similar to: Tapply.

Displaying 20 results from an estimated 10000 matches similar to: "Tapply."

2013 Mar 14
1
ggplot2 problem
Hello all! I have a problem with ggplot2 library. I want to do an heat map and the y variables are the year months. If I use the following code, he y values are in alphabetical order, but I want it in month order. The code is: library(reshape) library(ggplot2) library(scales) p <- ggplot(data.m, aes(variable, Month)) + geom_tile(aes(fill = value),
2017 Sep 15
7
require help
hello to all. I am working on macroeconomic data series of India, which in a yearly basis. I am unable to convert my data frame into time series. kindly help me. also using zoo and xts packages. but they take only monthly observations. 'data.frame': 30 obs. of 4 variables: $ year: int 1980 1981 1982 1983 1984 1985 1986 1987 1988 1989 ... $ cnsm: num 174 175 175 172 173 ... $ incm:
2009 Mar 11
2
Question about datatypes/plotting issue
Hi, I am trying to plot the Case-Shiller index found at: http://www2.standardandpoors.com/spf/pdf/index/CSHomePrice_History_022445.xls The way I'm importing it into R is as follows: library(gdata) W <- read.xls("http://www2.standardandpoors.com/spf/pdf/index/CSHomePrice_History_022445.xls ", header=TRUE) attach(W) To give you and idea of what the data looks like: >
2009 Jan 14
1
publication statistics from Web of Science
Dear list, This is a bit of an off-topic question, but I'm hoping to get some advice from more experienced people. I've used the website "Web of Science" to manually collect publication counts responding to several keywords as a function of date, since the 1960s. http://apps.isiknowledge.com/RAMore.do?product=UA&search_mode=&SID=P1g9lFJp9 at
2013 Nov 26
7
[PATCH RESEND 0/1] libxl: introduce an option for disabling the non-O_DIRECT
I think I posted this patch before, but it looks like it was in December 2012 (!). 1/1 libxl: introduce an option for disabling the non-O_DIRECT workaround Ideally it would go into 4.4, at least. Provided the corresponding qemu part has gone into qemu-xen, which I think it has. Can anyone confirm ?
2008 Nov 04
1
perform Kruskal-Wallis test without using the built-in command in R
Hi, again i am stuck in my presentation, and i have never learn R before in my life but need this to be done, so please help me out for a favour: http://www.nabble.com/file/p20333155/kew.dat kew.dat run this in R and these comes up: Month Year Rain 1 Jan 1900 74.400000 2 Feb 1900 80.500000 3 Mar 1900 23.600000 4 Apr 1900 23.600000 5 May 1900 25.100000 6
2004 Mar 09
1
vector extraction
Hello, I could need some help on this one: >From the data.frame "Test.dataset2" below (TSCS data for 151 "countries.to.map" for "year" 1973-95; each "country.to.map" is described by a unique code), I would like to extract a vector "color" that for each "country.to.map" takes on the value of "dv" (a categorical variable with
2007 Oct 03
1
Reimplement order somehow
Hello, I have a script in R language that makes sorting using the order() method of R language. What I need is to reimplement this method in any other language (PHP, Perl, Python, Java maybe). First I tried to reimplement it in php, here is some numbers that i need to sort: 1,2,3,4,5,6,7,8,9,10,300,231,11,12,0,1 R language: n = c(1,2,3,4,5,6,7,8,9,10,300,231,11,12,0,1) n [1] 1 2 3 4 5
2013 Mar 12
5
extract values
Hello all! I have a problem to extract values greater that for example 1820. I try this code: x[x[,1]>1820,]->x1 Please help me! Thank you! The data structure is: structure(c(2.576, 1.728, 3.434, 2.187, 1.928, 1.886, 1.2425, 1.23, 1.075, 1.1785, 1.186, 1.165, 1.732, 1.517, 1.4095, 1.074, 1.618, 1.677, 1.845, 1.594, 1.6655, 1.1605, 1.425, 1.099, 1.007, 1.1795, 1.3855, 1.4065, 1.138, 1.514,
2017 Sep 16
2
require help
You can just use the same code that I provided before but now use your dataset. Like this df <- read.csv(file="data2.csv",header=TRUE) dates <- as.Date(paste(df$year,"-01-01",sep="")) myXts <- xts(df,order.by=dates) head(myXts) #The last command "head(myXts)" shows you the first few rows of the xts object year cnsm incm wlth
