similar to: binding multidimension array

Displaying 20 results from an estimated 1200 matches similar to: "binding multidimension array"

2005 Jun 21
1
test for equality of two data sets with multidimensional variables
Hello there, I have two data sets with 14 variables each, and wish to do the test for equality of their covariance matrices and mean vectors. Normally these tests should be done by chi square test (box provided) and Hotelling's T square test respectively. Which R functions could do this kind of test? I just find some functions could do for one dimension, but no for multidimension. Some one
2012 May 07
2
Matrix "BYTES" size
Dear R people. I´m facing a big problem. I need to create a matrix with 10.000 columns and 750.000 rows. matrix<- as.data.frame(matrix(data=0L, nrow=750000, ncol=10000) as you can see, the data frame has huge dimesions. I was able to find out about thr "L" in data, this way I´m telling that my data is "integer" class. By doing this object.size(matrix) tells me that this is
2009 May 24
2
Assigning variable names from one object to another object
Hello I have 2 datasets say Data1 and Data2 both are of different dimesions. Data1: 120 rows and 6 columns (Varname, Vartype, Labels, Description, ....) The column Varname has 120 rows which has variable names such id, age, gender,.....so on Data2: 12528 rows and 120 columns The column names in this case are V1, V2, ......... V120 (which are default names in R when we say head=F in read.csv)
2005 May 02
1
Multivariate kernel density estimation
Hi, I need to estimate the density at the mean of a sample of a few thousands data points with a dimesion up to 5. The data is uni-modal and regularly shaped. I couldn't find any kernel density package for R which supports more than 3 dimensions. Have I overlooked a package or does somebody have code for this purpose? Any other advice? Regards, Stephan
2006 Mar 08
1
info() function?
I would like to have some function for getting an overview of the variables in a worksheet. Class, dimesions, length, number of missing values,... Guess it wouldn't be that hard to set up such a function, but I guess there are others who have made it already. Or is it already a standard feature in the base package? Any suggestions? Robert
2005 Apr 21
2
apply vs sapply vs loop - lm() call appl(y)ied on array
Christoph -- There was just a thread on this earlier this week. You can search in the archives for the title: "refitting lm() with same x, different y". (Actually, it doesn't turn up in the R site search yet, at least for me. But if you just go to the archive of recent messages, available through CRAN, you can search on refitting and find it. The original post was from William
2010 Mar 02
2
Binding a matrix to a matrix
Hello I have a 2x10x200 matrix and I would like to bind to it another 2x10 matrix in order to end up with an 2x10x2001 matrix, which command should i use in order to do this? Thank you Felipe Parra [[alternative HTML version deleted]]
2006 Nov 23
2
loading libraries on MPI cluster
Dear R-users, we are using library(snow) for computation on a linux cluster with RMPI. We have a problem with clusterEvalQ: after launching clusterEvalQ it seems loading the required library on each node but if we type a function belonging to the loaded package R doesn't find it. > library(snow) # making cluster with 3 nodes > cl <- makeCluster(3, type = "MPI") Loading
2003 Oct 21
5
do.call() and aperm()
Hi everyone I've been playing with do.call() but I'm having problems understanding it. I have a list of "n" elements, each one of which is "d" dimensional [actually an n-by-n-by ... by-n array]. Neither n nor d is known in advance. I want to bind the elements together in a higher-dimensional array. Toy example follows with d=n=3. f <-
2009 Sep 03
5
abind, but on lists?
