similar to: small change in output

Displaying 20 results from an estimated 9000 matches similar to: "small change in output"

2010 Apr 26
1
Error in pf(q, df1, df2, lower.tail, log.p) : Non-numeric argument to mathematical function
inputfille snpid indid genotype gvariable probeid gene geneexpression rs1040480 CHB_NA18524 C/T 2 GI_19743926-I PTPRT 5.850586 rs1040480 CHB_NA18526 C/C 1 GI_19743926-I PTPRT 6.028641 rs1040480 CHB_NA18529 C/C 3 GI_19743926-I PTPRT 5.944392 rs1040481 CHB_NA18532 C/C 1 GI_19743926-I PTPRT 5.938578 rs1040481 CHB_NA18537 C/C 2 GI_19743926-I PTPRT 5.874439 rs1040481 CHB_NA18540 C/C 3 GI_19743926-I
2010 Apr 13
2
liner regression for multiple keys
a1 is the first key in input. second column is x-axis and 3rd is y-axis and 4th is its corresponding key. Now for every key in 1st column I would like to calculate LR that gives p value. I tried to manage with a single key. But my problem is that How could I manage multiple keys in input. Thanx in advance input a1 1 2.5 x a1 2 3.5 x a1 3 4.5 x a1 1 2.6 x a1 2 3.8 x b1 1 4.6 y
2003 Jul 07
1
P-value for F from summary.lm (was RE: (no subject))
[Please use the subject line!] In the help page for summary.lm, the "Value" section says that the returned object has a component called "fstatistic", which has the F-statistic and the associated numerator and denominator degrees of freedom. You can get the p-value by something like: fstat <- summary(speciallinearmodel)$fstatistic pval <- pf(fstat[1], fstat[2],
2012 Dec 14
1
format.pval () and printCoefmat ()
Hi List, My goal is to force R not to print in scientific notation in the sixth column (rel_diff - for the p-value) of my data frame (not a matrix). I have used the format.pval () and printCoefmat () functions on the data frame. The R script is appended below. This issue is that use of the format.pval () and printCoefmat () functions on the data frame gives me the desired results, but coerces
2010 Dec 22
0
fdrtool help
Hello, I am using fdrtool(x, statistic="pvalue") where x is a vector of chisq p-values. I can get this command to work with some x, but not with others. When it does NOT work, I get the following screen output: > fdrtool(pvals$Chi2.pval, statistic="pvalue") Step 1... determine cutoff point Step 2... estimate parameters of null distribution and eta0 Step 3... compute p-values
2023 Oct 29
1
The argument 'eps.Pvalue' of `printCoefmat()`
Hi all, Just a minor issue that I am not sure whether this is considered a "bug." It is about the help page. In the help page of printCoefmat(), for the argument 'eps.Pvalue', the description is as below: number, .. I have to read the source to figure out that this argument is to be used by format.pval(). Maybe the description of 'eps.Pvalue' can be revised to refer
2023 Oct 29
1
The argument 'eps.Pvalue' of `printCoefmat()`
On 29/10/2023 3:48 a.m., Shu Fai Cheung wrote: > Hi all, > > Just a minor issue that I am not sure whether this is considered a > "bug." It is about the help page. > > In the help page of printCoefmat(), for the argument 'eps.Pvalue', the > description is as below: > > number, .. > > I have to read the source to figure out that this argument
2013 Jun 24
1
help needed with printing multiple arguments as vectors, not matrices
** I am using the following way to get p-values from fiser exact test. However, I do need to print for each pair the values "n00, n01, n10, n11". How can I print that as a table and not a matrix as below along with the p-value? Any help will be greatly appreciated fish <- function(y, x) {n00 = sum((1-x)*(1-y)); n01 = sum((1-x)*y); n10 = sum(x*(1-y)); n11 = sum(x*y); a =
2016 Apr 29
2
lm() with spearman corr option ?
