similar to: function to create multiple matrices

Displaying 20 results from an estimated 200 matches similar to: "function to create multiple matrices"

2010 Mar 16
1
nested looping functions and dataframes
Hey All, So, I am confused how exactly to use nesting loop functions in R to spit out data frames. I've managed to create a working function for my data set that generates a data frame for a given set of Year i and Location j; but how would I do it for all Years and Locations? Here is my working function: test<-function(i,j){ a<-x[which(x$Year==i & x$Location==j),]
2010 May 04
2
R for web browser
Hi Everyone, Does anyone know of any projects for running an interactive R session within a web browser? I'm looking for something similar to the one on the Ruby website (http://tryruby.org), except for R. Thanks for your responses in advance! Lanna ----- Lanna Jin lannajin at gmail.com 510-898-8525 -- View this message in context:
2010 May 04
7
How to replace all <NA> values in a data.frame with another ( not 0) value
I need to replace <NA> occurrences in multiple columns in a data.frame with "000/000" how do I achieve this? Thanks Nevil Amos
2010 May 03
8
Delete rows with duplicate field...
as a r noob i am having another problem: i have a big dataframe where each row corresponds to one entry and each column is a field... for instance, i have the column ID and time and many more... Id like to get a dataframe where all IDs are just included once (some users with that ID might have several entries but Id like to kepp only one).. when i use unique I only get a list of the levels (or
2009 Nov 06
1
using xyplot to plot frequencies
Hi all, First off, thank you for the overwhelming response last time. I'm still trying to figure out the syntax of R to plot some distributions of some frequencies. I've managed to plot histograms from the data, but I would like to clean it up using xyplot from library(lattice). Unfortunately I cannot find a solution to my problem. Given a dataframe "all2", with numerical
2009 Nov 05
3
performing operations on a dataframe
Hey all, I feel like the solution to this problem should be relatively simple, but for some reason I can't find answers or come up with my own solution. Given the dataframe: (SpA and SpB not important, want to look at distribution of cooccurance for each year) Year SpA SpB Coocc 2000 0 2000 2 2000 1 2001 8 2001 2 2001 0 2001 0 2002 1 2002 2 How can I apply different functions to
2011 Nov 07
2
adjusting levelplot color scale to data
Hi guys, I have a matrix with values varying from approximately -0.7 to 0.33 that I want to create a heatmap/levelplot with. When I execute the levelplot function for my matrix, I end up getting colors that are adjusted to the max and min rather than around 0. In other words, ideally I would like to have a color ramp that goes from red (negative number), to white (0), to blue (positive);
2012 Mar 29
1
Retrieving matrix column and row names by index value
Hi all, So let's say I have a matrix, mdat and I only know the index number. How do I retrieve the column and row names? For example, > mdat <- matrix(c(1,2,3, 11,12,13), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("row1", "row2"), c("C.1", "C.2", "C.3"))) > mdat[4] [1] 12 >
2010 Apr 30
3
short question about data frame manipulation
Dear group, I am losing my mind with a simple question. Sorry if obvious, but I maybe start to be confused after days and days of reading documentations. Df : df <- structure(list(a = 1:3, b = 4:6, c = structure(c(1L, 1L, 1L), class = "factor", .Label = "w")), .Names = c("a", "b", "c"), row.names = c(NA, -3L), class =
2010 Sep 03
1
How to use lm() output for systemfit() 'Seemingly unrelated regression'
I am having problem using output of lm() function for further analysing using systemfit package. Basicaly, the problem s following - I generate several formulas using lm() > fo1 <- lm(r98[,2] ~ f98[,1] + f98[,2] + ... + f98[,43]) > fo2 <- lm(r98[,1] ~ f98[,1] + f98[,2] + ... + f98[,43]) and than I want to estimate a general model using package systemfit. > fitsur <-
