similar to: getting random integers

If I combine elements into a list b <- c(22.4, 12.2, 10.9, 8.5, 9.2) my.c <- sample.int(round(2*mean(b)), 5) my.list <- list(b, my.c) the names of the elements seems to get lost in the process: > str(my.list) List of 2 $ : num [1:5] 22.4 12.2 10.9 8.5 9.2 $ : int [1:5] 11 8 6 9 20 If I explicitly name the elements at list-creation, I get what I want: my.list <- list(b=b,

c <- structure(c(2L, 2L, 1L, 3L, 4L, 2L, 3L, 2L, 3L, 2L, 5L), .Label = c("foo", + "bar", "a really really long variable label mostly here to show the need of word-wrapping text in labels", + "a not so important value", "baz"), class = "factor") plot(c) Is there a way to get the long variable labels to automatically wrap so that all

foo <- rnorm(30*34*12) dim(foo) <- c(30, 34, 12) I want to make a data.frame out of this three-dimensional array. Each dimension will be a variabel (column) in the data.frame. I know how this can be done in a very slow way using for loops, like this: x <- rep(seq(from = 1, to = 30), 34) y <- as.vector(sapply(1:34, function(x) {rep(x, 30)})) month <- as.vector(sapply(1:12,

Hello r-help! I have data with two kind of ratings on status of 100 occupations. The first kind of rating is on the percieved "objective" status that these occupations have in society at large, and the second kind or rating is on the status that the respondents think that these occuption *should* have. The ratings were originally integer values in the rage 1-9, but in the current data,

Hi list I have a data frame I would like to loop over. To begin with I would like crosstabulations using the first variabel in the data frame, which is called "meriter". > table(meriter[[1]], meriter[[3]]) ja nej Annan 0

Hi, I have problem. In the function below (test and test2) i want the function test not to print the variable data but i want the function test2 to use the variable test$data. This is the creation of the variable data: > matrice=c(1:10) > matrice=matrix(matrice,nrow=5,ncol=2) This is the function test: > test=function(data){ + return(list(x=5,data=data)) + } This is the function

Dear R users, I have a problem since I try to plot my datas with different colors. plot(tvar, var, xlab="zeit [s]",ylab="Variation [%]", col = ifelse(var <= varstability, 'green','red')) this works well! But since I add a type="l" to my plot, it will color all the plot with green!!! Is there any solution? I avoid to use teachingDemos. Thanks. --

Hi all Say I have a function: myname=function(dat,x=5,y=6){ res<<-x+y-dat } for various input such as myname(dat1) myname(dat2) myname(dat3) myname(dat4) myname(dat5) how should I modify the 'res' line, to have new informative variable name correspondingly, such as dat1.res dat2.res dat3.res dat4.res dat5.res stored in the workspace. This is only an example of a complex

Hello, I have a nasty loop that I have to do 11877 times. The only thing that slows it down really is this merge: xx1 = merge(dt,ua_rd,by.x=1,by.y= 'rt_date',all.x=T) Any ideas on how to speed it up? The output can't change materially (it works), but I'd like it to go faster. I'm looking at getting around the loop (not shown), but I'm trying to speed up the merge first.

Dear All, I am trying to install rgl on my mac notebook from the source file. I tried using: /usr/bin/R64 CMD INSTALL rgl_0.92.798.tar.gz and get the following error message: checking for X... no configure: error: X11 not found but required, configure aborted. ERROR: configuration failed for package ?rgl? * removing ?/Library/Frameworks/R.framework/Versions/2.14/Resources/library/rgl? *

Hi r-help! Consider the following data-frame: var1 var2 var3 1 3 1 4 2 2 2 3 3 2 2 3 4 4 4 NA 5 4 3 5 6 2 2 3 7 3 4 3 How can I get R to convert this into the following? Value 1 2 3 4 5 var1 0 3 2 2 0 var2 1 3 1 2 0 var3 0 0 4 1 1 TIA, -- Hans Ekbrand (http://sociologi.cjb.net) <hans at

I must be missing something obvious here: According to the help page for read.spss, the reencode option is only active when R is run under a UTF-8 locale. read.spss can only import the SPSS file when run under a iso88591(5) locale, under a UTF-8 locale I get: Error in read.spss("wo.sav") : error reading system-file header In addition: Warning message: In read.spss("wo.sav")

Dear R helpers, I have a large data set with 36 variables and about 50.000 cases. The variabels represent labour market status during 36 months, there are 8 different variable values (e.g. Full-time Employment, Student,...) Only cases with at least one change in labour market status is included in the data set. To analyse sub sets of the data, I have used daisy in the cluster-package to create

Hi list! Short version: How do I convert a whole data.frame from latin1 encoding to utf8? I get SPSS files with latin1 encoding. My OS is GNU/Linux and the locale sv_SE.utf8, and I normally interface R with Emacs/ESS. I have used the following hack to convert a data.frame in latin1 to utf8: > Sys.setlocale(category = "LC_ALL", locale = "sv_SE.iso88591") > foo <-

Hi, I'm plotting 4 graphs on one page (2x2 matrix) but I cant seem to get the title for the whole page right. I'm doing: op <- par(mfrow = c(2,2), pty="s") hist(var$V2, breaks="FD",main="Euclidean Metric", xlab="Sum of 3NN ... hist(var$V2, breaks="FD",main="Manhattan Metric", xlab="Sum of 3NN ... hist(var$V2,

I have a column of 1000 datapoints from the normal distribution with mean 2 and variance 4. How can I get a histogram of these observations with 20 bins with each bin having 50 observations? -- Thanks, Jim. [[alternative HTML version deleted]]

Hi, I have a set of observations which are divided into two sets A and B. I have some code that bins the dataset into 10 bins based on the max and min of the observed values. I would like to make a histogram of A & B using my calculated bins but plot the distribution of B on top of A (like a stacked barplot). This is possible since both sets A & B are binned using the same bin ranges.

Hi: I have been trying to figure out a simple way to plot an histogram whose frequencies are modified by a factor (associated with each value). Actually what I did was plotting each value with its modified frequency(using plot($values, $frequency, type="h")), but it doesnt take into account the probability distribution(which is necessary). It will be very helpful from you any

Hello, To indicate probability densities instead of counts on a histogram, I specify freq = FALSE. However, I expect that summing all top y coordinates over all the intervals of the histogram will provide 1. 1) v <- c(0.2885, 0.2988, 0.3139, 0.2615, 0.3179, 0.3163, 0.2583, 0.3052, 0.2527, 0.3147, 0.3235, 0.2408, 0.2480, 0.3108, 0.3577, 0.2829, 0.2694, 0.3275, 0.3314, 0.2639, 0.3076,

Dear All, I am creating 4 plots (files) but I could see only 3. Here is a simple code d=data.frame(age=rnorm(100,40,8),ht=rnorm(100,170,15)) tiff(file=paste("test","%03d",".tif",sep="")) hist.data.frame(d) datadensity(d) par(mfrow=c(1,2),mar=c(3,3,3,3)) boxplot(d$age) hist(age) dev.off() PDF works fine but png and tiff seems to miss the second