Hi, A following function was kindly provided by GGally?s maintainer, Barret Schloerke. function(data, mapping, ...) { p <- ggplot(data = data, mapping = mapping) + geom_point(color = I("blue")) + geom_smooth(method = "lm", color = I("black"), ...) + theme_blank() + theme(panel.border=element_rect(fill=NA, linetype =
2011 Sep 28
2
apply lm function to dataset split by two variables
Dear all, I am not fluent in R and am struggling to 1) apply a lm to a weight-size dataset, thus the model has to run separately for each species, each year; 2) extract coefs, r-squared, n, etc. The data look like this: year sps cm w 2009 50 16 22 2009 50 17 42 2009 50 18 45 2009 51 15 45 2009 51 16 53 2009 51 17 73 2010 50 15 22 2010 50 16 41 2010 50 16 21 2010
2012 Aug 06
1
cannot find function "simpleRDA2"
Hi, I am trying to run the command "forward.sel.par," however I receive the error message: "Error: could not find function 'simpleRDA2'." I have the vegan library loaded. The documentation on "varpart" has not helped me to understand why I cannot call this function. Maybe I am missing something obvious because I am still an 'R' novice. Below is a
2009 Jun 16
2
save the output of summary(lmList(x)) into a dataframe
Hi r-helpers! I need to save the output of summary() function that I?ve runned like this: z<- lmList(y~x1+x2| x3, na.action=na.omit,data1,subset=year==1999) w<-summary(z) The output (w) is something like this: Call: Model: y ~ x1 + x2 | x3 Data: data1 Coefficients: (Intercept) Estimate Std. Error t value Pr(>|t|) 1 0.081110514 1.141352e-01
2000 Apr 05
2
My first R-program
Sorry, I pasted the wrong file in earlier... this is the correct one: pValCalculator(b, n=20, m=20) { ind <- 1:min(c(n,m)) prob <- (1-pnorm(b,sd=std*sqrt(ind))) prob1 <- sum((n-ind+1)*(m-ind+1)*prob) prob1 } inputData <- scan("/users/lvssso/projects/LAMA/output/pValLamaScore.tmp", list(block1 = "",block2 = "",width1 = 0,width2 = 0,alignment = 0,score
2010 Apr 27
3
Problem calculating multiple regressions on a data frame.
Hi there, I am stuck trying to solve what should be a fairly easy problem. I have a data frame that essentially consists of (ID, time as seqMonth, variable, value) and i want to find the regression coefficient of value vs time for each combination of ID and Variable. I have tried several approaches and none of them seems to work as i expected. For example, i have tried:
2000 Apr 05
0
My first R program
Hi, Sorry to bother you guys with this syntax problem, this is my first R program, and I seem to not have grasped something right. I keep getting an error message from 'parse' on the line with the *** : pValCalculator(b, n=20, m=20) { ind <- 1:min(c(n,m)) prob <- (1-pnorm(b,sd=std*sqrt(ind))) prob1 <- sum((n-ind+1)*(m-ind+1)*prob) prob1 } inputData <-
2005 May 13
1
error in plot.lmList
Hello, in R-2.1.0 I'm trying to prodice trellis plots from an lmList object as described in the help for plot.lmList. I can generate the plots from the help, but on my own data plotting fails with an error message that I cannot interpret (please see below). Any hints are greatly appreciapted. kind regards, Arne > dim(d) [1] 575 4 > d[1:3,] Level_of_Expression SSPos1 SSPos19
2007 Jan 21
2
efficient code. how to reduce running time?
Hi, I am new to R. and even though I've made my code to run and do what it needs to . It is taking forever and I can't use it like this. I was wondering if you could help me find ways to fix the code to run faster. Here are my codes.. the data set is a bunch of 0s and 1s in a data.frame. What I am doing is this. I pick a column and make up a new column Y with values associated with that
2012 Jun 19
1
Possible bug when using encomptest
Hello R-Help, ----------------------------------------------------------------------------------------------------------------------------------------- Issues (there are 2): 1) Possible bug when using lmtest::encomptest() with a linear model created using nlme::lmList() 2) Possible modification to lmtest::encomptest() to fix confusing fail when models provided are, in fact, nested. I have
2008 Dec 13
2
Obtaining p-values for coefficients from LRM function (package Design) - plaintext
Sent this mail in rich text format before. Excuse me for this. ------------------------ Dear all, I'm using the lrm function from the package "Design", and I want to extract the p-values from the results of that function. Given an lrm object constructed as follows : fit <- lrm(Y~(X1+X2+X3+X4+X5+X6+X7)^2, data=dataset) I need the p-values for the coefficients printed by calling
2008 Dec 13
2
weird pasting of ".value" when list is returned
could someone explain why the name of FPVAL gets " .value" concatenated onto it when the code below is run and temp is returned. I've been trying to figure this out for too long. It doesn't matter when I put the FPVAL in the return statement. It happens regardless of whether it's first or last. Thanks. f.lmmultenhanced <- function(response, pred1, pred2) {