Displaying 20 results from an estimated 2000 matches similar to: "plotrix 2.8-3"
2012 Apr 12
2
pyramid.plot in plotrix, axis labelling
Hi, I've been looking at ways to make pyramid plots in R. I like the pyramid.plot method in plotrix as it seems the simplest to use and building them in ggplot looks a bit more code intensive than I'd like, being as I'm new to R. This package does pretty much what I need it to do, however I can't seem to scale the x axis labels. The other labels scale fine with labelcex.
I
2011 Nov 14
1
Confused with an error message related to "plotrix" library in the newer versions of R.
Dear R Users,
Greetings!
I am confused with an error message related to "plotrix" library in the
newer versions of R.
I used to run an R script without fail in the earlier versions (R 2.8.1) of
R; but the same script is now throwing up an error message in the newer
versions (Now I have R 2.13.0 & R 2.14.0).
Herewith I am furnishing the same code for your perusal. It would
2010 Feb 13
4
Labels on a pyramide
I am using pyramid.plot() from the plotrix package.
I have something like this
############################################
xy.pop<-dados$masfr
xx.pop<-dados$femfr
#agelabels<-dados$femlab
xycol<-color.gradient(c(0,0,0.5,1),c(0,0,0.5,1),c(1,1,0.5,1),11)
xxcol<-color.gradient(c(1,1,0.5,1),c(0.5,0.5,0.5,1),c(0.5,0.5,0.5,1),11)
xylab<-dados$maslab
xxlab<-dados$femlab
2009 Mar 16
0
Updates to plotrix and clinsig
Hi everybody,
An update to plotrix (2.5-3) is now on CRAN. Apart from the usual
polishing, this includes an interesting new function (hierobarp) that
was suggested on this very list a few weeks ago. This function will plot
nested breakdowns of numeric values by one or more factors. It seems
quite useful for visualizing the deviations in successively finer
divisions of the data. Comments are
2009 Jul 21
0
plotrix v2.6-4
Hi all,
After a lot of rewriting, I am happy to say that plotrix_2.6-4 is on
CRAN. The reason I am announcing this is that the newish hierobarp
function has had a complete rewrite. This was the result of my learning
that the old version was horrendously slow on large data sets. Let me
know if there are any other problems in the package. Next up - a
function to center plot titles to the figure
2009 Jul 21
0
plotrix v2.6-4
Hi all,
After a lot of rewriting, I am happy to say that plotrix_2.6-4 is on
CRAN. The reason I am announcing this is that the newish hierobarp
function has had a complete rewrite. This was the result of my learning
that the old version was horrendously slow on large data sets. Let me
know if there are any other problems in the package. Next up - a
function to center plot titles to the figure
2009 Jul 30
1
Transparency and pyramid.plot
Hi all
Another question related to my earlier -- how might I get transparency to work
with pyramid.plot in library(plotrix)? I can't figure it out, and the help page
says it is there but doesn't give an example.
Thanks!
2008 Aug 15
2
Design-consistent variance estimate
Dear List:
I am working to understand some differences between the results of the
svymean() function in the survey package and from code I have written
myself. The results from svymean() also agree with results I get from
SAS proc surveymeans, so, this suggests I am misunderstanding something.
I am never comfortable with "I did what the software" does mentality, so
I am working to
2005 May 26
1
Survey and Stratification
Dear WizaRds,
Working through sampling theory, I tried to comprehend the concept of
stratification and apply it with Survey to a small example. My question
is more of theoretic nature, so I apologize if this does not fully fit
this board's intention, but I have come to a complete stop in my efforts
and need an expert to help me along. Please help:
age<-matrix(c(rep(1,5), rep(2,3),
2008 Jan 25
3
function code
R-help,
Sorry for this question (I guess it has been addressed before but
I could not find it in the archives)
but how can I see a function code
when the following comes up:
> svymean
function (x, design, na.rm = FALSE, ...)
{
.svycheck(design)
UseMethod("svymean", design)
}
<environment: namespace:survey>
Thanks in advance
2003 Feb 12
2
Various Errors using Survey Package
Hi,
I have been experimenting with the new Survey package. Specifically, I was
trying to use some of the functions on the public-use survey data from NHIS
(2000 Sample Adult file).
Error 1): The first error I get is when I try to specify the complex survey
design.
nhis.design<-svydesign(ids=~psu, probs=~probs, strata=~strata, data=nhis.df,
check.strata=TRUE)
Error in svydesign(ids =
2012 Oct 02
2
svyby and make.formula
Hello,
Although my R code for the svymean () and svyquantile () functions works fine, I am stuck with the svyby () and make.formula () functions. I got the following error messages.
- Error: object of type 'closure' is not subsettable # svyby ()
- Error in xx[[1]] : subscript out of bounds # make.formula ()
A reproducible example is appended below.
I would appreciate if
2008 Aug 26
2
svymeans question
I have the following code which produces the output below it
clus1 <- svydesign(ids = ~schid, data = lower_dat)
items <- as.formula(paste(" ~ ", paste(lset, collapse= "+")))
rr1 <- svymean(items, clus1, deff='replace', na.rm=TRUE)
> rr1
mean SE DEff
W525209 0.719748 0.015606 2.4932
W525223 0.508228 0.027570 6.2802
W525035 0.827202
2006 Dec 05
1
Surveys ans missing values
Hello,
I still apologise if the question i ask is naive. I would like to use R
instead of usual softs (SAS, Stata) or at list to do things that the others
do not. As a consequence I am trying to get familiar with R, and i am
astonished because it does not seem to do things that are easy to do on
other softs.
I have got data with missing values (I am working on a questionnaire filled
by students)
2006 Jul 07
2
Multistage Sampling
Dear WizaRds, dear Thomas,
First of all, I want to tell you how grateful I am for all your
support. I wish I will be able to help others along one day the same way
you do. Thank you so much. I am struggling with a multistage sampling
design:
library(survey)
multi3 <- data.frame(cluster=c(1,1,1,1 ,2,2,2, 3,3), id=c(1,2,3,4,
1,2,3, 1,2),
nl=c(4,4,4,4, 3,3,3, 2,2), Nl=c(100,100,100,100,
2010 Aug 25
1
Surprising behaviour survey-package with missing values
Dear list,
I got some surprising results when using the svytotal routine from the
survey package with data containing missing values.
Some example code demonstrating the behaviour is included below.
I have a stratified sampling design where I want to estimate the total
income. In some strata some of the incomes are missing. I want to
ignore these missing incomes. I would have expected that
2003 Sep 20
4
using aggregate with survey-design and survey functions
Hi R users,
I am trying to use the aggregate function with a survey design object and
survey functions, but get the following error. I think I am incorrectly using the
syntax somehow, and it may not be possible to access variables directly by
name in a survey-design object. Am I right? How do I fix this problem? I have
used aggregate with "mean" and "weighted.mean", and
2010 Mar 26
1
return.replicates in survey pkg
How do I retrieve the replicates estimates from a crosstab done using
svyby?
Here is an example from the help page for svyby in the package:
> data(api)
> dclus1<-svydesign(id=~dnum, weights=~pw, data=apiclus1, fpc=~fpc)
> rclus1<-as.svrepdesign(dclus1)
>
> a <- svyby(~api99, ~stype, rclus1, svymean, return.replicates=TRUE)
> a$replicates
NULL
But, compare to
> b
2017 Jul 09
2
Help with ftable.svyby
Hi all,
When I try the following with pkg Survey it returns the error below:
ftable(svyby(~INCOME, ~AGECL+RACECL, svymean, design=q50),
rownames=list(AGECL=c("<35", "35-44", "45-54", "55-64",
"65-74", ">=75"),
RACECL=c("white non hispanic", "non white or
2007 Dec 19
2
4 questions regarding hypothesis testing, survey package, ts on samples, plotting
Good morning!
I have 4 questions which trouble me:
1. I want to test the hypothesis that the 2 proportions (the mean of a binomial) which come from 2 different samples are equal. I want to use the following function
z= (p1-p2)/ sqrt((p1(1-p1)/n1)+(p2(1-p2)/n2)) which is one of the standard formulas for this case. Is there such a function in R?
p1=the proportion from the first sample
n1=the