similar to: iterating over a data frame the R way?

We''re still just starting out with Mocha/Stubba, so please forgive any newbie errors. I''m using "stubs" to test some realtime functions, to control exactly which time is returned from Time.now. I would expect the following test to pass: def test_two_stubs t = Time.now - 60 Time.stubs(:now).returns(t) start_time = Time.now t += 20

This problem was reported to me by a friend who has an LLVM port that is not put back to open source. Essentially, there is an intrinsic call _lr which is a load register. so then user code has something like: start_time = _lr(TIMER_REGISTER) ..... some_code_to_time .... end_time = _lr(TIMER_REGISTER) So what happens is that LLVM moves the code as follows: start_time = _lr(TIMER_REGISTER)

hi, I'm working with asterisk on a project and I found a problem with cdr_odbc. As we know, after answering each call a cdr event is raised which is saved in cdr_csv and cdr_odbc. but here my point is on cdr_odbc. some information, including start_time and end_time is given by cdr event but the problem is that these two information(start_time and end_time) is not getting save in cdr_odbc. I

Factor out copying the overlays to final disk images into a separate function. Signed-off-by: Roman Kagan <rkagan@virtuozzo.com> --- v2v/v2v.ml | 227 +++++++++++++++++++++++++++++++------------------------------ 1 file changed, 114 insertions(+), 113 deletions(-) diff --git a/v2v/v2v.ml b/v2v/v2v.ml index afffde2..703038c 100644 --- a/v2v/v2v.ml +++ b/v2v/v2v.ml @@ -110,121 +110,9 @@ let

I would like to know whether there is a faster way to do the below operation (updating vec1). My objective is to update the elements of a vector (vec1), where a particular element i is dependent on the previous one. I need to do this on vectors that are 1 million or longer and need to repeat that process several hundred times. The for loop works but is slow. If there is a faster way, please let

This can be vectorized. Try ix <- seq_along(vec2) S_diff2 <- sapply(seq_len(N1-(N2-1)*ratio_sampling), \(j) sum((vec1[(ix-1)*ratio_sampling+j] - vec2[ix])**2)) On Sun, Jun 16, 2024 at 11:27?AM Laurent Rhelp <laurentRHelp at free.fr> wrote: > > Dear RHelp-list, > > I try to use the package comprehenr to replace a for loop by a list > comprehension. > > I

Dear RHelp-list, ?? I try to use the package comprehenr to replace a for loop by a list comprehension. ?I wrote the code but I certainly miss something because it is very slower compared to the for loops. May you please explain to me why the list comprehension is slower in my case. Here is my example. I do the calculation of the square difference between the values of two vectors vec1 and

Simple one, have read and googled, still no luck! I want to create several empty vectors all of the same length. I would like multiple empty vectors (vec1, vec2, vec3) and want to create them all in one line. I've tried vec1,vec2,vec3 <- vector(length=5) and c(vec1,vec2,vec3) <- vector(length=5) and several other attempts but nothing seems to work ... suggestions? Thanks Jim

Is there any built-in way to lexicographically compare two vectors of the same length in R? The textbook algorithm could be coded as follows: lex.cmp <- function (vec1,vec2) { for (j in 1:length(vec1)) { if (vec1[j] < vec2[j]) { return(-1) } if (vec1[j] > vec2[j]) { return(1) } } return(0) } Thanks, Gabriel

Laurent, Thank you for introducing me to a package I did not know existed as I use features like list comprehension in python all the time and could see using it in R now that I know it is available. As to why you see your example as slow, I see you used a fairly complex and nested expression and wonder if it was a better way to go. As you are dealing with an interpreter doing delayed

Dear all, Without a loop, I would like transform 3 numeric vectors empty of 0/1 of same length Vec1 : transform 1 to A and 0 to "" Vec2 : transform 1 to B and 0 to "" Vec3 : transform 1 to C and 0 to "" to obtain only 1 vector Vec who is the paste of the 3 vectors (Ex : ABC, BC, AC, AB,...) Any idea ? Thank you for your help -- Michel ARNAUD

Hello Wise Ones... I need a clever way around a problem with findInterval. Consider: vec1 <- 1:10 vec2 <- seq(1, 10, by = 0.1) x1 <- c(2:3) a1 <- findInterval(x1, vec1); a1 # example 1 a2 <- findInterval(x1, vec2); a2 # example 2 In the problem I'm working on, vec* may be either integer or numeric, like vec1 and vec2. I need to remove one or more sections of this vector;

Just received the news from Tom Mornini. Congrats Ezra for the new Engine Yard site and the blog you will be collaborating. Hope to read you there soon. http://www.engineyard.com/ Jonathan -------------- next part -------------- An HTML attachment was scrubbed... URL: http://rubyforge.org/pipermail/backgroundrb-devel/attachments/20060925/3f251fa4/attachment.html

Try factor(vec2) in your bwplot() call. -----Original Message----- From: r-help-bounces at stat.math.ethz.ch [mailto:r-help-bounces at stat.math.ethz.ch]On Behalf Of Ernesto Jardim Sent: Friday, July 09, 2004 9:41 AM To: Mailing List R Subject: [R] Problem with bwplot Hi, I'm ploting some box-and-whisker plots with bwplot but I'm not getting any box-and-whiskers ... just dots.

Dear R-helpers: I have a question related to using do.call to call cbind and get. #the following works vec1 <- c(1,2) vec2 <- c(3,4) ColNameVec <- c('vec1','vec2') mat <- do.call("cbind",lapply(ColNameVec,get)) mat #put code above into a function then it does not work #before doing so, first remove vec1 and vec2 from global environment rm(vec1,vec2) test

Thanks. Yes. Your approach can identify: Glaxy ace S 5830 and S 5830 Glaxy ace But you can not identify using same program: Iphone 4S 16 G Iphone 4S 16G How should I solve both in same time. Kind regards,Tammy [[alternative HTML version deleted]]

Hello. Sorry I am not sure this question should go to llvm or mesa3d-dev mailing list, so I post it to both. I am writing a llvm backend for a modern graphics processor which has a ISA very similar to that of Direct 3D. I am reading the code in Gallium-3D driver in a mesa3d branch, which converts the shader programs (TGSI tokens) to LLVM IR. For the shader instruction also found in LLVM IR,

Hello again, Let say I have following user defined function: fn <- function(x, y) { Vec1 <- letters[1:6] Vec2 <- 1:5 return(list(ifelse(x > 0, Vec1, NA), ifelse(y > 0, Vec2, NA))) } