similar to: modify the levels of a variable

Displaying 20 results from an estimated 20000 matches similar to: "modify the levels of a variable"

2010 Oct 11
3
help with simple but massive data transformation
I have data that looks like this: start end value 1 4 2 5 8 1 9 10 0 I want to transform the data so that it becomes: startend value 1 2 2 2 3 2 4 2 5 1 6 1 7 1 8 1 9 0 10 0 ---- I've
2010 Dec 07
4
Creating binary variable depending on strings of two dataframes
Hi, consider the following two dataframes: x1=c("232","3454","3455","342","13") x2=c("1","1","1","0","0") data1=data.frame(x1,x2) y1=c("232","232","3454","3454","3455","342","13","13","13","13")
2009 Nov 12
2
redundant factor levels after subsetting a dataset
#I have a data frame with a numeric and a character variable. x=c(1,2,3,2,0,2,-1,-2,-4) md=c(rep("Miller",3), rep("Richard",3),rep("Smith",3)) data1=data.frame(x,md) #I subset this data.frame in a way such that one level of the character variable does not appear in the new dataset. data2=data1[x>0,] data3=subset(data1,x>0) #However, when I check the levels
2023 Jun 11
1
Problem with filling dataframe's column
Dear Rui; Many thanks for your email. I used one of your codes, "data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works correctly for me. Actually I need to expand the codes so as to consider all "Levels" in the "Layer" column. There are more than hundred levels in the Layer column. If I use your provided code, I have to write it
2023 Jun 11
1
Problem with filling dataframe's column
?s 21:05 de 11/06/2023, javad bayat escreveu: > Dear R users; > I am trying to fill a column based on a specific value in another column of > a dataframe, but it seems there is a problem with the codes! > The "Layer" and the "LU" are two different columns of the dataframe. > How can I fix this? > Sincerely > > > for (i in 1:nrow(data2$Layer)){ >
2023 Jun 11
1
Problem with filling dataframe's column
?s 22:54 de 11/06/2023, javad bayat escreveu: > Dear Rui; > Many thanks for your email. I used one of your codes, > "data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works > correctly for me. > Actually I need to expand the codes so as to consider all "Levels" in the > "Layer" column. There are more than hundred
2011 Oct 07
2
Merge dataframes
Hello, I am having some problems to use the 'merge' function. I'm not sure if I got its working right. What I want to do is: 1) Suppose I have a dataframe like: height width 1 1.1 2.3 2 2.1 2.5 3 1.8 1.9 4 1.6 2.1 5 1.8 2.4 2) And I generate a second
2011 Jul 16
1
Fwd: construct boxplots from data with varying column widths
From: David Winsemius <dwinsemius at comcast.net> On Jul 16, 2011, at 12:15 PM, Rory Campbell-Lange wrote: > On 16/07/11, David Winsemius (dwinsemius at comcast.net) wrote: >> >> On Jul 16, 2011, at 11:19 AM, Rory Campbell-Lange wrote: >> >>> I'm an R beginner, and I would like to construct a set of boxplots >>> showing database function runtimes.
