similar to: somebody help me about this error message...

Dear list, I have problem that I cannot solve and would like to ask your opinion. I tried to ask a few days ago already but got no answer and all my attempts to solve it by myself since then failed. Sorry for repeated posting! Here the problem broken down a bit. My problem basically is, that I want to use the elements of a character vector as names for objects and by recalling only the

Dear All: It was saved, but there was a space somewhere. So it works for me now. I do have another similar problem. I saved an R data file save(datahs0csv,file=" F:\Fall_2017\5-STA574\2-Notes\1-R\1-R_new\chapter4-Entering_Data/datahs0csv2 .rda") *The new R data file "*datahs0csv2.rda*" is in the directory.* I tried to load the file "" to R, but I got an error

Dear All: One more thing. I want to add the normal curve to the histogram. Is there away to stretch the peak of the curve to the top of the histogram or at least near to the top of the histogram. Please see the code below. Lizard.tail.lengths <- c(6.2, 6.6, 7.1, 7.4, 7.6, 7.9, 8, 8.3, 8.4, 8.5, 8.6,8.8, 8.8, 9.1, 9.2, 9.4, 9.4, 9.7, 9.9, 10.2, 10.4, 10.8,11.3, 11.9) x<-seq(5,12, 0.001)

Dear All: I am trying to load an R data set, but I got the following message. Please see below. The file is there. setwd("F:/Fall_2017/5-STA574/2-Notes/1-R/1-R_new/chapter4-Entering_Data") datahs0csv <- read.table("hs0.csv", header=T, sep=",") attach(datahs0csv) detach(datahs0csv) rm(list=ls()) Then I tried to reload the data, but I got this error message. I

I have a vaiable named NAM having value : 1,2,3,4,5,6,7,8,9. I want to make an indicator variable that will take value 1 if NAM=7 or NAM=8 or NAM=9. How can I do that? I usually do: Var001<- ifelse(NAM==7,1,0) for the simplest case. [[alternative HTML version deleted]]

My understanding is that R will not make copies of lists if there is only one reference to the object. However, I've encountered a case where R does make copies, even though (I think) there should be only one reference to the object. I hope that someone could shed some light on why this is happening. I'll start with a simple example. Below, x is a list with one element, and changing that

The object you load has the same name as the object you saved. In this case datahs0csv and not the name of the file sans .rda On Di., 12. Sep. 2017, 21:26 AbouEl-Makarim Aboueissa < abouelmakarim1962 at gmail.com> wrote: > Dear All: > > > It was saved, but there was a space somewhere. So it works for me now. > > I do have another similar problem. > > I saved an R

Hi All? I was looking at a posting from June-17. I managed to solve it. However, when I changed the example in the posting, my solution will work only once at a time which was mentioned by Jim Lemon on his response to the original posting. This means that my solution will have to be repeated as many times as the maximum number of spaces on each gap; something that may not work well for large

Dear all,   i would like to count the number of times where I have combined occurrences of the categories of 2 variables.   For instance, in the dataframe below, i would like to know how many times each author (au1, au2, au3 represent the first, second, third author) is associated with each of the category of the variable 'nam'. The position of the author does not matter.   nam <-

Dear All: I am wondering if there is a way in R to draw these two circles with shaded tracks in both circles using R, and make both circles uncovered. I am trying to make it in MS words, but I could not. Your help will be highly appreciated. In my previous post I added the image of the two circles, but the post never published. I just thought to resent the post again without the image. with

Hello, I have a maybe trivial question, but I simply don't understand well enought how to work with text/strings: I have a rather compelx data structure, a big list with several sub-lists/dataframes and for certain calculations (which I do in loops), I only need a certain group of sub-lists/dataframes, which I want to specify with a name vector and paste together the object name and pass it

Hi everyone,   I have got the following problem:   x1 <- rnorm(10,5,1) x2 <- runif(10,0,1) nam1 <- paste("A",1:4,sep=".") nam2 <- paste("A",6:9,sep=".") nam <- c(nam1,"A.4",nam2,"A.9") mydata <- data.frame(x1,x2) rownames(mydata) <- nam Error in `row.names<-.data.frame`(`*tmp*`, value = c("A.1",

Hi all, Take this simple script, which I'm trying to use to understand when modification in-place occurs, and when a new object is created: message("Global") x <- 1:3 .Internal(inspect(x)) x[2] <- 1L .Internal(inspect(x)) message("In function") (function() { x <- 1:3 .Internal(inspect(x)) x[2] <- 1L .Internal(inspect(x)) })() If I run it from the

Hello, I?m experimenting with ALTREP and was wondering if there is a preferred way to create an ALTREP wrapper vector without using .Internal(wrap_meta(?)), which R CMD check doesn?t like since it uses an .Internal() function. I was trying to create a factor that used an ALTREP integer, but attempting to set the class and levels attributes always ended up duplicating and materializing the

I'd love to understand what the function of the peer list returned by 'sip show peers' is for, especially when Realtime is used. If I start Asterisk with realtime enabled, a 'sip show peers' yields none. As each peer (phone) registers, or a call is made to the peer, Asterisk adds them to the list returned by 'sip show peers'. Correct? Apparently Asterisk doesn't

>I am trying to use the Hmisc function transace to transform predictors > > test<-cbind(flowstress,pressres,alloy) > xtrans<-transace(x,binary=pressres',monotonic='flowstress', categorical='alloy') > > >and I am getting the following message?? >Error in ace(x[, -i], x[, i], monotone = im, categorical = ic) : > unused argument(s) (monotone ...)

Hi Abou, Try this: library(plotrix) curve(rescale(dnorm(x ,mean=mean(Lizard.tail.lengths),sd=sd(Lizard.tail.lengths)), c(0,6)),add=TRUE, col=2, lwd = 2) Jim On Mon, Sep 25, 2017 at 9:35 AM, AbouEl-Makarim Aboueissa <abouelmakarim1962 at gmail.com> wrote: > Dear All: > > One more thing. > > I want to add the normal curve to the histogram. Is there away to stretch > the

I am trying to refer to a variable name in a lm regression where the variable name is in another variable, but it does seem to work. Here is an example: y<-rnorm(10) dat<-data.frame(x1=rnorm(10),x2=rnorm(10),x3=rnorm(10)) nam<-c('x1','x2','x3') library(gtools) com<-combinations(3,2,1:3) mod<-lm(y~nam[com[1,1]],data=dat) #error in model frame....:variable

Hi, I would like to know if it's ok to use .Internal(inspect(x)) in order to detect vector copying. Take for example the following silly code: f <- function() { x = seq(10) print(.Internal(inspect(x))) for(i in seq(10)) { x[i] <- x[i] + 1 print(.Internal(inspect(x))) } } The output of f() was: @bd7acf0 13 INTSXP g0c4 [NAM(1)] (len=10, tl=0) 1,2,3,4,5,... [1] 1 2

Dear R users,I come to you with a quite silly question I think, but I hope you can answer me... That is, I've got some problems in using the if and while conditions in a loop. Substantially, I want to select rows in a dataset depending on an index variable (suppose it ranges from 1 to 5), so to make a specific analysis (homemade of course) on thie new dataset. Mi first tought has been to do a