similar to: New Variable from Several Existing Variables

Hello to all is there a function wich splits a data.frame (column1,column2,column3,....) into data1 <-(column1,column3....) #column2 = 1 data2 <-(column1,column3....) #column2 = 2 data3 <-(column1,column3....) #column2 = 3 ... Regards Knut

I am writing a custom function that uses an R-function from the reshape package: cast. However, my question could be applicable to any R function. Normally one writes the arguments directly into a function, e.g.: result=cast(table1, column1 + column2 + column3 ~ column4, mean) (1) I need to be able to write this statement as follows: result=cast(table1, string_with_columns ~

Hi, set.seed(45) test1<-data.frame(columnA=rnorm(7,45),columnB=rnorm(7,10)) #used an example probably similar to your actual data apply(test1,2,function(x) sprintf("%.1f",median(x))) #columnA columnB # "44.5"? "10.2" par(mfrow=c(1,2)) lapply(test1,function(x) {b<-

I am about to write general functions to read the output of simulations models. These model generate output files with different sections which I want to analyze plot etc. Since this will be used many people at the department I wanted to make sure that will do this in the best way. For instance I want to read a snippets of data from a text that look like this.

Hi, I have a data fram like this: date column1 column2 column3 value1 value2 value3 1-1 A B C 10 5 2 2-1 A B D 5 2 0 3-1 A B E 17 10 7 How can I reshape it to: date column1 column2 column3 v x 1-1 A B C value1 10 1-1 A B C value2 5 1-1 A B C value3 2 2-1 A B D value1 5 2-1 A B D value2 2 2-1 A B D value3 0 3-1 A B E value1 17 3-1 A B E value2 10 3-1 A B E value3 7 Thx! Regards, Richard

hi, I have a vector full of strings like; xy_100_ab xy_101_ab xy_102_ab xy_103_ab I want to seperate each string in three pieces and the separator should be the "_" at the end I want a data.frame like: column1 column2 column3 xy 100 ab xy 101 ab xy 102 ab xy 103 ab I tried strsplit but I couldn't figure out how to convert the list I get into a data.frame. I just

Hi everyone, Hi want to separate the string(column1) for example column1 column2 column3 column4 column5 column6 bear b e a r cat c a t tiger t i g e r I know how to do this in excel where using MID function. Now I want to solve it using R. The list of strings is in

here's my question: suppose I have a matrix: mt<-matrix(1:12,ncol=6) now I have a vector vt<-c(1,2,2,2,1,2) which means I want to get: the 1st row for column1; the 2nd row for column2; the 2nd row for column3; the 2nd row for column4; ... that what I want is this vector: 1,4,6,8,9,12 Does anyone know how to do this fast? I know I can use for-loop to travel all columns,but

Hi, Im trying to complete a list of jobs using SQL Querries and some "if else" commands but im stucked in some steps. Could any of you give me some help? -in COLUMN1 change the format 20JAN2000:00:00:00 to 20JAN2000 and exclude every row that date is different from 20. -extract the first character in COLUMN2 and creat COLUMN3 with that value ex: COL2,COL3 135,1 461,4 247,2 -in every

Hello, Can someone kindly tell what the heck creating a relationship does in active record? I understand the idea of joining the tables and such. But how do I use it? Is it available in a scaffold? How about when I want to view a record and want to see all the joined data from the other table? Do I have to manually code the data I want from the other table? Does this automatically make the

Hi, I have a simple problem writing a function that is to be called like Myfunction( Column1 = low, Column2 = high, Column3 = all, Column4 = all, data = mydata) {. contourplot(z ~ mydata$Column3* mydata$Column3) . } Where Column1 and Column1 are the names of the dataframe mydata. How do I parse the arguments to obtain both, name and value of the argument. I tried strsplit(Column1,

Hi there I have two dataframes Dataframe_1 column_1 colum_2 121 12345 145 1675 167 2765 Dataframe_2 column_1 column2 121 abc 345 lmn 167 efg I want a resulting dataframe 121 12345 abc 167 2765 efg how do i go abt it Ramya -- View this message in context: http://n4.nabble.com/Dataframe-help-tp947934p947934.html Sent from the R

Hello, In my script I would like to use a loop, which sorts the dataframe according to different columns, pointed by the string variable. id col1 col2 col3 1 10 0 4 8 2 11 1 2 2 3 12 0 8 3 4 13 0 5 5 Usually the order() function can be used like this: sorted = mytable**[order(column3) , ] which results in properly sorted table: **

# Hello # I have a question regarding pairwise calculations of a matrix using a "for-loop." # Below I have a matrix "X" with 8 columns. These are Genotypic data so Column1 & Column2 is # a unit, Column3 & Column4 is a unit, Column5 & Column6 is a unit, and Coulmn7 & 8 is a unit. # I have a loop designed to calculate the number of times an individual in

# Hello # I have a question regarding pairwise calculations of a matrix using a "for-loop." # Below I have a matrix "X" with 8 columns. These are genotypic data so Column1 & Column2 is # a unit, Column3 & Column4 is a unit, Column5 & Column6 is a unit, and Coulmn7 & 8 is a unit. # I have a loop designed to calculate the number of times an individual in

Hi all, I'm hoping someone might help with a query about conditionally applying formulas to a dataframe. In essence I have 3 lookup tables (Table A, B & C) and a dataframe with a variable Type.Code, which identifies the Lookup Table to which each record belongs. The lookup tables reference different sensor types for which I need apply a different formula to values in Column3 in each row

Hi, I am newbie to R and working on result presentation? My Input table is in following format A B C D X T C K Z U Z M E V Z R Z U Z M E V P R I need to present my result in the

Hi there, I'm brand new to R, so let me know if this question is not appropriate for this list. I've been reading through the documentation and have tried a number of things, but am pretty much stuck so far. Here's the session info: > sessionInfo() R version 2.6.2 (2008-02-08) i386-apple-darwin8.10.1 locale: C attached base packages: [1] stats graphics grDevices

Dear list, I wonder if there a better way to have rbind/cbind/append to create the first element (if it is empty) instead of doing the following in a loop? for (i in 1:10) { if (i == 1) { aRow = SomeExpression(i) } else { aRow = rbind(aRow,SomeExpression(i)) } } Thanks Anthony

Hello, I'm hoping that there is an easier way to rename columns in a data frame other than by using the names() assignment, which requires you to type in all the column names at once for a data.frame, in the case that I simply want to rename a single column in a data frame. Also, is there an easy way to move columns in a data frame around relative to the other columns? Thanks in