similar to: Counting by rows based on multiple criteria

Hi, I have a question about the "sext..to" instruction. In the document, I found two examples: %x = sext i8 -1 to i16 It means: i8 -1 = 1111 1111 --> 1111 1111 1111 1111 = i16 how can it determinate, that the i16 value %x positive is (65535)? And the second example: %y = sext i1 true to i32 1 --> 1111 1111 1111 1111 1111 1111 1111 1111 In this example, %y is -1 I'm not sure

Dear all, I am attempting to perform a calculation which counts the number of positive (or negative) values based on the sample mean (on a per-row basis). If the mean is>0 then only positive values should be counted, and if the mean is <0 then only negative values should be counted. In cases where the mean is equal to zero, the value -99999 should be returned. The following is an example

Hi, I have a matrix (pwdiff in the example below) with ~480000 rows and 780 columns. For each row, I want to get the percentage of columns that have an absolute value above a certain threshold "t". I then want to allocate that percentage to matrix 'perc' in the corresponding row. Below is my attempt at doing this, but it does not work: I get 'replacement has length

Dear R-users: Sorry to bother so late with this question, which surely has simple answer. I'm working with matrices that contain either "1" or "0", for example: [,1] [,2] [,3] [,4] [,5] A 1 0 1 0 0 B 0 1 0 1 0 C 1 0 1 0 0 D 1 1 1 0 1 I want to count the number of "1" common to, say, A and B, the

Hi, I am a little new in R but I'm finding it extremely useful :) Here's my tiny question: I've got a table with a lot of columns. What I am interested now is to evaluate how many of 4 columns have a value greater than 1. I think it can be done with subset() but it will take a very long condition and become unfeasible if I want to compare more than 4 columns. I put here a small

> I'm not sure about it, when sext to results a positve/negative value? sext does signed-extension, zext does unsigned-extension. This means that zext always extends by zero bits, while with sext the additional bits are all copies of the top bit of the original value. So with sext, if it was negative in the original type when considered as a signed value, then it will be negative in the

Hello Everyone, I have what I think is a complex text parsing task. I've provided some sample data below. There's a relatively simple version of the coding that needs to be done and a more complex version. If someone could help me out with either version, I'd greatly appreciate it. Here are my sample data. haveData <- structure(list(profile_key = structure(c(1L, 1L, 2L, 2L, 2L,

Hello All, Can anyone tell help me understand why the function below doesn't work and how I can fix it? Below are some sample data, some code that works on individual rows of the data, and my attempt to translate that code into a function. My hope is to get the function working and then to apply it to the larger data frame using ddply() from the plyr package or possibly some other approach.

Hi I'm doing a bootstrap of a linear model using: boot.fishpower <- function(data, i){ data <- data[i,] fplm <- lm(log(U)~Q+S+P+B+D, data=data) fp <- coef(fplm) exp(fp) } > boot(logglm.data,boot.fishpower,100) Error in "[<-"(*tmp*, r, , value = statistic(data, i[r, ], ...)) : number of items to replace is not a multiple of replacement length

I am trying to automatically construct a distance function from a training set in order to use it to cluster another data set. The variables are nominal. One variable is a "class" variable having two values; it is kept separate from the others. I have a method which constructs a distance matrix for the levels of a nominal variable in the context of the other variables. I want to

Hi R-users, I'm trying to find an elegant way to count the number of rows in a dataframe with a unique combination of 2 values in the dataframe. My data is specifically one column with a year, one with a month, and one with a day. I'm trying to count the number of days in each year/month combination. But for simplicity's sake, the following dataset will do:

Hello, sorry for posting this independently of the original thread, but it is not that easy to answer to mails, when receiving the r-help as digest... ... The question was: > I compare each row of a matrix with each row of another matrix. > > testmat1 <- matrix(c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16), nrow=4) > testmat2 <- matrix(c(1,2,3,5,5,6,7,8,9,10,11,12,13,14,15,16),

Hi all (really probably just Deepayan): In the plot below I want to add text on either side of each violin plot that indicates the number of observations that are either positive or negative. I'm trying to do this with ltext() and I've also monkeyed about with panel.text(). The code below is generally what I want but my calls to ltext() are wrong and I'm not sure how to fix them.

Hi All, There are a variety of functions that can be applied to a variable (column) in a data frame: mean, min, max, sd, range, IQR, etc. I am aware of only two that work on the rows, using q1-q3 as example variables: rowMeans(cbind(q1,q2,q3),na.rm=T) #mean of multiple variables rowSums (cbind(q1,q2,q3),na.rm=T) #sum of multiple variables Can the standard column functions (listed in the

Hi, Can someone tell me how to remove rows of zeros from a matrix? For example if I have the following matrix, 0 0 0 1 2 8 0 0 4 56 I should end up with 0 1 2 8 4 56 -- Thanks, Jim. [[alternative HTML version deleted]]

Hi I have a data frame df with 3 columns. Some rows are NA across all 3 columns. How can I remove rows with NA across all columns? df=data.frame(col1=c(1:3,NA,NA,4),col2=c(7:9,NA,NA,NA),col3=c(2:4,NA,NA,4)) Thanks Joseph ____________________________________________________________________________________ Be a better friend, newshound, and [[alternative HTML version deleted]]

Dear R helpers, I wish to use the "sum" operator for each row of a data frame. However, it appears that the operator acts on the entire data frame, over all columns. What is the best way to obtain row- wise operation? The following code shows my attempts so far, and their problems:- test1=array(rbinom(120,1,0.5),c(20,3)) test1[,3]=NA sum(test1[,1:2]) test1[,3][sum(test1[,1:2])>=2]=1

Hi, I'm new to R and trying to some simple analysis. I have a data set with about 88000 transactions and i want to perform a simple support count analysis of an itemset which is say not a complete transaction but a subset of a transaction. say {A,B,D} is a transaction and i want to find support of {A,B} even though it never occurs as only A,B in the entire set To this i needed to create

Hi I have a two-column integer matrix like this: R> jj [,1] [,2] [1,] -1 1 [2,] -2 2 [3,] -7 6 [4,] -8 7 [5,] -6 5 [6,] -9 8 [7,] -5 4 [8,] 3 -3 [9,] -10 9 [10,] -4 3 I want a diagnostic that detects whether a row is a multiple of the first row or not. In this case, this would be rows 1,2, and 8. How to do this

Dear all, I have 2 data frames, both with 14 columns of data and differing numbers of rows. The first two columns are 'Latitude' and 'Longitude'. I want to find the pairs of Latitude and Longitude coordinates which are common to both datasets, and output a new data frame which is composed of these coincident rows. I tried using the 'unique' command, but had difficulties