similar to: env() for lme4

Displaying 20 results from an estimated 500 matches similar to: "env() for lme4"

2010 Aug 05
1
Help installation lme4a, Error Message: lme4a is not a valid installed library
Dear R users, I recently downloaded the library lme4a by svn checkout svn://svn.r-forge.r-project.org/svnroot/lme4. I tried to install the library lme4a by copying the downloaded document in the location where all the R libraries are saved. When I try to load the library, I obtain the message library(lme4a) Error in library(lme4a) : 'lme4a' is not a valid installed package R version
2010 Aug 05
1
Help installation lme4a,
Dear R users, I recently downloaded the library lme4a by svn checkout svn://svn.r-forge.r-project.org/svnroot/lme4. I tried to install the library lme4a by copying the downloaded document in the location where all the R libraries are saved. When I try to load the library, I obtain the message library(lme4a) Error in library(lme4a) : 'lme4a' is not a valid installed package R
2010 Nov 19
1
profile in lme4 and lme4a/lme4b
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2011 Oct 08
1
Help!
Hello dear friends. How can I make ubuntu to move from version 2.13.1 of R software to version 2.12.2. I want to go down to the less advanced version to use the package "lme4a". Please, I need your help. Thank you in advance.
2010 Feb 22
3
gsub patterns from vector elements w/out loop?
Dear list, I have two vectors: x <- c("one","two") y <- paste(rep(x,2),"blah") I want to replace all occurrences of each element of x in y with something else, so that y looks like this: y [1] "something else blah" "something else blah" "something else blah" [4] "something else blah" I can do this using a loop: for (
2010 Nov 29
1
cross tabulate variables by subject id
Dear list, I have data like this: dat1 <- data.frame(subject=rep(1:10,2), cond1=rep(c("A","B"),each=5), cond2=rep(c("C","D"),each=10), choice=sample(0:1,10,replace=TRUE)) I would like to compare subjects' "choice" for (cond1=="A" & cond2=="C") vs
2011 Feb 02
1
pass nrow(x) to dots in function(x){plot(x,...)}
Dear Rers, I have a function to barplot() a matrix, eg myfun <- function(x, ...) { barplot(x , ... )} (The real function is more complicated, it does things to the matrix first.) So I can do: m1 <- matrix(1:20,4) myfun(m1) myfun(m1, main="My title") I'd like to be able to add the number of rows of the matrix passed to the function to the "..." argument, eg
2008 Oct 05
1
barchart for aggregated (sum) data in lattice?
Hi list, I have data in a dataframe t1, with a column for different amounts spent, a column what it was spent on, and a column with dates, from which I create a new column with months. Example: amount <- rep(c(10,20,30),3) what <- rep(c("food","books","cycling"),3) when <- c(rep("2008-09-05",5),rep("2008-10-07",4)) t1 <-
2009 Oct 09
3
"Use R" -- term and logo copyright?
Dear list, I would like to start some R workshops at King's College London, and to do so, I would like to use the "Use R!" logo at http://www.agrocampus-ouest.fr/math/useR-2009//useR%21%202008_fichiers/useR-middle.png Since it seems to be difficult to get a shell account at KCL, I also went ahead and registered use-r.org.uk and am starting to put together a website at
2009 Dec 12
1
read.csv to read output of system()?
Dear list, I have a file that is comma delimited but contains some erroneous non-delimiter commas. I would like to replace these commas with semicolons and then read the correct file into R as a data frame. I want to do this from within R, without changing the original data file. My current idea of how to do this would be to use system("sed ...") and feed the result to read.csv(), but
2010 Aug 24
1
Index list by other list (w/ logical elements)?
I have two lists of the same shape, like this: x <- list() x[[1]] <- c("one","two") x[[2]] <- c("three","four","five") y <- list() y[[1]] <- c(TRUE,FALSE) y[[2]] <- c(FALSE,TRUE,TRUE) I would like to index x "by" y, that is, the result in this case should be: z [[1]] [1] "one" [[2]] [1] "four"
2009 Oct 03
2
add lines() to 1st plot in layout() after calling 2nd plot()?
Dear R users, I create a graphic with two plots side by side using layout(), like this: layout(matrix(c(1,2),1)) plot(1:10,main="left plot") lines(c(3:7,7:3),col="red") plot(10:1,main="right plot") The lines() obivously get added to the "left plot" plot. Now, I'm trying to write a function that builds up a plot bit by bit to then include it in a
2010 May 18
1
BIC() in "stats" {was [R-sig-ME] how to extract the BIC value}
>>>>> "MM" == Martin Maechler <maechler at stat.math.ethz.ch> >>>>> on Tue, 18 May 2010 12:37:21 +0200 writes: >>>>> "GaGr" == Gabor Grothendieck <ggrothendieck at gmail.com> >>>>> on Mon, 17 May 2010 09:45:00 -0400 writes: GaGr> BIC seems like something that would logically go into stats
2010 May 24
1
sparse matrices in lme4
I read somewhere (help list, documentation) that the random effects in lme4 uses sparse matrix "technology". I'd like to confirm with others that I can't use a sparse matrix as a fixed effect? I'm getting an "Invalid type (S4) " error. Thanks. ~~~~~~~~~~~~~~~~~~~ -Robin Jeffries Dr.P.H. Candidate in Biostatistics UCLA School of Public Health rjeffries@ucla.edu
2009 Sep 02
1
get function to return object "name"?
Dear list, I've written a function that plots subjects. Something like: myplot <- function(subject) { plot(subject) } Subjects are vectors, e.g. ... s1 <- c(200,200,190,180) ... and plotting them works fine, e.g. ... myplot(s1) Now I want to have "s1" etc appear in the plot title, but I don't know how to refer to this generically (the object "name"? I tried
2009 Oct 03
1
if else statement error
Hello, I am doing a if else statement in R. But it always comes out error such as 'unexpected symbol' There are two variables. ini and b. when ini=1, a=3; when ini>1 and b>2, a=3; all other situations, a=6. I don't know where it is wrong. Here is my code ini=3 b=4 if (ini==1) { a=3 } else if (ini>1 and b>2 ) { a=3 } else {a=6} Thanks a
2010 Jan 31
1
Help with R in ubuntu
Dear R users: Maybe it is a silly question, but I'm don't understand what am I doing wrong. In a new karmik koala ubuntu installation I compile the last patched 2.10.1 version of R. Every thing was right (I install all the dev libraries I need). First I type: ./configure --enable-R-shlib And I obtain: R is now configured for i686-pc-linux-gnu Source directory: .
2010 Nov 11
2
Number above the bar?
Hi I got an barplot, and I would like to have the exact number of the bars just above the bars anyone know how to do this? Sorry for bad English, and I do hope that you understand what im after. //Joel -- View this message in context: http://r.789695.n4.nabble.com/Number-above-the-bar-tp3037438p3037438.html Sent from the R help mailing list archive at Nabble.com.
2008 May 25
3
need help for building R in Ubuntu 8.04
Hi everyone I have been trying to build R in ubuntu 8.04 from its source code but am getting the following error. configure: error: --with-x=yes (default) and X11 headers/libs are not available Please help me and consider me a newbie in linux thanks in advance [[alternative HTML version deleted]]
2008 May 25
3
need help for building R in Ubuntu 8.04
Hi everyone I have been trying to build R in ubuntu 8.04 from its source code but am getting the following error. configure: error: --with-x=yes (default) and X11 headers/libs are not available Please help me and consider me a newbie in linux thanks in advance [[alternative HTML version deleted]]