similar to: conditional calculations per row (loop versus apply)

Displaying 20 results from an estimated 2000 matches similar to: "conditional calculations per row (loop versus apply)"

2009 May 14
2
Function to read a string as the variables as opposed to taking the string name as the variable
I am writing a custom function that uses an R-function from the reshape package: cast. However, my question could be applicable to any R function. Normally one writes the arguments directly into a function, e.g.: result=cast(table1, column1 + column2 + column3 ~ column4, mean) (1) I need to be able to write this statement as follows: result=cast(table1, string_with_columns ~
2013 Mar 21
2
Displaying median value over the horizontal(median)line in the boxplot
Hi, set.seed(45) test1<-data.frame(columnA=rnorm(7,45),columnB=rnorm(7,10)) #used an example probably similar to your actual data apply(test1,2,function(x) sprintf("%.1f",median(x))) #columnA columnB # "44.5"? "10.2" par(mfrow=c(1,2)) lapply(test1,function(x) {b<-
2012 Jun 12
4
How to index a matrix with different row-number for each column?
here's my question: suppose I have a matrix: mt<-matrix(1:12,ncol=6) now I have a vector vt<-c(1,2,2,2,1,2) which means I want to get: the 1st row for column1; the 2nd row for column2; the 2nd row for column3; the 2nd row for column4; ... that what I want is this vector: 1,4,6,8,9,12 Does anyone know how to do this fast? I know I can use for-loop to travel all columns,but
2009 Jul 07
2
How to separate the string?
Hi everyone, Hi want to separate the string(column1) for example column1 column2 column3 column4 column5 column6 bear b e a r cat c a t tiger t i g e r I know how to do this in excel where using MID function. Now I want to solve it using R. The list of strings is in
2009 Aug 03
2
Some SQL Challenges
Hi, Im trying to complete a list of jobs using SQL Querries and some "if else" commands but im stucked in some steps. Could any of you give me some help? -in COLUMN1 change the format 20JAN2000:00:00:00 to 20JAN2000 and exclude every row that date is different from 20. -extract the first character in COLUMN2 and creat COLUMN3 with that value ex: COL2,COL3 135,1 461,4 247,2 -in every
2009 Mar 13
1
Realtime dialplan application versus REALTIME dialplan function
Hi All, I'm upgrading some PBX's from 1.2 to 1.4 and having a bit of trouble with converting the Realtime application to the REALTIME function. I have the method down and understand simplistically what is going on, at least enough to get my old 1.2 apps to run in 1.4 functions. I do not understand why change from the app to the func? What the benefits? To me, the app seemed so
2007 Oct 19
1
(no subject)
# Hello # I have a question regarding pairwise calculations of a matrix using a "for-loop." # Below I have a matrix "X" with 8 columns. These are Genotypic data so Column1 & Column2 is # a unit, Column3 & Column4 is a unit, Column5 & Column6 is a unit, and Coulmn7 & 8 is a unit. # I have a loop designed to calculate the number of times an individual in
2010 Jul 26
4
using string variable as order() function argument
Hello, In my script I would like to use a loop, which sorts the dataframe according to different columns, pointed by the string variable. id col1 col2 col3 1 10 0 4 8 2 11 1 2 2 3 12 0 8 3 4 13 0 5 5 Usually the order() function can be used like this: sorted = mytable**[order(column3) , ] which results in properly sorted table: **
2008 Feb 26
1
Split data.frames depeding values of a column
Hello to all is there a function wich splits a data.frame (column1,column2,column3,....) into data1 <-(column1,column3....) #column2 = 1 data2 <-(column1,column3....) #column2 = 2 data3 <-(column1,column3....) #column2 = 3 ... Regards Knut
2007 Oct 19
1
conduct pairwise column comparisons without comparing a column to itself
# Hello # I have a question regarding pairwise calculations of a matrix using a "for-loop." # Below I have a matrix "X" with 8 columns. These are genotypic data so Column1 & Column2 is # a unit, Column3 & Column4 is a unit, Column5 & Column6 is a unit, and Coulmn7 & 8 is a unit. # I have a loop designed to calculate the number of times an individual in
2006 Apr 20
0
parsing arguments of a function
Hi, I have a simple problem writing a function that is to be called like Myfunction( Column1 = low, Column2 = high, Column3 = all, Column4 = all, data = mydata) {. contourplot(z ~ mydata$Column3* mydata$Column3) . } Where Column1 and Column1 are the names of the dataframe mydata. How do I parse the arguments to obtain both, name and value of the argument. I tried strsplit(Column1,
2010 Feb 27
1
New Variable from Several Existing Variables
I am new to R, but have been using SAS for years. In this transition period, I am finding myself pulling my hair out to do some of the simplest things. An example of this is that I need to generate a new variable based on the outcome of several existing variables in a data row. In other words, if the variable in all three existing columns are "Yes", then then the new variable should
2004 Oct 25
2
Reading sections of data files based on pattern matching
I am about to write general functions to read the output of simulations models. These model generate output files with different sections which I want to analyze plot etc. Since this will be used many people at the department I wanted to make sure that will do this in the best way. For instance I want to read a snippets of data from a text that look like this.