2003 Apr 15
2
troubles with displaying legend on the plot
Dear colleagues, I have troubles while trying to display legend on the plot. I have data.frame fr > fr year M1 M2 1 1979 58.85198 56.77303 2 1980 57.59725 55.93749 3 1981 57.32133 55.55232 4 1982 54.69320 53.10566 5 1983 56.58973 55.03811 6 1984 58.81363 56.97641 7 1985 58.35583 56.82091 8 1986 60.41842 58.45457 9 1987
2017 Sep 16
0
require help
> On 15 Sep 2017, at 11:38, yadav neog <yadavneog at gmail.com> wrote: > > hello to all. I am working on macroeconomic data series of India, which in > a yearly basis. I am unable to convert my data frame into time series. > kindly help me. > also using zoo and xts packages. but they take only monthly observations. > > 'data.frame': 30 obs. of 4 variables:
2010 Jan 11
3
interpolation
Dear R-users, I have a complex line by xy-values (ordered by z). And I would like to get interpolated y-values on the positions of x = 0:600. How do I get the correct points? x=c(790,790,790,790,790,786,783,778,778,766,763,761,761,761,715,628,521,350,160,134,134,129,108,101,93,111,161,249,288,243,139,45,7)
2017 Sep 16
0
require help
oky.. thank you very much to all of you On Sat, Sep 16, 2017 at 2:06 PM, Eric Berger <ericjberger at gmail.com> wrote: > You can just use the same code that I provided before but now use your > dataset. Like this > > df <- read.csv(file="data2.csv",header=TRUE) > dates <- as.Date(paste(df$year,"-01-01",sep="")) > myXts <-
2017 Sep 15
0
require help
> On 15 Sep 2017, at 12:38, yadav neog <yadavneog at gmail.com> wrote: > > hello to all. I am working on macroeconomic data series of India, which in > a yearly basis. I am unable to convert my data frame into time series. Do you really need to convert your data to time series/xts/zoo? I don?t know you try what kind of an analysis but perhaps you don?t have to. > kindly
2015 Jul 01
5
additional leap second
hi, Index: leap_second/src/library/base/R/zdatetime.R =================================================================== --- leap_second/src/library/base/R/zdatetime.R (revision 68608) +++ leap_second/src/library/base/R/zdatetime.R (working copy) @@ -24,7 +24,8 @@ "1979-12-31", "1981-6-30", "1982-6-30", "1983-6-30",
2013 Mar 13
2
merge datas
Hello all! I have a problem with R. I try to merge data like this: structure(c(2.1785, 1.868, 2.1855, 2.5175, 2.025, 2.435, 1.809, 1.628, 1.327, 1.3485, 1.4335, 2.052, 2.2465, 2.151, 1.7945, 1.79, 1.6055, 1.616, 1.633, 1.665, 2.002, 2.152, 1.736, 1.7985, 1.9155, 1.7135, 1.548, 1.568, 1.713, 2.079, 1.875, 2.12, 2.072, 1.906, 1.4645, 1.3025, 1.407, 1.5445, 1.437, 1.463, 1.5235, 1.609, 1.738, 1.478,
2009 Feb 07
2
Time Series Graphics - "cannot plot more than 10 series"
Hi Experts, I would like to present time series data in meaningful way in building some graphics. I've tried: (1) plot(ts(mbaye3)) and (2) plot(ts(mbaye3), start=1990) But I always get this error-message: Fehler [error] in plotts(x = x, y = y, plot.type = plot.type, xy.labels = xy.labels, : cannot plot more than 10 series as "multiple" my data: mbaye3
2013 Feb 27
2
matrix multiplication
Hi, Try this: #mat1 is the data res<-do.call(cbind,lapply(seq_len(nrow(mat1)),function(i) {new1<-do.call(rbind,lapply(seq_len(nrow(mat1[-i,])),function(j) {x1<-rbind(mat1[i,],mat1[j,]); x2<-(abs(x1[1,1]-x1[2,1])*abs(x1[1,5]-x1[2,5]))+(abs(x1[1,2]-x1[2,2])*abs(x1[1,6]-x1[2,6]))+(abs(x1[1,3]-x1[2,3])*abs(x1[1,7]-x1[2,7]))+(abs(x1[1,4]-x1[2,4])*abs(x1[1,8]-x1[2,8]))}));new1}))
2013 Jan 03
2
Sas by function in R
Hello, It's an alternative to use SAS by function in R? I want to plot d histograms by plot.from example bellow: Thank you! plot d 1 1 16.3 2 1 25.0 3 1 57.8 4 1 17.0 5 2 10.8 13 2 96.4 17 3 76.0 18 3 32.0 19 3 11.0 20 3 11.0 24 3 106.0 25 3 12.5 21 4 19.3 22 4 12.0 26 4 15.0 27 5 99.3 32 7 11.0 36