similar to: package "wmtsa": how to set up the Tolerance vector to detect time series peaks blindly

Here is another occurrence of wmTSA internal error. My time series is a short breathing cycle (2425-Cyle_9.txt). Since wmtsa functions that extract extrema seem to expect longer series than I have, I tried the folowing two tricks: 1) I prolong the 1-cycle series on both ends through duplicating the first value (on the left end( and the last value on the right end as any ties as the 1-cycle

I have attached the signal that causes the error message in this email subject. Only columns 1 and 3 have to be considered. It is the work trajectory of a molecule migrating between two equilibrium conformations. The curve has 2 peaks, as shown in its plot. But I keep missing the 2nd one. Here is my short script: library(wmtsa) setwd("C:/Documents and Settings/Monville/Alanine

Full_Name: Maura Monville Version: 2.8 OS: Mac OS/X 10.5 Submission from: (NULL) (87.4.122.234) Here is the code that causes wavCWTPeaks error aats <- create.signalSeries(aa, pos=list(from=0.0, by=0.033)) aa.cwt <- wavCWT(aats) x11 (width=10,height=12) plot (aats,main=paste(insig," Cycle: ",j,sep="")) aa.maxtree <- wavCWTTree (aa.cwt,

aa <- (structure(list(X.0.85 = c(-1.02, -1.17, -1.29, -1.39, -1.46, -1.5, -1.52, -1.5, -1.46, -1.39, -1.3, -1.19, -1.07, -0.93, -0.79, -0.65, -0.5, -0.36, -0.22, -0.08, 0.05, 0.18, 0.3, 0.41, 0.52, 0.62, 0.72, 0.81, 0.89, 0.98, 1.05, 1.13, 1.19, 1.25, 1.29, 1.31, 1.31, 1.29, 1.24, 1.16, 1.06, 0.93, 0.77, 0.58, 0.38, 0.16, -0.07, -0.31, -0.89, -1.05, -1.19, -1.31, -1.41, -1.47, -1.51, -1.51,

I cannot understand the following error printed out when I try to get the extrema of my time series. I would appreciate some suggestion as I really cannot interpret the error. I might not be using a proper set of parameters in calling such functions. I am learning by doing ... > aa.peak <- wavCWTPeaks (aa.tree) Error in `row.names<-.data.frame`(`*tmp*`, value = c("1",

I keep getting the following error when I look for minima in the series: > aa.peak <- wavCWTPeaks (aa.tree) Error in `row.names<-.data.frame`(`*tmp*`, value = c("1", "0")) : invalid 'row.names' length How can I work it around ? Thank you. Regards, Maura Alice Messenger ;-) chatti anche con gli amici di Windows Live Messenger e tutti i telefonini TIM!

Dear R family I have a question as to how to get an answer I want to derive with the outcome from R-package, "wmtsa". My concern is that I want to decide equivalent degrees of freedom (EDOF) based on the following outcome. library(wmtsa) W <- wavMODWT(X, wavelet="s8") z1 <- wavEDOF(W) print(z1) #Intentionally, I do not assign n.levels and specify SDF. The following is

I can send data along, but it is too large for the list: I am using wmtsa and the function wavCWT I would like to use the range.scale to only evaluate a subset of frequencies. deltat of the time series that I am trying to analyze is 1 d = wavCWT(RM202.ts, range.scale = c(96, 2688)) and I get the error message Error in wavCWT(RM202.ts, scale.range = c(96, 2688) : Minimum scale must be greater

I am always fascinating by good programming techniques. R contains a lot of very good examples I have been learning from. Since I am using some functions from package "wmtsa", I though I could borrow the elegant example, in the documentation of function "wavBestBasis" to compute the entropy from the Wavelet Transform coefficients. In the following I have pasted the excerpt,

Hi folks, I'm attempting to use the EMD package to analyze some neuroimaging data (timeseries with 64 channels sampled across 1 million time points within each of 20 people). I found that processing a single channel of data using EMD::emd() took about 8 hours. Exploration using Rprof() suggested that most of the compute time was spent in EMD::extrema(). Looking at the code for EMD:extrema(),

The following error occurs every now and then by calling a function of wmTSA package: Error in `row.names<-.data.frame`(`*tmp*`, value = c("1", "0")) : invalid 'row.names' length I would greatly appreciate some guidelines about how to catch such an error upon its occurrence and have it handled by my own routine rather than letting R stop the currently run

Is there a way to write and analysis to disk and then reconstruct the whole thing back into an object. wavCWT() #wmtsa package I am running out of memory on my computer and I was wondering if there was a way to iterate through this process (as it is an iterative process anyway- it just stores the whole thing to memory). Or is there a way to set the scale that I want to look at so that wavCWT

Dear List, R ist somtimes a bit frustrating... I ran the example from http://bm2.genes.nig.ac.jp/RGM2/R_current/library/QRMlib/man/plotMultiTS.html and I get an error. Has someone an explanation for this? Thanks a lot, Steve CODE: library(R.utils) library(tseries) library(wmtsa) library(waveslim) library(brainwaver) library(timeSeries) library(QRMlib) > ?plotMultiTS >

There is a series of data contains time in fixed step and energy varying with time, how to test its periodicity?In R, it seems there is no direct tools since I have search the R manual with periodic and I have not found any related topic. Thanks a lot

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Hi all, as I am trying to move slowly from just "working" to "good" code, I'd like to ask if there's a smarter way than using a for-loop in tasks like the example below. I need to obtain the extrema of the cumulated sum of a detrended time series. The following code is currently used, please have a look at the comments for my questions and remarks: system.time({ X

https://bugzilla.mindrot.org/show_bug.cgi?id=2516 Bug ID: 2516 Summary: ssh client shouldn't trust the DNS AD bit blindly Product: Portable OpenSSH Version: 7.1p1 Hardware: All OS: All Status: NEW Severity: security Priority: P5 Component: ssh Assignee: unassigned-bugs at

Full_Name: Karsten Krug Version: 2.4.0 OS: Open Suse 10.0, Windows XP Submission from: (NULL) (88.134.13.50) I found a problem in the 'optimise' function for one dimensional optimisation. Example 1: Try to find a maximum of the function below with the use of 'optimise' in the interval [0,0.5]. The function follows a parabola and has two local maxima located at the margins of

http://r.789695.n4.nabble.com/file/n3312061/x_and_y_values.txt x_and_y_values.txt I have the absorbance values form HPLC Chromatogram. I need to find the peaks in datapoints and area under each peak. I am not sure how how to find the peaks, I tried couple of libraries and peak function but they return me a list of values which when computed from area turns out to be huge nnumbers. In the

Hello, Listers I'm trying to run blloean logit model with R. My code is: > library(boolean) > library(foreign) > pr <- read.dta ("prcore1.dta") > bp <- boolprep ("(a&b)|c", "cwt", a="O1", b="t", c="DM2 > + ah + md + con + n3 + rel + slo + pyrs > + sp1 + sp2 + spl3") > answer <- boolean (bp, link =