similar to: "too many arguments" error

Hi all! I am desperately trying to figure out the solution to this error, but nothing as of yet is working. As noted in an earlier post I am using GenABEL. In an attempt to read in the phenotype file, in the format .dat, R keeps giving me the error "more columns than column names" I have tried to read in the data without the headers; I have also tried to trim the data to remove any

What's the difference between: <em>emphasis</em> and <i>italicized</i> and <strong>strong</strong> and <b>bold</b> It seems to subtle for my browsers. The only "difference" I've been able to find is that according to the O'Reilly book <strong> and <emphasis> are semantic tags, while <b> and <i>

Hi: I'm trying to plot dates on the x-axis of a code, but the legend is not being displayed. I receive the following error: Error in match.arg(x, c("bottomright", "bottom", "bottomleft", "left", : 'arg' should be one of bottomright, bottom, bottomleft, left, topleft, top, topright, right, center In addition: Warning message: longer

Hi I have a scatterplot of points with pch=1 and a single point with pch=3, lwd=3. It has a high line width to attract attention to it. The following script plot(rnorm(10),rnorm(10),col="black") points(rnorm(10),rnorm(10),col="red") points(0,0,pch=3,lwd=3) if(TRUE){ legend("bottomleft",c("a","b","Truth"),pch=c(1,1,3),col=c

Hi, all: Is there an automatic smart legend for R? Since my R code is running in a row, which will produce a bunch of R plots in a single run, some of the produced plots are really "ridiculous". Because my legend is fixed to "topleft", sometimes, which occludes the key parts of the figure/plots, but most of the time, the legend works just fine. I'm wondering is there a

The following code demonstrates an annoyance with plot.lm(): library(DAAGxtras) x11(width=3.75, height=4) nihills.lm <- lm(log(time) ~ log(dist) + log(climb), data = nihills) plot(nihills.lm, which=5) OR try the following xy <- data.frame(x=c(3,1:5), y=c(-2, 1:5)) plot(lm(y ~ x, data=xy), which=5) The "Cook's distance" text overplots the label for the point with the

According to http://wiki.winehq.org/WineReleasePlan the new release date for Wine 1.0 is set to June 17. However the Firefox 3.0 release date is also set to June 17. http://developer.mozilla.org/devnews/index.php/2008/06/11/coming-tuesday-june-17th-firefox-3/ Their release is planned to be high profile and they even plan to set a Guinness world record for downloads in a single day!

useRs, Here is some R-ready data for my question to follow. Of course this data is small snippet from a much larger dataset that is about a decade long. Q<-read.table(textConnection("2002 3 28 15 77.38815 2002 3 28 30 77.09505 2002 3 28 45 76.80196 2002 3 28 60 76.50887 2002 3 28 75 76.50887 2002 3 28 90 76.50887 2002 3 28 105

(A) I received the following bounced message when I tried to submit a bug from http://bugs.r-project.org/cgi-bin/R (B) The bug report itself is at the bottom. Thanks, Chris (A) -------- Original Message -------- Subject: Undelivered Mail Returned to Sender Date: Wed, 6 Aug 2008 17:08:02 +0200 (CEST) From: MAILER-DAEMON at pubhealth.ku.dk (Mail Delivery System) To: candrews at buffalo.edu

On Tue, Mar 5, 2019 at 9:54 PM Richard White <w at rwhite.no> wrote: > Hi Gabriel, > > The point is that it *visually* displays as NA, but is.na() still > responds as FALSE. > > When I (and I am sure many people) see an NA, we then use is.na(). If we > see Inf displayed, we then use is.infinite(). With as.Date() this breaks > down. > > I'm not arguing that

Full_Name: John Maindonald Version: R-2.8.1 OS: MacOS X 10.5.6 Submission from: (NULL) (203.173.3.75) The following code demonstrates an annoyance with plot.lm(): library(DAAGxtras) x11(width=3.75, height=4) nihills.lm <- lm(log(time) ~ log(dist) + log(climb), data = nihills) plot(nihills.lm, which=5) OR try the following xy <- data.frame(x=c(3,1:5), y=c(-2, 1:5)) plot(lm(y ~ x,

Hi all, Small problem in generating the line charts. Question: Legend for the first graph is coming wrong., for second graph correctly. Please fix the legend postion at the down of graph. Plesae give me the solution. Thank you Devarayalu Orange1 <- structure(list(REFID = c(7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9), ARM = c(1, 1, 1, 1, 2, 2, 2, 2, 1, 1, 1, 1, 2, 2, 2,

Hi Gabriel, The point is that it *visually* displays as NA, but is.na() still responds as FALSE. When I (and I am sure many people) see an NA, we then use is.na(). If we see Inf displayed, we then use is.infinite(). With as.Date() this breaks down. I'm not arguing that as.Date(Inf) should be coerced to NA. I'm arguing that as.Date(Inf) should be *visually* displayed as Inf (i.e. the

Dear R developers, I needed to align the title of legend for some of my plots. If there is interest to include this into base R, bellow are the examples and the relevent diffs. Regards, Gregor x <- 1:10 y1 <- 1.5 * x y2 <- 2.0 * x y <- cbind(y1, y2) source(file=url("http://gregor.gorjanc.googlepages.com/legend.R")) matplot(x, y, type="l", lty=c(1, 2)) ##

Hi, there is a function to plot survival curves: library(survival) plot.KM <- function(survival, x, x_cut.off, main='', label='') { plot(survfit(survival ~ I(x >= x_cut.off)), main=main) legend('bottomleft', c(expression(label >= x_cut.off),expression(label < x_cut.off))) } Now, I need to determine as the argument what appears in the legend. I want

jelks said: > What a dumb idea. You should > lean your head to the right about 20 degrees, > to simulate the text. that should be "stage-right", right?, so your listener will hear it right? -bowerbird -------------- next part -------------- An HTML attachment was scrubbed... URL:

How do I move the legend from default position (right and within the plot)?to the "bottomleft" of the plot? ? interaction.plot(YEAR, ID?GROWTH, legend=TRUE, col = 2:7,xlab="Year", ?????? ylim=c(0,2), ylab="Growth",leg.bty = "o") Peter Maclean Department of Economics UDSM

Hi all: I'm trying to plot two time series created in Rmetrics and label the x-axis with dates. I tried the following: dates <- as.Date(seriesPositions(x.agg)) r <- as.Date(range(dates)) ts.plot(x.agg@Data[,c(1,5)],gpars=list(ylab="Volume", lty=c(1:2),xaxt="n",main="Plot of Volume")) axis.Date(1, at=seq(r[1], r[2], length.out=10),

Dear all, I am doing library(survival) fit <- coxph(Surv(futime,fustat) ~ rx, ovarian) plot(survfit(fit,newdata=ovarian),col=c(1,2)) legend("bottomleft", legend=c("rx = 0", "rx = 1"), lty=c(1,2),col=c(1,2)) Is this correct to compare these two groups? Is the 0.31 the p-value that the median f two groups are equal Why lty does not work here? Many thanks

Dear R community It is possible to adjust the legend in combined ggplots using ggarrange with be positions top, bottom, left and right. My question: Is there a function to change the position of the legend to topright or bottomleft? Right and top etc are in the middle of the axis. Kind regards Sibylle