similar to: Questions about ggplot2

Hi, I have the follow ggplot2 code I am running: ggplot(data=bb.res.math,aes(x=factor(id.bb),y=bb.math.comb,fill=BB)) + geom_bar() + facet_grid(BB~.) + scale_fill_brewer(pal="Set1") + ylab("Average Student Residual (Math)") + xlab("Student ID") The number of unique id.bb is 2207 and so my X-axis has a couple of thousands, indistinguishable tick marks that correspond

Hi, I am using ggplot2 to with the following code: gmathk2 <- qplot(time,math,colour=Kids,data=kids.ach.lm.k5,geom="smooth",method="lm",formula=y~ns(x,1)) + opts(title="Smoother Plot: Math K-5") + xlab("Time") + ylab("Math") + scale_colour_brewer(pal="Set1"); gmathk2 This plots all the smoother for all the x values. What I'd like

Hi, I have 45 models that I have named: 1, 2, 3, ... , 45 and I am trying to plot them in order of ascending BIC values. I am however unclear as to how I can get the models to line up on the x-axis by BIC and not by numeric order. For example, if model 5 has a lower BIC than 1, I want it to be the first point on the left hand side of the curve. This seems to work in plot: plot(1:45,

Hi, I have 45 models that I have named: 1, 2, 3, ... , 45 and I am trying to plot them in order of ascending BIC values. I am however unclear as to how I can get the models to line up on the x-axis by BIC and not by numeric order. For example, if model 5 has a lower BIC than 1, I want it to be the first point on the left hand side of the curve. This seems to work in plot: plot(1:45,

A new version of the ggplot2 web application is available at http://www.yeroon.net/ggplot2. New features include 1D geom?s (histogram,?density, freqpoly), syntax mode (by clicking the tiny arrow at the?bottom), and some additional facet options. Furthermore some minor?improvements and fixes, most notably for Internet Explorer. As usual, a little demo video that shows how to use the new features:

I get the following error when I run qplot() qplot(grade, read,data = hhm.long.m, geom = c("point", "smooth")) Error in smooth.construct.cr.smooth.spec(object, data, knots) : x has insufficient unique values to support 10 knots: reduce k. I am not sure how to tackle this problem. When I take a subsample (< 1000) than I am able to run that function but with my sample

Hi, I am wondering if there is a way to change the pattern of the fill in histogram in ggplot2? By default the fill is solid and I'd like to add some sort of pattern to make it more visible that these are different levels of a factor. Thanks! Chris [[alternative HTML version deleted]]

Hi: I need some help. I am ploting a bar graph but I can't adjust my x axis scale I use this code: i <- qplot(ForkLength,Number,data=FL,geom="bar") i + geom_bar(colour="blue",fill="grey65") # too crowded FL_dat <- ggplot(FL,aes(x=ForkLength,y=Number)) + geom_bar(colour="green",fill="grey65") FL_dat +

Hi, Let's say I have the following data: > a=matrix(c(1,2,4,4,2,1,1,2,4),nrow=3,byrow=T) > a [,1] [,2] [,3] [1,] 1 2 4 [2,] 4 2 1 [3,] 1 2 4 What syntax should I use to get R to tell me the column that corresponds to the maximum value for each row? For my example, I would like to get a vector that says 3, 1, 3 because the maximum value for row 1 is

Hi, I am having trouble with syntax for a for loop. Here is what I am trying to do. class=c(rep(1,3),rep(2,3),rep(3,3)) out1=rnorm(length(class)) out2=rnorm(length(class)) out3=rnorm(length(class)) data=data.frame(class,out1,out2,out3) dat.split=split(data,data$class) for(i in 1:3){ sub[i]=dat.split[i] } However, the for loop doesn't work. I want to assign each split to a different

Hi, I am trying to write a loop to recode my data from -999 to NA in R. What's the most efficient way to do this? Below is what I'm presently doing, which is inefficient. Thanks, Chris dat0 <- read.table("time1.dat") colnames(dat0) <- c("e1dq", "e1arcp", "e1dev", "s1prcp", "s1nrcp", "s1ints",

* Please cc me if you reply as I am a digest subscriber * Hi, I am wondering how I can run a multilevel survival model in R? Below is some of my data. > head(bi0.test) childid famid lifedxm sex age delta 1 22.02 22 CONTROL MALES 21.36893 0 2 13.02 13 MAJOR MALES 21.18001 0 3 64.02 64 CONTROL MALES 20.09377 0 4 5.02 5 CONTROL FEMALES

Hi, I was trying to draw a geom_bar plot. However, by default, the bars are arranged according to the label, which I don't want. I want the bars to appear exactly as they appear in the data frame. For example in the code: Lab=c(letters[4:6],letters[1:3]) valuex = c(3.1,2.3,0.4,-0.4,-1.2,-4.4) df <- data.frame(Lab,valuex) px <- ggplot(df,aes(Lab,valuex,label=Lab)) +

Dear R experts, I am trying to arrange multiple plots, creating one graph for each size1 factor variable in my data frame, and each plot has the median price on the y-axis and the size2 on the x-axis grouped by clarity: library(ggplot2) df <- data.frame(price=matrix(sample(1:1000, 100, replace = TRUE), ncol = 1)) df$size1 = 1:nrow(df) df$size1 = cut(df$size1, breaks=11)

Hi, I am trying to fit the following model: sr.reg.s4.nore <- survreg(Surv(age_sym4,sym4), as.factor(lifedxm), data=bip.surv) Where age_sym4 is the age that a subject develops clinical thought problems; sym4 is whether they develop clinical thoughts problems (0 or 1); and lifedxm is mother's diagnosis: BIPOLAR, MAJOR DEPRESSION, or CONTROL. I am interested in whether or not

Dear List, (self-contained example + version info at the bottom) I'm having trouble producing a barplot using the functions in ggplot2. When I use the position="dodge" option, the bars are plotted but also a number of spurious markers. More specifically, a number of black dots are plotted in the graph that should not be there. This behaviour is not seen when calling the same

Hi all I have a large dataframe with (among others) a categorical variable of 52 levels and would like to create a barplot with the bars ordered in decreasing frequency of the levels. I belive it is referred to as a pareto plot. Consider a subset where I keep only the categorical variable in question. # Example: v1 = c("aa", "cc", "bb", "bb",

When I am using geom_bar I get these white slashes through the legend keys. I cannot figure out how to remove them. ggplot(diamonds, aes(clarity, fill=cut)) + geom_bar() I have tried using opts(legend.key = theme_blank()) but with no luck. Any suggestions would be much appreciated. I am using R vers. 2.15.0 and ggplot 0.9.1, win xp Best wishes Jonas Hal

You just have to change the levels of the factor ... library(ggplot2) Lab = c(letters[4:6], letters[1:3]) valuex = c(3.1,2.3,0.4,-0.4,-1.2,-4.4) df <- data.frame(Lab,valuex) # set the factor levels to the same order as observed in the data frame df$Lab <- factor(df$Lab, levels=unique(df$Lab)) px <- ggplot(df,aes(Lab,valuex,label=Lab)) + geom_text(aes(y=0)) + geom_bar(stat =

Dear R Community, Below is a problem with a simple ggplot2 graph. The code returns the error message below. Error: stat_count() must not be used with a y aesthetic. My code is below and the data is attached as a ?text? file. # Graph of the probabilities library(digest) library(DT) datatable(probability) str(probability) probability$Fertilizer <- as.factor(probability$Fertilizer)