similar to: max number from a list of numbers

Hi everyone, I was working on the Paice-Husk Stemmer, which is a Bite Size Project for Xapian, and I have created a C++ as well as Snowball version of it. I read the algorithm, and picked the rules from here: http://www.comp.lancs.ac.uk/computing/research/stemming/paice/descript.htm The C++ code takes rules as input from a file and generates the stem of given word, whereas the Snowball version

Hi all, I'm feeling a little guilty to ask this question, since I've written a solution using a rather clunky for loop that gets the job done. But I'm convinced there must be a faster (and probably more elegant) way to accomplish what I'm looking to do (perhaps using the "merge" function?). I figured somebody out there might've already figured this out: I have

Hello again, I am simply trying to import a rectangular table of strings. The table's dimensions are 1990 x 2, yet my read.table() command can only find 362 of the rows (and they're not the first 362). I would've taken the time to figure out how to use scan, readLines, or some other tool that can read in character strings, and then parse and input to a table, but that seems like

Last one for you guys: The command: length(gregexpr('cus','hocus pocus')[[1]]) [1] 2 returns the number of times the substring 'cus' appears in 'hocus pocus' (which is two) It's returning the number of **disjoint** matches. So: length(gregexpr('aa','aaa')[[1]]) [1] 1 returns 1. **What I want to do:** I'm looking for a way to count

> On 30 Nov 2014, at 17:51, Abhishek Singh Kushwah <abhishek18kushwah at gmail.com> wrote: > > > Two of the implementation of algorithms has already been rejected > > previously due to licenses both being the implementation of porter > > but our xapian use implementation in snowball which i assume is > > under GPL. The only cases I can think you might be

Dear contributors I have tried this experiment: x<-c() for (i in 1:12){ x[i]<-list(cbind(x1[i],x2[i])) #this is a list of 12 couples of time series I am using to perform a test } # that compares them 2 by 2 # ################# #trace statistic test<-data.frame() cval<-array( , dim=c(2,3,12)) for (i in 2:12){ for (k in 1:2){ for (j in 1:3){ result[k,j,i]<-

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I am looking for a function to flatten a list to a list of only 1 level deep. Very similar to unlist, however I don't want to turn it into a vector because then everything will be casted to character vectors: x <- list(name="Jeroen", age=27, married=FALSE, home=list(country="Netherlands", city="Utrecht")) unlist(x) This function sort of does it: flatlist

Wow.. thanks for the deluge of responses! Aggregate seems like the way to go here. But, suppose that instead of integers in column V2, I actually have dates (and instead of keeping the minimum integer, I want to keep the earliest date): > df =

Hi All, I'm trying to use the "sample" function within a loop where the vector being sampled from (the first argument in the function) will vary in length and composition. When the vector is down in size to containing only one element, I run into the "undesired behaviour" acknowledged in the ?sample help file. I don't want sample(10,1) to return a number from

Hi, A noobie question: I'm simply trying to run a conditional statement that evaluates if a substring is found within a larger string. I find that if it IS found, my function returns TRUE (great!), but if not, the condition does not evaluate to FALSE. ex): if( grep("hi", "hop", fixed = TRUE) ) print('yes, your substring is in your string') else

I've made packages for Debian Squeeze for Gluster 3.4.0-alpha2, they are available on http://torbjorn-dev.trollweb.net/gluster-3.4.0alpha2-debs/. They built and installed successfully, and have been running nicely for a couple of hours, but your mileage may vary. The Debian packaging is on http://torbjorn-dev.trollweb.net/gluster-3.4.0alpha2-debs/glusterfs-3.4.0-debian.tar.gz. I took the

Greetings, I am not familiar with processing text in R. Can someone tell me how to read each line of words as separate elements in a list? FE, I would like to turn: word1 word2 word3 word2 word4 into a list of length two with three character elements in the first list and two elements in the second. I know that this should be easy, but I am a little confused by the text functions. Thanks in

Hi, I'm requesting you don't berate me for asking this question: I clearly don't have the gist of factors. I have two dataframes, A and B. Each of them has a column containing strings (they're labels). I want to, one-by-one in a loop, compare the particular string in an entry from dataframe A to an entry in B, to see if they're the same. The problem, when posing the

ls is a list of character vectors created by strsplit() I want to concatenate the 1st 4 character elements of each list item as a new vector called file. I admit to being confused about list syntax even after numerous readings. Here's what I tried: ls <- list(c("Focused", "10k", "A12", "t04.tif", "+", "µm"),

Dear R helpers: I wonder how to pass more than one argument to the function called by lapply. For example, #R code below --------------------------- indf <- data.frame(id=I(c('a','b')),y=c(1,10)) #I want to add an addition argument cutoff into the function called by lapply. outside.fun <- function(indf, cutoff) { unlist(lapply(split(indf, indf[,'id']),

Hi, There must be an easy way to do this, but I'm not finding it.. I'd just like to know the syntax to move up and down folder levels, without necessarily entering a full file path. Also, how to construct file and folder paths using variables. For example 1, if I wanted to print to the screen the contents of a file called myFile.txt using the bash shell, I'd use the following:

Hi R-help, I am interested in comparing two vectors of data observations to see if they come from the same distrubution (and have settled on the Kolmogorov-Smirnov test to do this).. I'd prefer to use all my data points, but computationally speaking, this is proving to be troublesome due to the size of my vectors (the larger of the two is about 90 million observations). I suppose I could

Dear fellow R users, I am replacing elements of a list like so: pulse_subset[[1:20]]=unlist(pulse[i])[1:20] where pulse is a list of lists, and pulse [i] has >20 values. This gives the error "Recursive Indexing failed at level 2". But, interestingly this instruction is part of a loop which has gone through about 200,000 iterations before giving this error. Actual code: >

Hi Sorry to ask such a basic question. I have a list, each element of which is a vector of two values. What I actually want is a matrix with two columns, and one row per element of the list. Obviously I have tried as.matrix(), and as.vector() but I didn't expect the latter to work. I feel so lame asking this. Any suggestions? Mick