similar to: Converting date format

Fellow R users, I am stumped on what would seem to be something fairly simple. I have a dataframe that has a variable named 'WEEK' that takes the numbers 1:26 (26 week time-period) with each number repeated five times consecutively (once for each weekday, Monday through Friday). Ex. 111112222233333.....2626262626. I would like to randomly extract two weekdays per five day week for

Hello R Users, How to convert decimal date to date as YYYY.mm.dd.hr.min.sec For example, I have decimal date in one column , and want to convert and write it in equivalent date(YYYY.mm.dd.hr.min.sec) in another next six columns. 1979.000000 1979.020833 1979.041667 1979.062500 Is it possible in R ? Kindly help, Regards, Yogesh -- Dr. Yogesh K. Tiwari, Scientist, Indian Institute

R experts, Hello, I am trying to sample a vector 1:40 without replacement such that no element in the new vector is within 7 units of either of its immediate neighbors. This is part of a larger program I am working on. The following code works well about 65 % of the time (14/40). The problem I encounter happens when the last element remaining to be sampled from the vector STRATA is within 7

R community, How could I extract the week number from a date vector (in class Date) such that week numbering (week 1...2...) begins (May 01) and ends (October 31) on the same specific dates each year? Thank you, Mike

----Original Message----- From: Martyn Plummer [mailto:plummerm at iarc.fr] Sent: Thursday, January 12, 2017 3:36 AM To: Weiner, Michael <weinerm at ccf.org>; r-sig-fedora at r-project.org Subject: Re: [R-sig-Fedora] rgl >One possibility is that you have the 32-bit version of mesa-libGL-devel installed. This will provide the headers but not the 64-bit l>ibrary which is what you need

Hey folks, I have a difficult (at least for me) problem that I was hoping one of you may know how to solve. I want to assign a sequence to subsets of a variable in a data frame based on date. The variable is 'SITE1' and the date is a unique day (DD) and month (MM) combination. The sequence contains site numbers 101:104, and each day-month combination takes four site numbers from that

Hello, is there an elegant way, how I can convert each row of a data frame into distinct elements of a list? In essence, what I'm looking for is something like rows.to.lists <- function( df ) { ll <- NULL for( i in 1:nrow(df) ) ll <- append( ll, list(df[i,]) ) return (ll) } but more done more efficiently (the data frame may contain ten-thousands of rows). I thought about

R experts, I have been unable to get the following ifelse statement to work as desired when applied to my data frame. Example: DF$ANYEF <- with(DF,ifelse(PSOUGHT1=='ANY'|PSOUGHT2=='ANY'|PSOUGHT3=='ANY',PEFF,0)) ##### this statement will be replicated 16 times for 16 unique _EF variables ### Basically, I want each ANYEF for each row to equal the corresponding row

Hi, Does anyone know how to add minutes (up to 100 min) to a 24 hour time, to create a new 24 hour time? I can't seem to find any documentation or examples explaining how to do this. The variables of interest are 'ARRIVE','WAIT', and 'DEPART' in the attached partial dataframe. I want 'DEPART' to be the "sum" of 'ARRIVE' and 'WAIT' in

Does anyone have any experience retrieving latitutde and longitude for an address from the Google Maps API? I'd like to have an R script that submits a street address, city, state, and zip code and returns the coordinates. So far, I've been submitting the coordinates from another program, then loading the coordinates in R and merging them back into the data frame I want to use.

Dear R Helpers, I have imported an SPSS file that contains date data. The data appear in R in a numeric format, as follows: 10485849600 10477641600 10561104000 10562745600 etc. I'd be extremely grateful if someone could tell me how to make these numbers into comprehensible dates! Thanks, Jonathan Williams

Dear all, I have found the following (for me) incomprehensible behaviour of ISOdate (POSIXct): > ISOdate(1900,6,16) [1] "1900-06-15 14:00:00 Westeurop?ische Sommerzeit" > ISOdate(1950,6,16) [1] "1950-06-16 14:00:00 Westeurop?ische Sommerzeit" Note that in the first case I get the 15th of June back, not the 16th as I would have expected! This happened under R-1.7.1 on

Dear Members, Compliments of the Season!! Below is a part of a code I use for Fourier analysis of signals. The code handles data with the format 05 01 01 8628 (year, month, day and count) 05 01 02 8589 (year, month, day and count) The sample data is attached as 2005daily.txt. I would like to adapt the code to handle data of the form: 05 01 01 00 4009

Hello out there.... Again I have a problem and I stuck... How can I sort a vector of dates? For example I have the vector a<-ISOdate(2001, 1, 1) + 70*86400*runif(10) How can this vector be sorted chronological? And what's the function I should work with to handle these entries? (in sense of: which(a>2001-01-04) or somehting like that) Thank you for helping M.Kirschbaum

I have a Fedora linux 24 64bit workstation I am trying to install rgl on and I keep running into this error: trying URL 'https://cran.cnr.berkeley.edu/src/contrib/rgl_0.97.0.tar.gz' Content type 'application/x-gzip' length 2369444 bytes (2.3 MB) ================================================== downloaded 2.3 MB * installing *source* package 'rgl' ... ** package

Sure I'm missing something simple here, but I haven't been able to find a easy way to convert a pure numeric (# of seconds since the beginning of 1970) back into a POSIX* object. ex. > z<-as.POSIXct(Sys.time()) > z [1] "2002-05-01 10:33:56 Mountain Daylight Time" > x<-unclass(z) > x [1] 1020270836 Is there a simple way to transform x back into a POSIX*

Hi Ogbos, You can just use ISOdate. If you pass more values, it will process them: ISOdate(2018,01,22) [1] "2018-01-22 12:00:00 GMT" > ISOdate(2018,01,22,18,17) [1] "2018-01-22 18:17:00 GMT" Add something like: if(is.null(data$hour),data$hour<-12 then pass data$hour as it will default to the same value as if you hadn't passed it. Jim On Mon, Jan 22, 2018 at 6:01

Dear all, I used cph() function from Frank harrell's Design package to create a survival model, then used functions 'Function' and 'sascode' to generate prediction equation based on the saved survival model. But it failed. I included a stratified variable in the model. If I removed the stratification, they were working well. Does that mean that function 'Function'

Has anyone ever tried putting a circle around a letter or a number in a plot title? For instance, if I have a plot title "Scatterplot for Subject 24", I want to put a circle around 24 to distinguish that plot from the other 30 I've generated. Any tips or ideas beyond plotting a circle in the margin? Benjamin Benjamin Nutter | Biostatistician | Quantitative Health

-----Original Message----- From: Tom Callaway [mailto:tcallawa at redhat.com] Sent: Thursday, January 12, 2017 8:25 AM To: Weiner, Michael <weinerm at ccf.org>; r-sig-fedora at r-project.org Subject: Re: [R-sig-Fedora] rgl On 01/12/2017 08:01 AM, Weiner, Michael wrote: > I resolved this by reinstalling mesa-libGL (dnf reinstall libGL) seems /lib64/libGL.so.1.2.0 was missing off the