similar to: Accessing data in groups created with split() and other beginner questions

Hi All, I try to do a scatterplot for a bunch of variables. I plot a dependent variable against a bunch of independent variables: -- cut -- graphics::plot( v01_r01 ~ v08_01_up11, data = dataset, xlab = "Dependent", ylab = "Independent #1" ) -- cut -- It is tedious to repeat the statement for all independent variables. Found an alternative, i.e. : -- cut -- mu

Dear all, I am using the following code to write the plot to an eps format postscript(file="test.eps",horizontal=FALSE)

Good day all, I'm trying to plot a continuous line plot, which is followed by two forecast points eg. one forecast point is 12 months out, and another 24 months out from the last date of the line plot. In my attempts so far, the second plot (the forecast points) is scaled against a new axis scale, thus the two plots are not directly comparable (I need the forecast points to be scaled

HI, Dear R community, I have used the following codes this morning, but this afternoon, I got the following errors: > x <- seq(0,10, by=1) > y <- c(0.952, 0.947, 0.943, 0.941, 0.933, 0.932, 0.939, 0.932, 0.924, 0.918, 0.920) # missense > z <- c(0.068, 0.082, 0.080, 0.099, 0.108, 0.107, 0.101, 0.105, 0.118, 0.130, 0.132) # missense False Negative > p <- c(0.035, 0.036,

Hi, I have a model called Stock with a value called "strength." I wrote a simple method in the Stock.rb model file to update the value of "strength" for each record in the stocks table. I created a controller called fix_controller.rb. I don''t have access to the live system, so the idea is that an admin will go to http://url/fix and a script will run to check and

It''s been a few days since I posted my last two emails (of which, no one replied to) so I''ve gone ahead and coded a working slider class as well as a ''resizeable'' class that allows a user to drag and resize the element. I also linked these two together as I want to have slider behavior that can resize the resizeable element. The end result is both the

Hello, I am trying to alter the way in which lattice functions (specifically xyplot) print the axis labels when one uses the 'scales' parameter. I can obtain the effect I want by using scales=list(y=list(log=10, labels=expression(yvalues))) where yvalues are the values that would have been printed as the y-axis labels if the "labels" argument had not been present. To help

Thank you Jim, The code did assist me to get the what I needed. Also, I learnt that there are different types of dashes (en-dash/em-dash/hyphen) as explained on this site : http://www.punctuationmatters.com/hyphen-dash-n-dash-and-m-dash/ I achieved it by executing below command after going through this page on stackoverflow:

Hi Sunny, Try this: # notice that I have replaced the fancy hyphens with real hyphens end<-c("2001-","1992-","2013-","2013-","2013-","2013-", "1993-2007","2010-","2012-","1984-1992","1996-","2015-") splitends<-sapply(end,strsplit,"-") last_bit(x)

Hi, I have a char vector with year values. Some cells have single year value '2001-' and some have range like 1996-2007. I need to remove hyphen character '-' from all the values within the character vector named as 'end'. After removing the hyphen I need to get the last number from the cells where there are year range values i.e if the cell has range 1996-2007, the code

Hello everyone, I would like to create a "dynamic" array to keep storing number in it for (i in c(2:length(final))){ myarray <-final[i]-final[i-1] myarray2<-2*final[i] } At the end I would like to use myarray as the x values of an array and the myarray2 as the yvalues of the same array. I tried cbind but it didnot work. Could you please help me with that? Best

cumsum() seems to be what you need. This can probably be done more elegantly, but ... out <- aggregate(Q ~ wyr, data = Daily, which.max) tbl <- table(Daily$wyr) out$Q <- out$Q + cumsum(c(0,tbl[-length(tbl)])) out ## yields wyr Q 1 1990 4 2 1991 6 3 1992 9 4 1993 15 5 1994 18 I leave the matter of Julian dates to you or others. Cheers, Bert Bert Gunter "The trouble

Using the dataset below, I got close to what I'm after, but not quite all the way there. Any suggestions appreciated: Daily <- read.table(textConnection(" Date wyr Q 1911-04-01 1990 4.530695 1911-04-02 1990 4.700596 1911-04-03 1990 4.898814 1911-04-04 1990 5.097032 1911-04-05 1991 5.295250 1911-04-06 1991 6.569508 1911-04-07 1991 5.861587 1911-04-08 1991 5.153666

Hello, for my meta-analysis I try to test if two varainces are equal without using the raw scores. I have is the SD's, N's and the Means. I want to test the variances from dependent and independend samples. I assume I can use the var.test procedure for the independent samples, but what about the dependent samples ? Has anyone an idea how to realise this with R ? Thanks in advance

R-Help community, I understand that data.frames can hold elements of type double, string etc but NOT objects (such as a matrix etc). This is not convenient for me in the following situation. I have a function that takes 2 inputs and returns a vector: testfun <- function (x,y) seq(x,y,1) I have a data.frame defined as follows: testframe<-data.frame(xvalues=c(2,3),yvalues=c(4,5)) I would

Hi all, I am strugling with date formates and caliculating diferent operations like different between 2 dates and getting minimum in vector of dates that is i m working with dates in formate "6/22/1992 12:00:00 AM" and the vector is [1] 6/4/1992 12:00:00 AM 2/13/1992 12:00:00 AM 6/19/1992 12:00:00 AM [4] 2/11/1992 12:00:00 AM 6/22/1992 12:00:00 AM 10/3/1991

I have following object : > date2 [,1] [,2] [1,] "apr" "1992" [2,] "aug" "1992" [3,] "dec" "1992" [4,] "feb" "1992" [5,] "jan" "1992" [6,] "jul" "1992" [7,] "jun" "1992" [8,] "mar" "1992" [9,] "may"

Hi, I have the next procedure: t1<-data.frame(table(substr(names(subset(lasker[[1]], lasker[[1]] >= 4)), 1, 7))) t1[1:5,] Var1 Freq 1 1988-02 3 2 1988-03 1 3 1988-04 1 4 1988-05 2 5 1988-06 3 How to make a new list?, dataframe? having 189 elements in the 'lasker' list: > str(lasker[[1]]) 'table' int [, 1:1274] 1 1 3 2 1 5 4 1 1 4 ... -

The text below is a part of, some work I have to do, which is due in 2 days and I am strung up with a lot of other stuff, so I was hoping someone would take 5 mins and help me ?? Here is a part of my data.frame: year country1 country2 contig comlang pop1 gdp1 pop2 gdp2 rta dist avgflow 1 1992 AUS AUT 0 0 17.4950008 321708.281

Suppose I create an R program called myTest.R with only one line like the following: type <- as.integer(readline("input type (1: type1; 2: type2)? ")) Then I'd like to run myTest.R in batch mode by constructing an input file called answers.R with the following: source("myTest.R") 1 When I ran the following at the terminal: R CMD BATCH answer.R output.Rout it failed