2006 Apr 06
1
reshape question
Hi, I have a data fram like this: date column1 column2 column3 value1 value2 value3 1-1 A B C 10 5 2 2-1 A B D 5 2 0 3-1 A B E 17 10 7 How can I reshape it to: date column1 column2 column3 v x 1-1 A B C value1 10 1-1 A B C value2 5 1-1 A B C value3 2 2-1 A B D value1 5 2-1 A B D value2 2 2-1 A B D value3 0 3-1 A B E value1 17 3-1 A B E value2 10 3-1 A B E value3 7 Thx! Regards, Richard
2012 Mar 16
5
How to Group Categorical data in R?
Hi, I am newbie to R and working on result presentation? My Input table is in following format A B C D X T C K Z U Z M E V Z R Z U Z M E V P R I need to present my result in the
2008 Mar 05
3
ipf function in R
Hi I have a 3 x 2 contingency table: 10 20 30 40 50 60 I want to update the frequencies to new marginal totals: 100 130 40 80 110 I want to use the ipf (iterative proportional fitting) function which is apparently in the cat package. Can somebody please advice me how to input this data and invoke ipf in R to obtain an updated contingency table? Thanks. By the way I am quite new to R. -- Dr
2010 Feb 09
3
split strings in a vector and convert it to a data.frame
hi, I have a vector full of strings like; xy_100_ab xy_101_ab xy_102_ab xy_103_ab I want to seperate each string in three pieces and the separator should be the "_" at the end I want a data.frame like: column1 column2 column3 xy 100 ab xy 101 ab xy 102 ab xy 103 ab I tried strsplit but I couldn't figure out how to convert the list I get into a data.frame. I just
2004 Sep 10
3
Improving on Rice coding
Hello, I am the author of the Bonk audio compression program... i've just been looking at your comparrison table, and i noticed bonk gets marginally better compression than Flac on some files (actually i was rather surprised to see bonk on the list at all, it's not exactly high profile :-) ). Bonk in lossless mode is a pretty naive implementation of a predictive coder, so the main
2008 Feb 29
1
can the matrix size limit be increased?
Hi there, I'm brand new to R, so let me know if this question is not appropriate for this list. I've been reading through the documentation and have tried a number of things, but am pretty much stuck so far. Here's the session info: > sessionInfo() R version 2.6.2 (2008-02-08) i386-apple-darwin8.10.1 locale: C attached base packages: [1] stats graphics grDevices
2003 Nov 24
4
R postscript generation error (lines versus points) (PR#5285)
Full_Name: Stephen Harker Version: 1.80 OS: linux (Yellow Dog 3.0 on ppc) Submission from: (NULL) (130.194.13.101) In creating a postscript file from a set of data in which the points are plotted using `points()' and lines drawn using `lines()' I have found since upgrading from R version 1.4? to 1.8 that the two sets do not coinicide completely. This is best illustrated by a simple