2023 Jun 11
2
Problem with filling dataframe's column
Dear R users; I am trying to fill a column based on a specific value in another column of a dataframe, but it seems there is a problem with the codes! The "Layer" and the "LU" are two different columns of the dataframe. How can I fix this? Sincerely for (i in 1:nrow(data2$Layer)){ if (data2$Layer == "Level 12") { data2$LU == "Park"
2009 May 24
2
Assigning variable names from one object to another object
Hello I have 2 datasets say Data1 and Data2 both are of different dimesions. Data1: 120 rows and 6 columns (Varname, Vartype, Labels, Description, ....) The column Varname has 120 rows which has variable names such id, age, gender,.....so on Data2: 12528 rows and 120 columns The column names in this case are V1, V2, ......... V120 (which are default names in R when we say head=F in read.csv)
2006 May 13
2
What does it mean to be "masked from data" when attaching? (Newbie question)
I have several data frames, each with six variables and several hundred cases broken out from a larger dataframe by eleven values of a factor called "Division". I have to perform the same analysis on each one. I would like to do it by creating a data frame called data2 eleven times, once with data corresponding to each value of the factor, and performing the same analysis on each of
2011 Jul 06
3
Reshape from long to wide format with date variable
Hi, I need to reshape my dataframe from a long format to a wide format. Unfortunately, I have a continuous date variable which gives me headaches. Consider the following example: > id=c("034","034","016","016","016","340","340") > date=as.Date(c("1997-09-28", "1997-10-06", "1997-11-04",
2010 Apr 25
3
Noobie question on aggregate tapply and by
I have a 43MB dataframe ( 5 variables) and I'm trying to summarize subsets of the data. I've RTFM ( not very clear) and looked at a variety of samples but cant seem to figure out how to make these functions work. A sample of what I want to do would be this: ids<-seq(1,50) years<-c(rep(5,10),rep(6,10),rep(7,10),rep(8,20))
2008 Aug 21
1
problem merging two data sets ( one with a header and one without)
I have two set of data, Data1 and Data2 . Data1 has a header and Data2 does not. I would like to merge the two data sets after removing some columns from data2 . I am having a problem merging so I had to write and read final data and specify the ?header=F? so the merge can be done by?V1?. Is there a way to avoid this step. The problem is when I do cbind the FinalData has different column names
2011 May 19
2
balanced panel data
I have a dataframe with many firm-year observations and many variables. Not all firms have information for all the years. I want another dataframe with only those firms that have information all years. This is, I want a balanced panel data, but with the maximum number of years. In my reprocucible example I want to keep firms 1,2 and 3 (period 2000 to 2004). I need your help to create a
2005 Jul 11
1
validation, calibration and Design
Hi R experts, I am trying to do a prognostic model validation study, using cancer survival data. There are 2 data sets - 1500 cases used to develop a nomogram, and another of 800 cases used as an independent validation cohort. I have validated the nomogram in the original data (easy with the Design tools), and then want to show that it also has good results with the independent data using 60
2004 Aug 10
2
intersect two files
Hi all; Im working with two datasets in R, say data1 and data2. Both datasets are composed of several rows and columns (dataframe) and some of the rows are identical in both datasets. Im wondering if there is any way to remove from one set, say data1, the rows that are identical in the other set, say data2, using R? Thanks for any hint in advance Christian
2010 May 28
1
Match 2 vectors
Hi, I have 2 dataframes of unequal length, and I would like to match a factor to them so that both dataframes will have the same number of rows. example: # create the 2 dataframes with unequal length data1 <- data.frame(letters, 1:26)[-c(5,10,19:21),] data2 <- data.frame(letters, 1:26)[-c(6,9,15:18),] data2a <- match(data1[,1], data2[,1]) data2b <- data2[data2a,] When I match
2009 Nov 13
2
why the same values cannot be judged to be the same in R
Hi Rusers, I found sometimes that the same values cannot be judged to be the same in R. Anybody knows the probelm? I think i ignored some minor detail. Thanks. Here is the example. ############ data1<-matrix(data=c(1,1.2,1.3,"3/23/2004",1,1.5,2.3,"3/22/2004",2,0.2,3.3,"4/23/2004",3,1.5,1.3,"5/22/2004"),nrow=4,ncol=4,byrow=TRUE)
2010 Mar 24
3
How to use the paste function to create an already used variable
Hi there, I have the following problem Four data frames exist: data1 data2 data3 data4 Now I want to write a loop and temporarily store the data1, data2, data3, data4 in a variable called data. I tried the following... for (i in 1:4) { Data <- paste("data",i,sep="") ... .. } but it doesn't function. I think the problem is the definition of the mode of the pasted