similar to: save in for loop

Dear users, I would like to process all the lists from all *.rda files that I have in one folder. Up to now, I can load all the *.rda files without any problem. The problem is when I want to access the list saved within each *.rda file (only one list per rda file). Here is my code: fpath <- "D:/R" listnames <- list.files(path=fpath, pattern=glob2rx("*.rda"),

Hey all, I am writing a function in which I will have a matrix of 4 columns and a variable amount of rows. The first to columns will always contain be of the Character type, the third and fourth columns can be a variation of data types, usually characters and integers, but sometimes lists or matrices. At one point the code makes, for each row, a copy of that row, then it makes some adjustments

Dear group, I am trying to write functions, but as a beginner, everything is not so obvious. Let's say I want the results in a list of elemts like this : tot1, tot2, etc Here is a function: toto <- function(x,y) { for(i in x:y){ paste(c("tot",i),collapse="")<-(i*2) } } If I type this : >toto(1,5) I get this message error: Error in paste(c("tot",

Greetings, I am a very novice user with R, and in the course of running a linking procedure : P.old<- function (a, c, b, xi){ #a contains a parameters #c contains c parameters #b contains b parameters #xi is a one column vector containing quadrature points for xi(=theta-gamma)for one item tmp <- a*(xi-b)

Hello everyone, I have versions 2.7.2 and 2.10.1 installed on a machine that has no access to internet. In 2.7.2 I can use ? to get help on functions, which in 2.10.1 that does not work, all I see is "starting httpd help server...done" and then nothing. Have I downloaded 2.10.1 incorrectly (=forgot to tick some box for local help file repository) or is the internet help now the

Simple one here ... but can't get it to work ... for (i in 1:4){ paste("stuff",[i]),sep="") <- 3 + i } ls() rm(list=ls()) I just want it to create 4 new variables called stuff1, stuff2, stuff3, stuff4 with the corresponding assignments. I realise that there are more elegant functions but this is just a model of a bigger situation. Thanks Jim

sorry I had a mistake sending my question without a subject. I do resend again. Please excuse me. > Hello > I have a data array with soil variables (caperf), in which the variable "clay" is factor (as I see entering str(caperf)) . I need to do a regression model, so I need to have arcilla (=clay) as a numeric variable. For that I have entered > >

Hi, I have tried looking at the archives but havent found any answer that works till now (Sorry if i have missed anything) I am a newbie to R and i am trying to carry out hierarchical clustering using hclust -> as.dendrogram and then plotting the results as a dendrogram using the plot function plot(object). My question is : In the function "plot", can one decrease the leaf label

Dear R users, I would like to compare two dataframes, actually their categorical variables (as factors) only (there are 12, from column 1 to 12). The reason I do that is that I got 2 datasets from two different methods and I would like to be sure that each method used the same data (3D images) to extract 2 different sets of 3D parameters. Is it clear so far? So I thought about using

Hello guys, I want to rbind the columns of a data frame but I don't know how to do it, let's say: A B C 1 2 3 1 2 3 I want to get 1 1 2 2 3 3 It seems very simple but I still didnt get a find of how to do it...Please help! -- View this message in context: http://r.789695.n4.nabble.com/bind-a-data-frame-columns-tp2318526p2318526.html Sent from the R help mailing list archive

Good morning, I have something like this: names(coint_tests) <- apply(b,2,paste, collapse="_") which prints 15 names like: A_B, C_D, E_F, ... AA,B,C,D.. Are time series. Then there is a vector called coint_tests of length 15 which yields "yes" or "no". I need to add a function to plot the time series Ai_Bi if the coint_tests vectors gives me a "YES".

Dear R-help list users, I have a huge vector of numbers, how I can invert orden? For example x <- 1:10000000 I would like to obtain x_r <- 10000000:1 Thanks, Sebastian.

Dear list, I have a question I'm trying to use the following command in R, but it gives me an error message.The command is: data<-ddply(data,c("year","name"), transform, check1=ifelse(check1==1 & check2==1, 1,NULL)) so in my data frame I already have the check1 variable, if the conditions (check1==1 & check2==1) is respected, check has to have 1 as value,

Hi I have two data frames that contains the same sort of data and I want do add them together to get one big data frame, anyone know how to do that? ex: data.frame1 A B C 1 2 3 4 5 6 7 8 9 and data.frame2 A B C 9 8 7 6 5 4 3 2 1 Would then become one big set: data.frame3 A B C 1 2 3 4 5 6 7 8 9 9 8 7 6 5 4 3 2 1 Thx for your help //Joel -- View this message in context:

Dear fellows, I am a novice in R. I would like to combine a matrix and a vector. Assume that we have the matrix a and the vector b with same length of column. a<-matrix(seq(1:10),nrow=2,ncol=5,byrow=TRUE) a= 1 2 3 4 5 6 7 8 9 10 b<-t(c(11,12,13,14,15)) b= 11 12 13 14 15 Then, I want to combine a and b as follows. c= 1 2 3 4 5 6 7 8 9

Hi, I have a list which looks like this... > str(y) List of 10 $ : chr [1:4] "ABCD" "5" "0" "1" $ : chr [1:4] "DEF" "15" "1" "16" $ : chr [1:4] "AAA" "2" "17" "8" $ : chr [1:4] "SSS" "15" "25" "1" $ : chr [1:4] "III"

Dear fellow R users, I am trying to conduct a regression analysis. I have thousands of variables. The names are V1, V2,........V2000 Is there an easy way to include these variables in the regression? my model is something like that: model<- lm(y~V1+V2+.....+V2000, data=data) Thanks so much in advance, Ozlem

Hello, How can I read a xlsx file using xlsx package? Thanks Albert [[alternative HTML version deleted]]

Hi there, I have been trying to use the "pvclust" package but have been having some difficulties. This is the first time I have used R so I am sure the mistake I am making is a basic one. The data I have is a distance matrix and I have been using the command; fit <- pvclust(cluster, nboot=1000, method.dist="euclidean") to try and perform hierarchical clustering with

It looks from str(SA) that Response IPS1 is a data.frame of class "anova", which probably cannot be coerced to vector. Maybe you can use unlist() instead of as.vector() Or something like SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even maybe with unlist() Without a better REPRODUCIBLE example, I cannot tell more (maybe some others