similar to: Problem with strptime generating missing values where none appear to exist

Thanks Don MacQueen for this reply to my initial query - please SEE MY REPLIES TO THESE IDEAS AND FURTHER INFORMATION BELOW >From: Don MacQueen [macq at llnl.gov] >Sent: 23 February 2010 21:25 >To: Jonathan Williams; r-help at r-project.org > >Subject: Re: [R] Problem with strptime generating missing values where none appear to exist > >What happens if you do all that NA

Hi, I wrote a little helper that calulates someone''s age based on his/her date of birth. def age(dob) diff = Date.today - dob age = (diff / 365.25).floor age.to_s end It works fine, but it''s not completely accurate as it just takes the average days in a year. It should be able to calculate this more accurately, right? I can''t work it out

Hello All, I've been reading books about R for awhile now and am in the process of replicating the SAS analyses from an old report. I want to be sure that I can do all the things I need to in R before using it in my daily work. So far, I've managed to read in all my data and have done some data manipulation. I'm having trouble with fixing an error in a date variable though, and was

i know it''s probably really simple, how do i work out someone''s age if i have their d.o.b. stored as a date in my db. cheers -- Posted via http://www.ruby-forum.com/.

Hi, I wanted to calculate the age of people in my dataset by subtracting the individual's date of birth from their intake into a program. After several hours, searches of help archives, and the downloading of lubiridate, I have had no luck with this. Below is the code I used. > intakeDS$DOB <- as.character(intakeDS$DOB) > intakeDS$DOB <- as.Date(intakeDS$DOB,

Hello, I have some data that has dates in the form 27.02.37. I convert them to a date object as follows: as.Date(data$date,format="%d.%m.%y") But this gives me years such as 2037 when I would like them to be 1937. I thought of trying to take off some time i.e. as.Date(camCD$DoB,format="%d.%m.%y") - 100*365 But that doesn't seem to work out correctly. Any ideas how to

Hello, I have a data which looks like below: Some of the patients have multiple diagnosis. ID(200 patients)   Diag (100 unique Diag-200 in general)   Proc (50 uniqe Proc)  DOB (200)   Gender (200)    a                           daig1 b                           diag2 c                            diag1 I want to reformat this data to : ID   diag1 diag 2 diag 3..  diagx   proc1   proc2  

Hi, I have a column of DOB in mm/dd/yyyy. I want to convert this format to age. Thanks a lot.   Best,Farnoosh Sheikhi [[alternative HTML version deleted]]

Hello, I am trying to read a database exported from SAS. It is form of csv, and the date format reads '02-Feb-99'. I used following code to convert character to date format, db$dob<-as.Date(db$dob, format="%d-%b-%y"). but it doesn't work, only seems NA. What's wrong with this code? Thank you in advance. Best, Dong-Hee Koh [[alternative HTML version deleted]]

On Fri, Jun 10, 2016 at 6:36 AM, Gor Nishanov <gornishanov at gmail.com> wrote: > >> If you're going down that route, that still leaves the question of the > >> semantics of the fork intrinsic... thinking about it a bit more, I think > >> you're going to run into problems with trying to keep around a return > block > >> through optimizations:

Dear R experts, I'm reading data from an online database via API and it gets delivered in this messy comma separated structure, > RAW.API <-

Dear All, I installed R 2.7.0 and tried to call a dataset i had ealier own called on R2.6.2 but i keep on getting an error: use("maltreat.dta") Error in fromchar(x) : character string is not in a standard unambiguous format Tried doing the same with R2.7.1 but i get the same error. However if i call the same on R 2.6.2, there is no error: use("maltreat.dta") > des()

I simply can''t figure this out. I have been reading and re-reading Agile book and wiki.rubyonrails.org - all sorts of validation methods and still, it doesn''t work. Controller code def create @client = Client.new(params[:client]) if @client.save! flash[:notice] = ''Client was successfully created.'' redirect_to :action =>

I had occasion recently to read in a one-line *.csv file that looked like: "CandidateName","NSN","Ethnicity","dob","gender" "Smith, Mary Jane",111222333,"E","2/25/1989","F" That "F" (for female) in the last field got transformed to FALSE. Apparently read.csv (and hence read.table) are inferring

Hello all. I am a novice Ruby on Rails programmer, starting my first project using a legacy Oracle 10 database. Using ''reverse_scaffold'' I have created the models/controllers/views for my existing Oracle tables. All seems to work well, using /model/index, /model/show for most of my tables, *except* when one of the tables contains a Oracle ''date'' column, for

I have files which have columns of data that look like this: DOB 9/27/1964 ... That is, dates in month/day/year format. When variables like DOB are read in, they are converted to factors. So, I wrote this to convert from date to age in years: age<-function(x) {as.numeric(Sys.time()-strptime(as.character(x),format="%m/%d/%Y"))/365.25} This isn't very precise or pretty, but it

All of the tutorials and the Agile book use MySQL and I''ve got that working. I am now trying to use PostgreSQL and can''t seem to get going. Is my problem the db setup in postgresql? I have installed postgres-pr The error message when I try to access http://localhost:3000/clients when using PostgreSQL (MySQL works fine) ActiveRecord::StatementInvalid (RuntimeError: ERROR

how can i calculate the age of a person using database " birth date" my teble is user and column is bday .... now i want to calculate the age will some one please tell me how can i calculate the age.. actually i want to compare my two database fields birthdate and joining date ......that is why i need this.... will someone please tell me how can i do that

On Tue, 26 Mar 2024 14:50:41 +0100 Franta Hanzl?k <franta at hanzlici.cz> wrote: > On Tue, 26 Mar 2024 08:01:27 +0000 > Rowland Penny via samba <samba at lists.samba.org> wrote: > > > On Tue, 26 Mar 2024 02:57:51 +0100 > > Franta Hanzl?k via samba <samba at lists.samba.org> wrote: > > > > > Please, it is possible (perhaps with some Samba

On Tue, 26 Mar 2024 08:01:27 +0000 Rowland Penny via samba <samba at lists.samba.org> wrote: > On Tue, 26 Mar 2024 02:57:51 +0100 > Franta Hanzl?k via samba <samba at lists.samba.org> wrote: > > > Please, it is possible (perhaps with some Samba schema extension?) to > > have items as 'c' (countryName), 'l' (localityName), 'l' > >