Displaying 20 results from an estimated 2000 matches similar to: "logical(0) response from lrm"
2010 Jun 09
2
combining expressions in mathplot
Is there a cleaner way of combining two expressions.
This example works and gives what I want
plot(1:10)
aa <- expression(alpha==.05)
bb <- expression(beta ==.80)
aabb <- expression(alpha==.05 ~ ", " ~ beta ==.80)
text(5, 10, aa)
text(5, 9, bb)
text(5, 8, aabb)
text(5,1, parse(text=paste(deparse(aa[[1]]), deparse(bb[[1]]), sep="~")))
text(5,2,
2010 Mar 18
6
Validating alignment of NTFS/VMDK/ZFS blocks
Good evening,
I understand that NTFS & VMDK do not relate to Solaris or ZFS, but I was wondering if anyone has any experience of checking the alignment of data blocks through that stack?
I have a VMware ESX 4.0 host using storage presented over NFS from ZFS filesystems (recordsize 4KB). Within virtual machine VMDK files, I have formatted NTFS filesystems, block size 4KB. Dedup is turned on.
2014 Nov 23
2
R string comparisons may vary with platform (plain text)
On 23/11/2014 09:39, peter dalgaard wrote:
>
>> On 23 Nov 2014, at 01:05 , Henrik Bengtsson <hb at biostat.ucsf.edu> wrote:
>>
>> On Sat, Nov 22, 2014 at 12:42 PM, Duncan Murdoch
>> <murdoch.duncan at gmail.com> wrote:
>>> On 22/11/2014, 2:59 PM, Stuart Ambler wrote:
>>>> A colleague?s R program behaved differently when I ran it, and we
2023 Jul 28
1
Joining a new Samba AD DC
on Fri Jul 28 14:30:33 2023 Rowland Penny via samba <samba at lists.samba.org> wrote:
> On 28/07/2023 19:04, Mark Foley via samba wrote:
> >
> > After checking with the previous run, these sysvolreset errors are the same as
> > before, so syncing the sysvol didn't make any different.
> >
> > You wrote: "It looks to me that you have more GPO's
2010 Sep 27
7
Regular expressions: offsets of groups
Dear list!
> gregexpr("a+(b+)", "abcdaabbc")
[[1]]
[1] 1 5
attr(,"match.length")
[1] 2 4
What I want is the offsets of the matches for the group (b+), i.e. 2
and 7, not the offsets of the complete matches. Is there a way in R
to get that?
I know about gsubgn and strapply, but they only give me the strings
matched by groups not their offsets.
I could write
2009 Aug 17
1
image() generates many border lines in pdf, not on screen (quartz) - R 2.9.1 GUI 1.28 Tiger build 32-bit (5444) - OS X 10.5.8
Dear all,
I have invested substantial amount of work in a complicated, yet on
screen perfect looking graph that uses image(). Unfortunately saving it
as pdf (or quartz.save at high resolution) all generate very disturbing
border lines around each small rectangle that image() has drawn. While
using Preview it helps to turn off antialiasing to make those faint
lines disappear on screen
2020 May 12
0
last_login_dict: Failed to write value: dict-server returned failure: sql dict: commit failed
Hello,
I get last_login_dict: Failed to write value: dict-server returned
failure: sql dict: commit failed randomly in the logs:
---
???????1 mailserver dovecot: imap(test-email-bb at exemple.com)
<NtiT9H2SFIVcuGID> [xxx.xxx.xxx.xxx]: Error: last_login_dict: Failed to
write value: dict-server returned failure: sql dict: commit failed:
INSERT, UPDATE command denied to user
2005 Jul 12
1
Design: predict.lrm does not recognise lrm.fit object
Hello
I'm using logistic regression from the Design library (lrm), then fastbw to
undertake a backward selection and create a reduced model, before trying to
make predictions against an independent set of data using predict.lrm with
the reduced model. I wouldn't normally use this method, but I'm
contrasting the results with an AIC/MMI approach. The script contains:
# Determine full
2004 Mar 22
2
Handling of NAs in functions lrm and robcov
Hi R-helpers
I have a dataframe DF (lets say with the variables, y, x1, x2, x3, ...,
clust) containing relatively many NAs.
When I fit an ordinal regression model with the function lrm from the
Design library:
model.lrm <- lrm(y ~ x1 + x2, data=DF, x=TRUE, y=TRUE)
it will by default delete missing values in the variables y, x1, x2.
