Displaying 20 results from an estimated 7000 matches similar to: "Loop"
2018 Feb 25
2
include
HI Jim and all,
I want to put one more condition. Include col2 and col3 if they are not
in col1.
Here is the data
mydat <- read.table(textConnection("Col1 Col2 col3
K2 X1 NA
Z1 K1 K2
Z2 NA NA
Z3 X1 NA
Z4 Y1 W1"),header = TRUE,stringsAsFactors=FALSE)
The desired out put would be
Col1 Col2 col3
1 X1 0 0
2 K1 0 0
3 Y1 0 0
4 W1 0 0
6 K2 X1
2018 Feb 25
0
include
Hi Val,
My fault - I assumed that the NA would be first in the result produced
by "unique":
mydat <- read.table(textConnection("Col1 Col2 col3
Z1 K1 K2
Z2 NA NA
Z3 X1 NA
Z4 Y1 W1"),header = TRUE,stringsAsFactors=FALSE)
val23<-unique(unlist(mydat[,c("Col2","col3")]))
napos<-which(is.na(val23))
preval<-data.frame(Col1=val23[-napos],
2018 Feb 25
3
include
Thank you Jim,
I read the data as you suggested but I could not find K1 in col1.
rbind(preval,mydat) Col1 Col2 col3
1 <NA> <NA> <NA>
2 X1 <NA> <NA>
3 Y1 <NA> <NA>
4 K2 <NA> <NA>
5 W1 <NA> <NA>
6 Z1 K1 K2
7 Z2 <NA> <NA>
8 Z3 X1 <NA>
9 Z4 Y1 W1
On Sat, Feb 24, 2018 at 6:18 PM, Jim
2018 Feb 25
0
include
Jim has been exceedingly patient (and may well continue to be so), but this smells like "failure to launch". At what point will you start showing your (failed) attempts at solving your own problems so we can help you work on your specific weaknesses and become self-sufficient?
--
Sent from my phone. Please excuse my brevity.
On February 25, 2018 7:55:55 AM PST, Val <valkremk at
2018 Feb 25
2
include
Sorry , I hit the send key accidentally here is my complete message.
Thank you Jim and all, I got it.
I have one more question on the original question
What does this "[-1] " do?
preval<-data.frame(Col1=unique(unlist(mydat[,c("Col2","col3")]))[-1],
Col2=NA,col3=NA)
mydat <- read.table(textConnection("Col1 Col2 col3
Z1 K1 K2
Z2
2018 Feb 25
0
include
hi Val,
Your problem seems to be that the data are read in as a factor. The
simplest way I can think of to get around this is:
mydat <- read.table(textConnection("Col1 Col2 col3
Z1 K1 K2
Z2 NA NA
Z3 X1 NA
Z4 Y1 W1"),header = TRUE,stringsAsFactors=FALSE)
preval<-data.frame(Col1=unique(unlist(mydat[,c("Col2","col3")]))[-1],
Col2=NA,col3=NA)
rbind(preval,mydat)
2018 Feb 24
0
include
Thank you Jim and all, I got it.
I have one more question on the original question
What does this "[-1] " do?
preval<-data.frame(Col1=unique(unlist(mydat[,c("Col2","col3")]))[-1],
Col2=NA,col3=NA)
mydat <- read.table(textConnection("Col1 Col2 col3
Z1 K1 K2
Z2 NA NA
Z3 X1 NA
Z4 Y1 W1"),header = TRUE)
2008 Jun 24
2
persp plot
I have a set of data in the form
x1, y1, z1
x1, y2, z2
...
x1, yN, zN
x2, y1, z(N+1)
x2, y2, z(N+2)
...
x2, yN, z(2N)
...and so on...
xM, yN, val(M*N)
I have been trying to figure out how to get R to use this data in a
persp plot. So far the only thing that I can figure out to do is to
break the data file into three different files. The first file
contains the x-coordinate data:
x1
x2
2004 Feb 05
1
Multilevel in R
Hello,
I have difficulties to deal with multilevel model. My dataset is composed
of 10910 observations, 1237 plants nested within 17 stations. The data set is not
balanced. Response variable is binary and repeated.
I tried to fit this model
model<- glmmPQL( y ~ z1.lon*lun + z2.lat*lun + z1.lon*lar + z2.lat*lar + z1.lon*sca + z2.lat*sca +z1.lon*eta + z2.lat*eta,
random = ~ lun + lar + sca
2018 Feb 24
3
include
On 24/02/2018 1:53 PM, William Dunlap via R-help wrote:
> x1 = rbind(unique(preval),mydat)
> x2 <- x1[is.na(x1)] <- 0
> x2 # gives 0
>
> Why introduce the 'x2'? x1[...] <- 0 alters x1 in place and I think that
> altered x1 is what you want.
