similar to: Time series cross-sectional regression analysis

Hi, Suppose a=matrix(1:9,3,3) > a [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 Now, > class(a[1:2,]) [1] "matrix" > class(a[1:3,]) [1] "matrix" > class(a[,1:2]) [1] "matrix" > class(a[,1:3]) [1] "matrix" But, > class(a[1,]) [1] "integer" > class(a[,1]) [1]

Hi, Can somebody tell me the formula for "?wilderSum" in TTR package? I mean how are these calculated? BR, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi all, Just like Fortran creates EXE files for a code, can R also do the same? Thanks for the info. Thanks and Regards, Shubha Karanth | Amba Research Ph +91 80 3980 8283 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, Can I get a comparison between R and MATLAB? How is R efficient than MATLAB? Or what are the weaknesses of R compared to MATLAB? Thank you very much for your help, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain confidential and/or

Hi R, Again struck with regular expressions... Suppose, S=c("World_is_beautiful", "one_two_three_four","My_book") I need to extract the last but one element of the strings. So, my output should look like: Ans=c("is","three","My") gsub() can do this...but wondering how do I give the regular expression....

Hi R, I have a request... Can I call R functions/routines from C# or C++? If so, how do I do this? Do I need to have some knowledge on DLL to do this? Thanks a lot for your help, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

Hi R, I have a 100th order equation for which I need to solve the value for x. Is there a package to do this? For example my equation is: (x^100 )- (2*x^99) +(10*x^50)+.............. +(6*x ) = 4000 I have only one unknown value and that is x. How do I solve for this? BR, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore *

Hi R, I have certain checkings, which gives FALSE, but actually it is true. Why does this happen? Note that the equations that I am checking below are not even the case of recurring decimals... > 1.4^2 == 1.96 [1] FALSE > 1.2^3==1.728 [1] FALSE Thanks in advance, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo *

Hi R, A simple question, but don't know the answer... x="a" a=5 I need to remove the object "a" by using only x. something like rm(somefunction(x))...Is this possible? Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

Hi R, I have the variance-covariance matrix, >V=matrix(c(0.011119238, 0.002407527, 0.002407527, 0.020739401),2,2) I need to find a vector X=c(x1,x2), such that 1) X'VX is equal to a constant 2 (say) and 2) sum(x) should be equal to a another constant 1.5 (say). How do we do this in R? BR, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94

Hi R, A quick question: How do we find the number of words in a string? Example: C="Have a nice day" And the number of words should be 4. any built in function or?... Thanks, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

R users, I have a problem in RMysql. The error I get is: > library(RMySQL) > library(RMySQL) >options(expressions=10000) > MySQL(max.con = 16, fetch.default.rec = 500, force.reload = FALSE) Error: protect(): protection stack overflow I have no idea of why the error is. Can anyone help on this? Many Thanks, Shubha Shubha Karanth | Amba Research Ph +91 80 3980

Hello R, Is there a package to perform Polynomial goal programming in R? BR, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, This is a problem, which I have tried to present in a simple way: Let, x1=1:10 x2=2:11 y=2+3*x1 lm_obj=lm(y~x1+x2) lm_obj step(lm_obj) # Step function for the first time y=y^0.1 lm_obj step(lm_obj) #Step function after a transformation on Y, but 'lm_obj' is not modified. The two step function behave differently. The first one is before the

---------- Forwarded message ---------- From: Shubha Vishwanath Karanth <shubhak at ambaresearch.com> Date: Nov 24, 2006 7:54 PM Subject: Dates Conversion/write.foreign To: Shubha Karanth <shubhakaranth at gmail.com>, Shubha Vishwanath Karanth <shubhak at ambaresearch.com> Hi R experts, I need an urgent help... I have an a dataframe caled idat. Below i give a snapshot

Hi R, I have a list, l=list(list(c(1,2),c(4,5),c(6,7)),list(c(11,22,33),c(44,55,66))) > l [[1]] [[1]][[1]] [1] 1 2 [[1]][[2]] [1] 4 5 [[1]][[3]] [1] 6 7 [[2]] [[2]][[1]] [1] 11 22 33 [[2]][[2]] [1] 44 55 66 How do I know the dimensions of this list?... In other words, how many sub-lists, sub-sub-lists etc...are there in l? How do I know this?

Hi R, I am trying to download the data from R. I give the below command. > library(fImport) > yahooSeries("IBM") trying URL 'http://chart.yahoo.com/table.csv?s=IBM&a=7&b=08&c=2007&d=7&e=07&f=2008& g=d&x=.csv' Error in download.file(url = url, destfile = file, method = method) : cannot open URL

Hi R, I have the data frames, data1, data2....data50. Now I want to put all of these in a single list. But, >list(data1, data2,.........data50) is very big to write. How do I then do it? Thanks, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, This is a very trivial one.... C=0.1 I want to check whether my value of C is between 0 and 1 exclusively.... I don't want to use (C>0 & C<1). And I can't use a single statement like (0<C<1). Is there a between function? Or how do we specify from 0 to 1? Does %in% help me? Many Thanks, Shubha This e-mail may contain confidential and/or

Hi R, I was experimenting with the CA package for correspondence analysis. data(author) ca(author) plot(ca(author)) How can I get the values used by the plot for the two axis for biplot? In other words, how will I be able to obtain the scores in the dimensions (which are obtained by PCA) of the graphs? Thanks. Thanks and Regards, Shubha This e-mail may contain