Based on model.lrm, I want to apply the robust covariance
2017 Sep 14
0
Help understanding why glm and lrm.fit runs with my data, but lrm does not
> On Sep 14, 2017, at 12:30 AM, Bonnett, Laura <L.J.Bonnett at liverpool.ac.uk> wrote:
>
> Dear all,
>
> I am using the publically available GustoW dataset. The exact version I am using is available here: https://drive.google.com/open?id=0B4oZ2TQA0PAoUm85UzBFNjZ0Ulk
>
> I would like to produce a nomogram for 5 covariates - AGE, HYP, KILLIP, HRT and ANT. I have
2012 May 27
2
Unable to fit model using “lrm.fit”
Hi,
I am running a logistic regression model using lrm library and I get the
following error when I run the command:
mod1 <- lrm(death ~ factor(score), x=T, y=T, data = env1)
Unable to fit model using ?lrm.fit?
where score is a numeric variable from 0 to 6.
LRM executes fine for the following commands:
mod1 <- lrm(death ~ score, x=T, y=T, data = env1)
mod1<- lrm(death ~
2002 Apr 15
2
ssh -R limitations?
Hi there!
I've a couple of questions on -R feature:
Here is my situation:
PC_A has a private IP, ssh client and has a service I want to see from the
internet.
PC_B is a linux firewall (public IP) where there is an open port that
forwards all traffic to PC_C (ssh server on port 22) which is in PC_B LAN.
I want to create a tunnel from PC_A to PC_C to access a service on PC_A from
2017 Sep 14
1
Help understanding why glm and lrm.fit runs with my data, but lrm does not
Fixed 'maxiter' in the help file. Thanks.
Please give the original source of that dataset.
That dataset is a tiny sample of GUSTO-I and not large enough to fit this
model very reliably.
A nomogram using the full dataset (not publicly available to my knowledge)
is already available in http://biostat.mc.vanderbilt.edu/tmp/bbr.pdf
Use lrm, not lrm.fit for this. Adding maxit=20 will
2009 Aug 29
3
lrm in Design
Hello everybody,
I am trying to do a logistic regression model with lrm() from the design
package. I am comparing to groups with different medical outcome which can
either be "good" or "bad". In the help file it says that lrm codes al
responses to 0,1,2,3, etc. internally and does so in alphabetical order. I
would guess this means bad=0 and good=1.
My question: I am trying to
2006 Nov 14
1
Using lrm
Hi,
I have to build a logistic regression model on a data set that I have. I
have three input variables (x1, x2, x3) and one output variable (y).
The syntax of lrm function looks like this
lrm(formula, data, subset, na.action=na.delete, method="lrm.fit",
model=FALSE, x=FALSE, y=FALSE, linear.predictors=TRUE, se.fit=FALSE,
penalty=0, penalty.matrix, tol=1e-7,
2017 Sep 14
3
Help understanding why glm and lrm.fit runs with my data, but lrm does not
Dear all,
I am using the publically available GustoW dataset. The exact version I am using is available here: https://drive.google.com/open?id=0B4oZ2TQA0PAoUm85UzBFNjZ0Ulk
I would like to produce a nomogram for 5 covariates - AGE, HYP, KILLIP, HRT and ANT. I have successfully fitted a logistic regression model using the "glm" function as shown below.
library(rms)
gusto <-
2008 Oct 09
2
Singular information matrix in lrm.fit
Hi R helpers,
I'm fitting large number of single factor logistic regression models
as a way to immediatly discard factor which are insignificant.
Everything works fine expect that for some factors I get error message
"Singular information matrix in lrm.fit" which breaks whole execution
loop... how to make LRM not to throw this error and simply skip
factors with singularity
2008 Mar 03
1
using 'lrm' for logistic regression
Hi R,
I am getting this error while trying to use 'lrm' function with nine
independent variables:
> res =
lrm(y1994~WC08301+WC08376+WC08316+WC08311+WC01001+WC08221+WC08106+WC0810
1+WC08231,data=y)
singular information matrix in lrm.fit (rank= 8 ). Offending
variable(s):
WC08101 WC08221
Error in j:(j + params[i] - 1) : NA/NaN argument
Now, if I take choose only four
2009 Aug 21
1
Possible bug with lrm.fit in Design Library
Hi,
I've come across a strange error when using the lrm.fit function and the
subsequent predict function.
The model is created very quickly and can be verified by printing it on
the console. Everything looks good. (In fact, the performance measures
are rather nice.)
Then, I want to use the model to predict some values. I get the
following error: "fit was not created by a Design
2009 Oct 25
1
Getting AIC from lrm in Design package
I am trying to obtain the AICc after performing logistic regression
using the Design package. For simplicity, I'll talk about the AIC. I
tried building a model with lrm, and then calculating the AIC as
follows:
likelihood.ratio <-
unname(lrm(succeeded~var1+var2,data=scenario,x=T,y=T)$stats["Model
L.R."]) #Model likelihood ratio???
model.params <- 2 #Num params in my model
AIC