similar to: Decreasing Cumsum Function?

Dear all, I have a repository file (let's call it repo.txt) that contain two columns like this: # tag value AAA 0.2 AAT 0.3 AAC 0.02 AAG 0.02 ATA 0.3 ATT 0.7 Given another query vector > qr <- c("AAC", "ATT") I would like to find the corresponding value for each query above, yielding: 0.02 0.7 However, I want to avoid slurping whole repo.txt

Greetings R-ians: I know what doesn?t work but I don?t know why, nor how to remedy things. I have a character string containing "." which I want to replace with " " gsub(".", " ", file.label) replaces the every character with a blank. However gsub(".xls", " ", file.label) replaces ".xls" with a blank as expected. It appears

R-ians: After some effort I coerced my code to do what I want but my syntax is a kludge. Suggestions on more elegant syntax? par <- NIM.results$par do.call("Draw.NIM.POD.curve", list(par[1], par[2], par[3], par[4], par[5], a.hat.decision, .... et cetera ... It seems that I should be able to avoid defining the variable "par" and then specifying each of its elements,

Dear all, I have the following matrix: > str(mat) Named chr [1:32268] "yQAAA" "jQAAQ" "UQAAg" "FQAAw" "1QABA" ... - attr(*, "names")= chr [1:32268] "CAAAAAAAAA" "CAAAAAAAAC" "CAAAAAAAAG" "CAAAAAAAAT" ... I want to destroy the attribute yielding only this: > str(mat) Named chr [1:32268]

Greetings R-ians: Searching the Searchable Mail Archives I discovered that ctrl L will clear the Rgui screen, which is what I'd like to do from a print (or some similar) statement. Is there a mechanism to use the ctrl L clear-screen sequence in a script, or print statement? Thanks for your counsel. Charles Annis, P.E. Charles.Annis at StatisticalEngineering.com phone: 561-352-9699 eFax:?

Hi, With the following codes, I attempt to convert the data.frame into a matrix. However I notice that data.matrix function doesn't seem to work. __ BEGIN__ dat <- read.table("mydata", comment.char = "!" , na.strings = "null"); # Select n-genes by random sample # n = 1 nosamp <- 1 geneid <- sequence(nrow(dat)) geneid.samp <- sample(geneid,nosamp)

Greetings, R-ians: I would like to know which version or R was used to create a given package. I think I remember seeing that topic discussed recently but cannot find it among my notes. Can anyone tell me how to determine which version of R created a package? Thanks. Charles Annis, P.E. <mailto:Charles.Annis@StatisticalEngineering.com> Charles.Annis@StatisticalEngineering.com

Hi all, Suppose I have 2 matrices A and B. And I want to measure how good each of this matrix is. So I intend to compare A and B with another "gold standard" matrix X. Meaning the more similar a matrix to X the better it is. What is the common way in R to measure matrix similarity (ie. A vs X, and B vs X) ? - Gundala Viswanath Jakarta - Indonesia

Dear all, How can I remove the even number from the following vector > x [1] 4 5 6 8 17 20 21 22 23 25 26 31 35 36 38 40 41 42 43 [20] 44 50 74 75 82 84 89 90 91 95 96 97 100 101 102 118 119 121 122 [39] 123 135 136 157 158 yielding 5, 17, 21, 23, 25, ..... (keep odd number). - Gundala Viswanath Jakarta - Indonesia

Greetings, R-ians: I'm using R 2.3.1 on WindowsXP. I need to find the name of a file at the end of a sting that contains the path + file, with the problematic "\\" as separators. The string looks something like this: "C:\\Documents and Settings\\myName\\My Documents\\R Projects\\Project1\\file.name.csv" What I want is "file.name.csv" Currently I use the

Greetings, R-ians: I'm using R 2.3.1 on WindowsXP. I need to find the name of a file at the end of a sting that contains the path + file, with the problematic "\\" as separators. The string looks something like this: "C:\\Documents and Settings\\myName\\My Documents\\R Projects\\Project1\\file.name.csv" What I want is "file.name.csv" Currently I use the

Dear R Helpers: I am trying to annotate a plot. The following code snippet works, but it is kind of a kludge since it adds the partial derivative symbols after creating the plotmath frac(). Is there a more elegant way to write a partial derivative? dev.off() plot(NA, xlim=c(-3,3), ylim=c(0,1.6), xlab="", ylab="", tck=-0.015) text(1.6, 1, expression(paste("slope =

Hi, I have the following vector which is created from 3 distinct distribution (three components) of gamma: x=c(rgamma(30,shape=.2,scale=14),rgamma(30,shape=12,scale=10),rgamma(30,shape=5,scale=6)) I want to plot the density curve of X, in a way that it shows a distinct 3 curves that represent each component. How can I do that? I tried this but doesn't work: lines(density(x)) Please

Greetings R-wizards: For historical reasons I have filenames with the character "?" and have successfully used "\u00e2" in its place, with the hoped-for result on all my on-screen plots. However since R2.7.0 I have trouble with savePlot() when the file name includes that character as it does in this example: savePlot(paste("diagnostic ? vs a ", file.label,

Dear all, I have the following matrix. > dat A A A A A A A A A A [1,] 0 0 0 0 0 0 0 0 0 0 [2,] 0 0 0 0 0 0 0 0 0 1 [3,] 0 0 0 0 0 0 0 0 0 2 How can I change it into: [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [1,] 0 0 0 0 0 0 0 0 0 0 [2,] 0 0 0 0 0 0 0 0 0 1

Hi Dieter, Sorry my mistake. I wanted to convert them into Decimal (not Hexadecimal). Given this string, the desired answer follows: > ascii_str <- "ORQ>IK" 79 82 81 62 73 75 > ascii_str2 <- "FDC" 70 68 67 - Gundala Viswanath Jakarta - Indonesia On Mon, Dec 22, 2008 at 5:49 PM, Dieter Menne <dieter.menne at menne-biomed.de> wrote: > Gundala

Hi, I have the following (M x N) matrix, where M = 10 and N =2 What I intend to do is to group index of (M) based on this condition of "x_mn" , namely For each M, If x_m1 > x_m2, assign index of M to Group1 otherwise assign index of M into Group 2 > x [,1] [,2] [1,] 4.482909e-01 0.55170907 [2,] 9.479594e-01 0.05204063 [3,] 8.923553e-01 0.10764474

Hi, How can I extract the label only from a given data frame. Fore example from this data frame. > print(dataf) V1 V2 V3 V4 V5 V6 V7 V8 V9 11145 14.3 17.1 31.2 41.7 45.8 49.8 68.6 70.6 72.9 3545 10.2 15.6 20.9 23.2 31.4 31.7 36.2 48.4 51.9 8951 15.2 17.5 20.0 21.4 32.4

Greetings, Amigos: I have been trying without success to convert a character string, > repeated.measures.columns [1] "3,6,10" into c(3,6,10) for subsequent use. as.numeric(repeated.measures.columns) doesn't work (likely because of the commas) [1] NA Warning message: NAs introduced by coercion I've tried many things including strsplit(repeated.measures.columns, split =

Suppose I have two vectors of same dimensions: x <-c(0.49534,0.80796,0.93970,0.99998) count <-c(0,33,0,4) How can I group the vectors 'x' into two vectors: 1. Vector `grzero` that contain value in x with `count` value greater than 0 and 2. Vector `eqzero` with value in x with `count` value equal to zero. Yielding > print(grzero) > [1] 0.80796 0.99998