>
> You asked why x2 was zero. The value of the expression
> f(a) <- b
> and assignments
2013 Oct 18
1
crr question in library(cmprsk)
Hi all
I do not understand why I am getting the following error message. Can
anybody help me with this? Thanks in advance.
install.packages("cmprsk")
library(cmprsk)
result1 <-crr(ftime, fstatus, cov1, failcode=1, cencode=0 )
one.pout1 = predict(result1,cov1,X=cbind(1,one.z1,one.z2))
predict.crr(result1,cov1,X=cbind(1,one.z1,one.z2))
Error: could not find function
2009 Mar 20
2
plotting two variables with a third used for color
I have a problem where I have two columns of data that I can simply plot using:
plot(wV[0:15,3],wY[0:15,3]).
This produces my desired plot.
Now, say I have a third variable that I would like to introduce and use that variable to set different colors in the plot
In this case, say I wanted values greater than 0 to be "blue" and values less than 0 to be "red"
Basically, my
2007 Jul 16
2
Error while fitting Partial Proportional Odds model using vglm
Dear R developers:
I am trying to fit a PPO model using vglm from the library VGAM, and get an
error while executing the code. Here is the data, code, and error:
Data: first row is the column names. a = age, and 1,2,3, 4 and 5 are
condition grades.
a 1 2 3 4 5
1 1 0 0 0 0
2 84 2 7 10 2
3 16 0 6 6 2
4 13 0 3 4 0
5 0 0 0 1 0
Library(VGAM)
2012 Mar 14
1
Questing on fitting Baseline category Logit model
Dear all,
I am facing some problem with how to fit a "Baseline category Logit
model" with R. Basically I am considering famous "Alligator" data as
discussed by Agresti. This data can also be found here:
https://onlinecourses.science.psu.edu/stat504/node/174
(there is also an accompanying R file, however the underlying R code
could not load the data properly!!!)
Below are
2010 Aug 29
3
Three-dimensional contingency table
Hi,
I am trying to assemble a three-way contingency table examining the presence/absence of mussels, water depth (Depth1 and Depth 2) and water velocity (Flow vs. No Flow). I have written the following code listed below; however, when run the glm I get the following message, "Error in model.frame.default(formula = Count ~ MP + wd + wv, drop.unused.levels = TRUE) : variable lengths differ
2007 Jan 06
2
Using VGAM's vglm function for ordinal logistic regression
R-Experts:
I am using the vglm function of the VGAM library to perform proportional
odds ordinal logistic regression. The issue that I would like help with
concerns the format in which the response variable must be provided for
this function to work correctly. Consider the following example:
------
library(VGAM)
library(MASS)
attach(pneumo)
pneumo # Inspect the format of the original dataset
2012 Apr 03
4
grouping
Hi all,
Assume that I have the following 10 data points.
x=c( 46, 125 , 36 ,193, 209, 78, 66, 242 , 297 , 45)
sort x and get the following
y= (36 , 45 , 46, 66, 78, 125,193, 209, 242, 297)
I want to group the sorted data point (y) into equal number of
observation per group. In this case there will be three groups. The first
two groups will have three observation and the third will
2012 Aug 10
1
Solving binary integer optimization problem
Hi,
I am new to R for solving optimization problems, I have set of communication
channels with limited capacity with two types of costs, fixed and variable
cost. Each channel has expected gain for a single communication.
I want to determine optimal number of communications for each channel
maximizing ROI)return on investment) with overall budget as constraint.60000
is the budget allocated.
2006 Jul 08
2
String mathematical function to R-function
hello
I make a subroutine that give-me a (mathematical)
function in string format.
I would like transform this string into function ( R
function ).
thanks for any tips.
cleber
#e.g.
fun_String = "-100*x1 + 0*x2 + 100*x3"
fun <- function(x1,x2,x3){
return(
############
evaluation( fun_String )
############
)
True String mathematical function :-( :-(
> nomes
[1]
2003 Apr 04
3
trellis.graphic in for-loop
Hi list,
I am unsuccessfully trying to produce a serious of trellis barcharts from
within a for-loop. The barcharts work outside the loop. What am I missing?
Example attached.
Thanks Herry
#XXXXXXXXXXXXXXXXXXXXXX
trellis.device(bg="white")
trellis.par.get("fontsize")->fontsize
fontsize$default<-16
trellis.par.set("fontsize",fontsize)