I'm trying to massage some data from Matlab into R. The matlab file has a "struct array" which when imported into R using the R.matlab package, becomes an R list with 3+ dimensions, the first of which corresponds to the structure fields, with corresponding row names, and the second and third+ dimensions correspond to the dimensions of the original struct array (as matlab
2008 Oct 28
2
abind
I am trying to combine two arrays with different dimensions into one. For example The first one is 1 2 3 4 5 6 The second one is 7 8 9 10 The resulted one would be like , , 1 1 2 3 4 5 6 , , 2 7 8 9 10 I used abind to do this, but failed. Could somebody please let me know how to do this in R? Thanks so many. Suyan
2013 Apr 10
6
means in tables
Hi. I have 2 tables, with same dimensions (8000 x 5). Something like: tab1: V1 V2 V3 V4 V5 14.23 1.71 2.43 15.6 127 13.20 1.78 2.14 11.2 100 13.16 2.36 2.67 18.6 101 14.37 1.95 2.50 16.8 113 13.24 2.59 2.87 21.0 118 tab2: V1 V2 V3 V4 V5 1.23 1.1 2.3 1.6 17 1.20 1.8 2.4 1.2 10 1.16 2.6 2.7 1.6 11 1.37 1.5 2.0 1.8 13 1.24 2.9 2.7 2.0 18 I need generate a table of averages, the
2005 Apr 21
1
Installing packages from source code
Hi everybody, I have trouble in installing packages from source code by following Section 5.1 in manual R-admin.pdf . I am using R 2.1.0 and Win NT. Following the Windows toolset section in the manual, I download the tool set package from: http://www.murdoch-sutherland.com/Rtools/tools.zip and unzip under C:\tools I also downloaded Perl (Windows Port) and installed it.
2011 Aug 12
1
install packages from intranet
Hi, I'm new to R. Apologies if this is a simple query, I've searched the mailing lists and docs but can't find a solution to my problem. I'm trying to make some packages available on our intranet. During development the 'intranet' is a webserver running on localhost. * When I call "install.packages" I get a mesage about not being able to access 'index
2005 Oct 21
1
Generalised rbind/cbind
Dear list, Is there a generalised form of rbind/cbind for combining matrices/arrays into higher-D structures? ie. if I have: a <- matrix(2,2,2) b <- matrix(3,2,2) how can I get array(rep(c(3,2), each=4), c(2,2,2)) ? It seems like this would be the job of a generalised abind function: abind(a,b, along=1) == rbind(a,b) abind(a,b, along=2) == cbind(a,b) abind(a,b, along=3)
2009 Oct 18
2
rbind to array members
Hi, I would like to add rows to arbitrary tables within a 3dimensional array. I can directly add data to an existing row of a table: > x <- array(0,c(1,3,2))> x[,,1] <- c(1,2,3) And I can even add a row to the table and assign to another object. > y <- rbind(x[,,1], c(4,5,6)) and 'y' is what I want it to be:> y?? ? [,1] [,2] [,3][1,] ? ?1 ? ?2 ? 3[2,] ? ?4 ? ?5 ? 6 but
2012 Mar 13
1
Visualising multiple response contingency tables
Dear R Help Community, I have a question and an answer (based on reading this forum and online research), but I though I should share both since probably there's a much better way to go about my solution. My question is specifically about how to best visualise multiple response contingency tables. What I mean by 'multiple response' is that the total number of responses per row of a
2011 Jan 20
1
syntax for a list of components from a list
I'm attempting to generalise a function that reads individual list components, in this case they are matrices, and converts them into 3 dimensional array. I can input each matrix individually, but want to do it for about 1,000 of them ... This works array2 <- abind(list1[[1]],list1[[2]],list1[[3]],along=3) This doesn't array2 <- abind(list1[[1:3]],along=3) This doesn't either
2002 Mar 13
1
several bugs (PR#918) lists and matrices
### I got bit again by the same bugs I wrote about a year ago. ### The bugs are related to matrices and arrays of lists. ### 1. There is a clear inconsistency in how R handles two ### functionally equivalent statements. ### array() is able to take a list and create a matrix. ### matrix() is unable to create that matrix. > vector("list", 2) [[1]] NULL [[2]] NULL >
2005 Feb 28
0
Re: R-help Digest, Vol 24, Issue 28
You've omitted a comma. races2000 is a data frame, which for purposes of extracting rows behaves like a 2-dimenional object. The following works fine: hills2000 <- races2000[races2000$type == 'hill', ] Additionally, you might like to ponder > type <- races2000[names(races2000)=="type"] > type[1:4] Error in "[.data.frame"(type, 1:4) :