similar to: Table to List Transformation Scenario

I would like to include this in a package. The S3 methods on R CMD check says * checking S3 generic/method consistency ... WARNING window: function(x, ...) window.chron: function(data, day1, hour1, day2, hour2, ...) See section 'Generic functions and methods' of the 'Writing R Extensions' manual. I have looked and can not figure it out. This function is for convience. What

Dear all, Just wondering if someone could help me out converting my code from a for() loop into a foreach() loop or using one of the apply() function. I have a very large dataset and so I'm hoping to make use of a parallel backend to speed up the processing time. I'm having trouble getting selecting three variables in the dataset to use in the foreach() loops. My for() loop code is:

What is R's equivalent to a C-like #include to incorporate external files. I have a 2k line function that is generated and need to include it at runtime but not manage it as a package (as it changes hourly.) Any ideas? [[alternative HTML version deleted]]

Hi, I am trying to edit a data frame such that the string in the first line is appended onto the beginning of each element in the subsequent rows. The data looks like this: > df V1 V2 V3 V4 1 DPA1* DPA1* DPB1* DPB1* 2 0103 0104 0401 0601 3 0103 0103 0301 0402 . . and what I want is this: >dfnew V1 V2 V3 V4 1 DPA1* DPA1* DPB1* DPB1* 2 DPA1*0103

How can I get the results of lm() into a list so I can loop through the results? e.g. myResults[1] <- lm(...) myResults[2] <- lm(...) myResults[3] <- lm(...) ... myResults[15] <- lm(...) myResults[16] <- lm(...) so far every attempt I've tried doesn't work throwing a "number of items to replace is not a multiple of replacement length" error or simply not

thanks to your guys help I am closer to solving my problem but I have some small problem. So let's say I start with >data number day hour 1 17 10 2 17 11 3 17 6 4 18 4 5 18 10 6 19 8 7 19 8 I want to split to odd days, which I am able to do, I call this object frames, which looks like: > frames $`1` c1 day1 hour1 1 1 17 10 2 2 17 11 3 3 17 6 $`2` c1 day1

Hi, i'm very new to R, so sorry for what i'm sure is a very basic question. I'm producing a boxplot with the data below: df3<-data.frame( x=c(10,11,115,12,13,14,16,17,18,21,22,23,24,26,27,28,29,3,30,32,33,34,35,4,4 1,45,5,50,52,56,58,6,67,6738,68,7,8,9), fq=c(8,11,1,2,4,4,2,2,6,3,4,2,2,1,1,1,4,51,3,1,1,1,1,35,1,1,19,2,1,1,1,14,1, 1,1,10,13,5),

Dear R friends, I am currently working with time series data, and I have a table(as data frame) that has looks like this (TransitDate are in format = "%e-%B-%Y") : TransitDate Transits CargoTons 1985-04-01 100 2500 1985-05-01 135 4500 1985-06-01 120 1750 1985-07-01 100 3750 1985-08-01 200

Hello to all, I am entirely new to Ruby and also to Ruby on Rails. As far as I understand, Rails builds its model according to the a specified table structuree in in the database. However, most of my applications, are for the most part (except some backend CRUD stuff) not database centric. They do a lot of calculation for the user. So, how can I create a model, when no database is needed,

Hi Paul, #First I set up some sample data since I don't have a copy of your data dtOrig <- as.Date( c("1985-04-01","1985-07-01","1985-12-01","1986-04-01")) dfOrig <- data.frame( TransitDate=dtOrig, Transits=c(100,100,500,325), CargoTons=c(1000,1080,3785,4200) ) #Generate the complete set of dates as a data frame dfDates<- data.frame(

Hello, R-helpers. I have a data frame below called df. I want to add a variable c, based on the following logic: if df$a < 5 then the first two times this condition is met place a 1 in c, the next two times this condition is met place a 2 in c and when the condition is not met let c equal df$b. The result would look like, dfnew, shown below. a <- rep(c(3,5,7), 4) b <- rep(c(NA,1,2),

I’m using a Windows development component which uses vorbis.dll, ogg.dll, vorbisenc.dll for encoding an Ogg Vorbis file. It's all working well except for one user occasionally has a 1 hour file appear as 2 hours and it plays at half speed. It is being converted from stereo to mono before feeding the encoder with a channels=1 configuration. Here is an example file which will be available for

Could someone please point me to the proper url to register for a fwd acount and get a fwd number. I couldn't find it at www.freeworlddialup.com or fwd.pulver.com Thanks, -Galt -- "They that would give up essential liberty for temporary safety deserve neither liberty nor safety." Benjamin Franklin

Hello All, Would like to be able to convert a matrix to a dataframe without losing an assigned dimname. Here is an example that should illustrate what I'm talking about. tableData <- state.x77[c(7, 38, 20, 46), c(7, 1, 8)] names(dimnames(tableData)) <- c("State", "") tableData State Frost Population Area Connecticut 139 3100 4862

Dear Eric, Hope you are doing great. I also tried the following: #First I created the complete date sequence TransitDateFrame <- data.frame(TransitDate=seq(as.Date(dataset1[1,1]), as.Date(dataset1[nrow(dataset1),1]), by = "month")) #Then I did the merging dataset1NEW <- merge(TransitDateFrame, dataset1, by="TransitDate", all.x=TRUE) Now it has, as expected the

Hi, I am a beginner in R and have only read a few chapters in the R book, I was not able to find a solution for this simple problem. I have an empty data frame: a=data.frame(name="test") which I would like to extend in a for-loop (with data extracted from a database). Ideally I would like to extend the data frame like this: a["new_1"] = 1:10 a["new_1"] = 1:12

I am reading regressors from an excel file (I have no control over the file) and some of the element names have spaces: i.e. "Small Bank Aquired" but I have found that lm(SourceData ~ . - "Small Bank Aquired", mcReg) doesn't work (mcReg = modelCurrentRegressors) As they are toggles I have ran them through factor() to be treated propertly as 0 or 1 but due to the fact I

Why are my coefficients getting appended with a 1? It borks a match I do later against the original list that doesn't have the random 1 added to the end. > linearModel[[1]] Call: lm(formula = modelSource ~ +UNITBUILD + UNITDB + ITBUILD + ITDB + UATBUILD + UATDB + HOGANCODE + RCF + ReleaseST1 + ReleaseST2 + ReleaseBLA + Small.Bank.Acquisitions + HLY.NewYear + HLY.MLK + HLY.PRES +

Dear all, for each A == 3 in 'df' I would like to change the variables B and K. My result should be the whole df and not the subset (A==3)... df <- data.frame(A = c(1,1,3,2,2,3,3), B = c(2,1,1,2,7,8,7), K = c("a.1", "d.2", "f.3", "a.1", "k.4", "f.9",

While I have found a few 802.11 cordless SIP phones, It's not ovious how they select which network to associate with. What I'm looking for is a 802.11 SIP phone that will auto detect the closest wireless network(s), offer a list to select from, then auto configure itself using dhcp. If you think about it this could be quite handy when strolling around in populated areas. Could someone