similar to: Change order of columns in table?

Hi, I?ve got some problems with the labels of the x-axis I,ve got two factors with two categories each: sex (males and females) and area (central and peninsulae), but because of the lenngth in the graphic just appeared two of the four labels. I thought the solution could be rotate it 45? degrees, I have read it can be done with "srt" or "rotate", but I don?t know hoe to use

Fellow R users, I am stumped on what would seem to be something fairly simple. I have a dataframe that has a variable named 'WEEK' that takes the numbers 1:26 (26 week time-period) with each number repeated five times consecutively (once for each weekday, Monday through Friday). Ex. 111112222233333.....2626262626. I would like to randomly extract two weekdays per five day week for

Hi, I am trying to count weekday of the month using R. For example, 1/4/2001 is the 4th weekday of Jan, and 1/5/2001 is the 5th weekday of the month, and 1/8/2001 is the 6th weekday of the month, etc. I get as far as extracting the weekdays from a sequence of dates (see below). But I have not yet figured out a fast way of counting without using a For Loop. Does anyone know how to do such counting

Hi all, probably really simple: I seem to be lacking some understanding for the character class: I have a bunch of dates in a dataframe and I want to add a string variable with the weekday for each date. If I use something like mydata$day <- weekdays (mydata$date), I can create subsets for each weekday (eg mydata=="Monday"), but summary (mydata$day) doesn't count the instances for

For what it's worth, I tried setting my Region | Formats setting to Spanish (Peru) in Windows 10 Control Panel, and got Spanish weekday and month results. I believe on Windows we use the Microsoft C strftime function to produce these strings, with the %A (for weekday) or %B (for month) formats. So this question probably needs to be addressed to Microsoft. Duncan Murdoch On 05/06/2017

(Sorry for reposting. Please delete previous msgs. Thanks!) Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604

Dear R-users, How do I obtain a sequence of dates consisting of only weekdays without the weekends in R? In S, I can do the following: timeSeq(from="12/17/2007", to="8/25/2008", by="weekdays") I tried using looking at timeSequence (fSeries package) and seq.Date (base package) but I do not know if I can specify "weekdays" rather than "day".

Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604 3 2010-05-31 Monday 0.74813943 4 2010-06-01 Tuesday

Hi Folks! I'm struggling with dates - but enough about my personal life..... I have two daily time series files. In one (x) the date format is Y/m/d and the other (y) is d/m/y. I used read.zoo on both and they read into R with no problem. Then I use: weekdays(as.Date(x$DATE)) and get what I expect - all the days of the week in my data set. When I use:

Hi, I am wondering if there is a simple way to fix the problem I am having. For unknown reason, I could not get the full name of the factors to be printed in the summary. I have tried to used summary.lm as well but the problem still persists. SJ$Weekday <-

Hi All, I'm fitting an intercept ANOVA model using R. I'm using following contrast statement, so my first level is considered as base level. options(contrasts = c("contr.treatment", "contr.treatment")) My data has two factors are "Month" and "WeekDay". Due to default alphabetic ordering, the Month(April) and WeekDay(Friday) are considered as base

Hi, I want to reporte some strange behaviour with the "months" function, from base R. When using "months" to extract months from a date column, I'm getting the months in english, when I was expecting months in spanish. When using "weekdays" to extract days of week from a date column, I'm getting the the days in spanish (as expected). My understanding is

Hello, I'm trying to make a 3D pie chart, but my labels are overlapping. I see that labelpos could offer a solution to this, but I have been unable to find any code snippets that indicate what type of value this argument requires. Any guidance would be appreciated! thank you, Tiffany

Thank you Duncan and Rui for your time and interest in this issue. Maybe it is a problem with Windows 7 and Spanish, and not Windows 10. Let's wait for someone with the same enviroment, before assuming it's a problem with my PC/configuration. 2017-06-05 14:37 GMT-05:00 Duncan Murdoch <murdoch.duncan at gmail.com>: > For what it's worth, I tried setting my Region

Hello, This doesn't answer the question, but in portuguese it works as expected. > x <- as.Date("2017-06-05") > months(x) [1] "junho" > weekdays(x) [1] "segunda-feira" > sessionInfo() R version 3.4.0 (2017-04-21) Platform: x86_64-w64-mingw32/x64 (64-bit) Running under: Windows 7 x64 (build 7601) Service Pack 1 Matrix products: default

R users, I am trying to generate a randomized weekday survey schedule that ensures even coverage of weekdays in the sample, where the distribution of variable DOW is random with respect to WEEK. To accomplish this I need to randomly sample without replacement two weekdays per week for each of 27 weeks (only 5 are shown). However, I need to sample from a sequence (3:7) that needs to be

I just started playing with rails this week and am working on porting our existing website to rails in our navigation we have a list that has the days of the week that link to the articles for those days. this seems to be working when I had it in the template it would give me the array I was looking for so I decided to move it to the helper so that I could use it on all my templates.

On converting character variables to ordered factors, regression result has strange names. Is it possible to obtain same variable names with and without intercept? Thanks, Naresh mydf <- data.frame(date = seq.Date(as.Date("2024-01-01"), as.Date("2024-03-31"), by = 1)) mydf[, "wday"] <- weekdays(mydf$date, abbreviate = TRUE) mydf.work <- subset(mydf, !(wday

I am having trouble finding out how to adjust the position of labels on pie charts. For the small wedges, many of the labels overlap making it impossible to read. Is there any way to offset the labels so that they don't overlap? Adam Green USGS Patuxent Wildlife Research Center [[alternative HTML version deleted]]

Hello, I have a dataset which has fields giving both calendar date and weekday. I know better functions are now available, but I am still using chron because of the is.holiday() function and a homemade (even Heath Robinson would be ashamed) is.daylight() function. As a check for typos in the data input, I checked that the dates matched the weekdays. I'm getting some confusing results