similar to: table command

Hi all, how can I divide two tables of the same dimension so that all names are preserved, ie do not become NA? I have "tab1" and "tab2", each having names in the first column. I want "tab3" with the same names and values "tab1/tab2". Thanks, Serguei

Hi, I am trying to execute the following SQL statement using two data frames: tab1, tab2 : Two Tables Select tab1.*, tab2.*, tab1.tobiiTime - tab2.ruiTime as timeDiff, IFNULL(n-m, -9999999) as alwaysIncrement FROM tab1 LEFT OUTER JOIN tab2 On tab1.data1 - tab2.mouseX = 0 And tab1.data2 - tab2.mouseY = 0 I am trying to do the following in R:- *#Getting error here:* data

Hi, I wanted the DICE coefficient (similarity measure for binary variables) to be calculated in R and found that the "igraph" package has the option of "similarity.dice" to do this. But, for this command, the input object should be an igraph object. But, I have a dataframe of columns containing 1's and 0's. Can I convert this dataframe into an igraph object, so that

HI Guy''s TAB1 and TAB2 have some radio button, checkbox and dropdown menu. When TAB1 is selected, I have to switch to TAB2 and then back to TAB1 to refresh the loaded content. How to make TAB1 refresh loaded content when click on its tab? *code is something like that* <ul class="tabs"> <li><a *href="#tab1"*>Gallery</a></li>

Hi R, This is a cross tabulation question. Suppose that, > d=read.table("clipboard",header=F) > d V1 V2 V3 A One Apple A One Cake A One Cake B One Apple B One Apple B One Apple > table(d$V2,d$V3) Apple Cake One 4 2 But, I don't want the count to be like the above. Here, it is counting the

Hi, Suppose a=matrix(1:9,3,3) > a [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 Now, > class(a[1:2,]) [1] "matrix" > class(a[1:3,]) [1] "matrix" > class(a[,1:2]) [1] "matrix" > class(a[,1:3]) [1] "matrix" But, > class(a[1,]) [1] "integer" > class(a[,1]) [1]

Hi R, A quick question: How do we find the number of words in a string? Example: C="Have a nice day" And the number of words should be 4. any built in function or?... Thanks, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

Hi R, If x=c(1,3,5) y=c(2,4,6) I need a vector which is c(1,2,3,4,5,6) from x and y. How do I do it? I mean the best way.... Thanks, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, I need to generate 50 random numbers (preferably poisson), such that their sum is equal to 100. How do I do this? Thank you, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, This is a very trivial one.... C=0.1 I want to check whether my value of C is between 0 and 1 exclusively.... I don't want to use (C>0 & C<1). And I can't use a single statement like (0<C<1). Is there a between function? Or how do we specify from 0 to 1? Does %in% help me? Many Thanks, Shubha This e-mail may contain confidential and/or

Hi Experts, I want to see my object as below: 'C:\Program Files\R\R-2.4.0\bin\Rgui.exe' So I use the paste command. None of the below is working. Could anyone help me on this? > paste("'C:\Program Files\R\R-2.4.0\bin\Rgui.exe'") [1] "'C:Program FilesRR-2.4.0\binRgui.exe'" > paste("'C:","\","Program

Dear R experts, Might be very simple question to ask but would be insightful. As the same story of nested "for loops". following is the code that I am using to get the autocorrelation function of the sample data. I have tried to get rid of for loops but since I am touching R after such a long time that I need to practice more but I need help to revive my skills. I know that apply() or

Hi R, Let, x=1:80 I want to sum up first 8 elements of x, then again next 8 elements of x, then again another 8 elements..... So, my new vector should look like: c(36,100,164,228,292,356,420,484,548,612) I used: aggregate(x,list(rep(1:10,each=8)),sum)[-1] or rowsum(x,group=rep(1:10,each=8)) But without grouping, can I achieve the required? Any other ways of doing

Hi R users, Is there a function in R, which does some calculation only for the month end in a daily data?... In other words, is there a command in R, equivalent to "last." function in SAS? BR, Shubha [[alternative HTML version deleted]]

Hi R, I have the data frames, data1, data2....data50. Now I want to put all of these in a single list. But, >list(data1, data2,.........data50) is very big to write. How do I then do it? Thanks, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, I have a list, l=list(list(c(1,2),c(4,5),c(6,7)),list(c(11,22,33),c(44,55,66))) > l [[1]] [[1]][[1]] [1] 1 2 [[1]][[2]] [1] 4 5 [[1]][[3]] [1] 6 7 [[2]] [[2]][[1]] [1] 11 22 33 [[2]][[2]] [1] 44 55 66 How do I know the dimensions of this list?... In other words, how many sub-lists, sub-sub-lists etc...are there in l? How do I know this?

Hi R, I was experimenting with the CA package for correspondence analysis. data(author) ca(author) plot(ca(author)) How can I get the values used by the plot for the two axis for biplot? In other words, how will I be able to obtain the scores in the dimensions (which are obtained by PCA) of the graphs? Thanks. Thanks and Regards, Shubha This e-mail may contain

---------- Forwarded message ---------- From: Shubha Vishwanath Karanth <shubhak at ambaresearch.com> Date: Nov 24, 2006 7:54 PM Subject: Dates Conversion/write.foreign To: Shubha Karanth <shubhakaranth at gmail.com>, Shubha Vishwanath Karanth <shubhak at ambaresearch.com> Hi R experts, I need an urgent help... I have an a dataframe caled idat. Below i give a snapshot

Hi R, I have a 100th order equation for which I need to solve the value for x. Is there a package to do this? For example my equation is: (x^100 )- (2*x^99) +(10*x^50)+.............. +(6*x ) = 4000 I have only one unknown value and that is x. How do I solve for this? BR, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore *

Hi R, I have certain checkings, which gives FALSE, but actually it is true. Why does this happen? Note that the equations that I am checking below are not even the case of recurring decimals... > 1.4^2 == 1.96 [1] FALSE > 1.2^3==1.728 [1] FALSE Thanks in advance, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo *