Displaying 20 results from an estimated 6000 matches similar to: "Generating variable from 2 others in dataframe"
2009 May 09
4
Generating a "conditional time" variable
Hi everyone,
Please forgive me if my question is simple and my code terrible, I'm new to
R. I am not looking for a ready-made answer, but I would really appreciate
it if someone could share conceptual hints for programming, or point me
toward an R function/package that could speed up my processing time.
Thanks a lot for your help!
##
My dataframe includes the variables 'year',
2006 Nov 22
3
dataframe manipulation
Hi,
Having a dataframe 'l1' (dput output is below):
>dim(l1)
1274 2
>l1[1:12,]
Var1 Freq
1 1988-01-13 1
2 1988-01-16 1
3 1988-01-20 3
4 1988-01-25 2
5 1988-01-30 1
6 1988-02-01 5
7 1988-02-08 4
8 1988-02-14 1
9 1988-02-16 1
10 1988-02-18 4
11 1988-02-24 2
12 1988-03-04 1
I want to extract the times
2006 Mar 29
9
Ftp upload shaping 2 ISP\'s problems....
I would lilke to shape upload ftp bandwidth in a dual ISP setup
[shorewall show connections]
tcp 6 431215 ESTABLISHED src=192.168.2.89 dst=83.xxx.xxx.23 sport=1487 dport=21 src=83.xxx.xxx.23 dst=10.0.11.2 sport=21 dport=1487 [ASSURED] use=2 mark=1
[tcdevices]
#INTERFACE IN-BANDWITH OUT-BANDWIDTH
$EIF 970kbit 245kbit
$LIF 970kbit 245kbit
2010 May 18
3
About option U in Dial Ast version 1.6.2
Has any one used this?
U(x[^arg[^...]]):
x - Name of the subroutine to execute via Gosub
arg - Arguments for the Gosub routine
Execute via Gosub the routine <x> for the *called* channel before
connecting to the calling channel. Arguments can be specified to
the Gosub
using '^' as a delimiter. The Gosub routine can set the variable ${GO
2006 Nov 23
1
how to loop this?
Hi,
I have the next procedure:
t1<-data.frame(table(substr(names(subset(lasker[[1]], lasker[[1]] >=
4)), 1, 7)))
t1[1:5,]
Var1 Freq
1 1988-02 3
2 1988-03 1
3 1988-04 1
4 1988-05 2
5 1988-06 3
How to make a new list?, dataframe? having 189 elements in the 'lasker'
list:
> str(lasker[[1]])
'table' int [, 1:1274] 1 1 3 2 1 5 4 1 1 4 ...
-
2006 Nov 26
1
adding elemens to a list
Hi,
I have a list of 20 elements, each of them of variable length and with a
structure like this:
lasker[[1]][1:10,]
Var1 Freq
1 1988-02 3
2 1988-03 1
3 1988-04 1
4 1988-05 2
5 1988-06 3
6 1988-07 1
7 1988-08 1
8 1988-09 1
9 1989-03 1
10 1989-04 1
How do I can insert in this list:
1988-01 0
1988-10 0
1988-11 0
1988-12 0
1989-01 0
2003 Apr 06
5
Odd and Even
Hi,
I'm trying to create a function, jim(p) which varies
depending on whether the value of p is odd or even. I
was trying to use th eIf function, but i cant work out
a formula to work out if p is odd or even.
Thanks,
Dave
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For a better Internet experience
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2007 Dec 19
3
plot cummulative sum from calendar time
I have the following list of observations of calendar time:
[1] 03-Nov-1997 09-Oct-1991 27-Aug-1992 01-Jul-1994 19-Jan-1990 12-Nov-1993
[7] 08-Oct-1993 10-Nov-1982 08-Dec-1986 23-Dec-1987 02-Aug-1995 20-Oct-1998
[13] 29-Apr-1991 16-Mar-1994 20-May-1991 28-Dec-1987 14-Jul-1999 27-Nov-1998
[19] 09-Sep-1999 26-Aug-1999 20-Jun-1997 05-May-1995 26-Mar-1998 15-Aug-1994
[25] 24-Jun-1996 02-Oct-1996
2013 Mar 14
1
ggplot2 problem
Hello all!
I have a problem with ggplot2 library. I want to do an heat map and the y
variables are the year months. If I use the following code, he y values are
in alphabetical order, but I want it in month order.
The code is:
library(reshape)
library(ggplot2)
library(scales)
p <- ggplot(data.m, aes(variable, Month)) + geom_tile(aes(fill = value),
2009 Jan 14
1
publication statistics from Web of Science
Dear list,
This is a bit of an off-topic question, but I'm hoping to get some
advice from more experienced people. I've used the website "Web of
Science" to manually collect publication counts responding to several
keywords as a function of date, since the 1960s.
http://apps.isiknowledge.com/RAMore.do?product=UA&search_mode=&SID=P1g9lFJp9 at
2009 Oct 07
1
Formatting outputs:(chronological object)
Hello everyone,
I have a data generated in a way similar to the following
library(chron);library(zoo)
date<- seq(as.Date("1990-01-01"),, as.Date("2000-12-31"), by = 1)
obs<- zoo(rnorm(length(date), mean = 10, sd = 2.5), order.by = date)
monthly<- function(date) as.Date(as.yearmon(Date))
result<- data.frame ( Date = obs = aggregate(obs, monthly, sum))
Now,
I want
2008 Mar 30
2
convert weekly time series data to monthly
I have weekly time series data with year, month, day, and price variables.
The input data set for the weekly series takes the following form:
Year month day price
1990 8 20 119.1
1990 8 27 124.5
1990 9 3 124.2
1990 9 10 125.2
1990 9 17 126.6
1990 9 24 127.2
1990 10 1 132.1
1990 10 8 133.3
1990 10 15 133.9
1990 10 22 134.5
1990 10 29 133.9
.. ... ... ...
... ... .... ....
2008 3 3 313.7
2008
2008 Jun 18
4
inverse cumsum
I've a matrix like this:
1985 1.38 1.27 1.84 2.10 0.59 3.47
1986 1.05 1.13 1.21 1.54 0.21 2.14
1987 1.33 1.21 1.77 1.44 0.27 2.85
1988 1.86 1.06 2.33 2.14 0.55 1.40
1989 2.10 0.65 2.74 2.43 1.19 1.45
1990 1.55 0.00 1.59 1.94 0.99 2.14
1991 0.92
2005 Apr 12
2
not plotting when non-existent
R-help,
I'm trying to plot the following:
year lgd
1 1986 136.97479
2 1987 69.10377
3 1988 67.66744
4 1989 71.60316
5 1990 62.06897
6 1992 6.25000
7 1993 27.72021
8 1995 23.83648
9 1996 10.29412
10 1997 95.67487
11 1998 82.09367
12 1999 56.60401
13 2000 29.80864
14 2001 23.77535
15 2002 48.30378
16 2003 83.47571
17 2004 74.58711
There are 2 missing years
2017 Jun 07
0
Determining which.max() within groups
cumsum() seems to be what you need.
This can probably be done more elegantly, but ...
out <- aggregate(Q ~ wyr, data = Daily, which.max)
tbl <- table(Daily$wyr)
out$Q <- out$Q + cumsum(c(0,tbl[-length(tbl)]))
out
## yields
wyr Q
1 1990 4
2 1991 6
3 1992 9
4 1993 15
5 1994 18
I leave the matter of Julian dates to you or others.
Cheers,
Bert
Bert Gunter
"The trouble
2010 May 13
1
Where has the stats-rosuda-devel mailing list gone?
I require some assistance with JGR, but following the mailing list link from http://jgr.markushelbig.org/FAQ.html leads me to http://mailman.rz.uni-augsburg.de/mailman/listinfo/stats-rosuda-devel which responds with
No such list stats-rosuda-devel
I was previously subscribed to this mailing list and want to resubscribe, but where has it gone?
Many thanks,
Oliver Mannion
Programmer
COMPASS -
2017 Jun 07
4
Determining which.max() within groups
Using the dataset below, I got close to what I'm after, but not quite all
the way there. Any suggestions appreciated:
Daily <- read.table(textConnection(" Date wyr Q
1911-04-01 1990 4.530695
1911-04-02 1990 4.700596
1911-04-03 1990 4.898814
1911-04-04 1990 5.097032
1911-04-05 1991 5.295250
1911-04-06 1991 6.569508
1911-04-07 1991 5.861587
1911-04-08 1991 5.153666
2010 Apr 08
1
reshape panel data
I have a data set with observations on 549 cities spanning an 18 year
period. However, some of cities did not report in one or more of the 18
years. I would like to implement the procedure suggested by Wooldridge
section 17.1.3 in his "Econometric analysis of cross section and panel data"
to correct for attrition. For example the table below indicates that the 3rd
and the 7th cities in
2012 Aug 02
4
Subseting
Hi everyone
I have banking data set in long format with 4 columns.One of these columns
is bank name which consist of 49 banks and I want the data for only 40
banks out of these 49
so can anyone help me on how to get this 40 banks data
My data looks like
Year Name totalliabilties assets
1990 a 90 10
1991 a 89 48
1992 a 87
2007 Jun 29
1
How to add elements to a table
Hi,
I've been using R for a few weeks now, but consider myself still a
newbie, especially in what concerns the basics of data handling in R.
My situation is this:
I read in data from a database using RODBC, and then use "table" to
produce a table of "counts per years", table which I give to "plot".
All is well, as long as there are no gaps in the years