measure is the "real" CPU time, the one which is independent on the %CPU. I'm using the

About six months ago there was a reference to a site (in french) that did a spectacular job of demonstrating R's graphical capabilities. My bookmarks were recently wiped and I cannot find this site despite my best googling. Anyone have the address which I have done a miserable job describing? Thanks. Michaell

Hello wizaRds ! I am looking for a french and recent version of "An introduction to R". Does anybody know where i could find on of these. Thanks. -- Romain Fran??ois 25, avenue Guy Moquet 94 400 Vitry sur seine FRANCE _______________________ _______________________ francoisromain at free.fr 01 46 80 65 60 06 18 39 14 69

Dear R helpers, I have following data.frame giving asset class (i.e. bank, corporate, sovereign etc. as there could be number of classes) and rating-wise default frequency. I need to plot graphs for each of these classes i.e. bank, corporate and sovereign where I will be plotting ratings (AAA, AA, etc) on the x-axis and their respective default probabilities on Y-axis. I have tried to write a

A very simple question. With a data frame like this: > n = c(2, 3, 5) > s = c("aa", "bb", "cc") > df = data.frame(n, s) I want df$s[1] or df[1,2], but how can I get rid of the extra line in the output about the factor levels: > df$s[1] [1] aa Levels: aa bb cc Thanks, Gang

Dear all, I am trying to shove a number of cmdscale() results into a single plot (k=1 so I'm trying to get multiple columns in the plot). From ?par I learned that I can/should set new=TRUE in either par() or the plot function itself. However with the following reduced code, I get only a plot with a column of data points with x==2. plot(1,10, xlim=range(0,3), ylim=range(0,10),

I am trying to make a box plot and overlay it with a scatter plot from another data.frame. I was able to successfully create the boxplot, but when i tried using points(x~y...) the dots did not show up. example code aa<-(300,300,300,300,600,600,600,600,900,900,900,900) bb<-(13,12,14,11,56,44,34,75,22.,34,22,98,59,55,56) cc<-(13,12,14,11,56,44,34,75,22.,34,22,98,59,55,56)

Dear R community, I am plotting a histogram and would wish to display another variable of the same dataset in a very narrow heatmap just below the x-axis. Never mind the specifics of my task: How can I draw a second graph/image just below a first graph/image? Thank you! Georg. *************** Georg Ehret JHU Baltimore, MD 21043, USA [[alternative HTML version deleted]]

I'm not sure I'm doing this right. I have two identical machines, A and B.: ----------------------- CONSOLE ----------------------- A ~$: gluster peer probe domU-BB-BB-BB-BB.compute-1.internal Probe successful A ~$: gluster peer status Number of Peers: 1 Hostname: domU-BB-BB-BB-BB.compute-1.internal Uuid: 8d5d9af4-6a92-4d56-b063-c8fc9ac17a45 State: Peer in Cluster (Connected) B ~$:

I don't quite understand the difference between the two methods for performing a chi-squared test on contingency tables: summary(table()) and chisq.test() They may different results. E.g.: aa <- gl(2, 10) bb <- as.factor(c(1,2,2,2,1,2,1,2,2,2,1,2,2,2,1,1,1,2,1,1)) aa <- c(aa, aa) bb <- c(bb, bb) table(aa, bb) summary(table(aa, bb)) chisq.test(aa, bb) Could somebody give me

Hi, I am sure there is an easy way to do it, but I can't find it. I have a data frame that has 15 columns and 7000 rows. The only values inside the data.frame are "aa", "ab", "bb" as you can see an example bellow. 1 2 3 1 aa ab ab 2 ab ab ab 3 aa aa aa 4 bb bb bb What I would like to do, is to generate a vector (or another data.frame) with 7000 rows, and 3