2010 Jun 15
2
[LLVMdev] Question on X86 backend
Hi Micah, > In X86InstrInfo.td for Call Instructions, it mentions that Uses for > argument registers are added manually. Can someone point me to the > location where they are added as the comment doesn't reference a > where or how? the register uses are added by the function X86TargetLowering::LowerCall() during the DAG Lowering phase. This is the relevant code segment: // Add
2011 Jun 07
3
Logistic Regression
I am working on my thesis in which i have couple of independent variables that are categorical in nature and the depndent variable is dichotomus. Initially I run univariate analysis and added the variables with significant p-values (p<0.25) in my full model. I have three confusions. Firstly, I am looking for confounding variables by using formula "(crude beta-cofficient - adjusted
2009 Oct 26
1
zeros keep dropping
Hello All! I am trying to plot the frequency of species coocurrance. If given a data set similar like this...(V1="species A", V2="species B", V3="frequency of cooccurance") > data V1 V2 V3 1 A B 0 2 A C 2 3 A D 5 4 B C 0 5 B D 1 6 C D 0 > data1<-as.data.frame(lapply(data,function(x)(rep(x,data$V3)))) > as.data.frame(data1[-1]) >
2010 Feb 18
1
Graphics Question
Hello All, I'm having some issues controlling graphics in R. I was wondering if anyone may help me tackle this problem: Given a data frame "X" with variables "Year", "Factor" (w/ n groups), and "Freq" How do I create a single graphic with the following plots aligned in a vertical stack? 1. box plot in the fashion Freq~Year|Factor 2. box plot
2014 Jan 19
2
PCI Passthrough
I'm trying to pass-through my VGA card to a guest session. I found: http://www.linux-kvm.org/page/How_to_assign_devices_with_VT-d_in_KVM - which is very frustrating because there's no date on the documentation. I suspect it's old. It does clearly say that you must have VT-d support for pci pass-through. It then goes on to say "Some work towards allowing this ["software
2016 Apr 19
5
Interquartile Range
That didn't work Jim! Thanks anyway On Mon, Apr 18, 2016 at 9:02 PM, Jim Lemon <drjimlemon at gmail.com> wrote: > Hi Michael, > At a guess, try this: > > iqr<-function(x) { > return(paste(round(quantile(x,0.25),0),round(quantile(x,0.75),0),sep="-") > } > > .col3_Range=iqr(datat$tenure) > > Jim > > > > On Tue, Apr 19, 2016 at
2016 Apr 19
2
Interquartile Range
Hi, I am trying to show an interquartile range while grouping values using the function ddply(). So my function call now is like groupedAll <- ddply(data ,~groupColumn ,summarise ,col1_mean=mean(col1) ,col2_mode=Mode(col2) #Function I wrote for getting the mode shown below
2010 May 05
0
R-help Digest, Vol 87, Issue 5
Unsubscribe -----Original Message----- From: r-help-request at r-project.org Date: Wed, 05 May 2010 12:00:09 To: <r-help at r-project.org> Subject: R-help Digest, Vol 87, Issue 5 Send R-help mailing list submissions to r-help at r-project.org To subscribe or unsubscribe via the World Wide Web, visit https://stat.ethz.ch/mailman/listinfo/r-help or, via email, send a message with subject
2011 Oct 13
1
Legend symbols (line, points) in one column.
Dear R users: I want to have in the same column both symbols, line and points, one for a data, and the other for the model. How can I do that? Or is there other better form to show both data and model in the same graphic? I need to make the difference on time of the same subject (repeated measurements on time) Problem example: ###########################################################
2016 Apr 19
0
Interquartile Range
Hi Michael, At a guess, try this: iqr<-function(x) { return(paste(round(quantile(x,0.25),0),round(quantile(x,0.75),0),sep="-") } .col3_Range=iqr(datat$tenure) Jim On Tue, Apr 19, 2016 at 11:15 AM, Michael Artz <michaeleartz at gmail.com> wrote: > Hi, > I am trying to show an interquartile range while grouping values using > the function ddply(). So my function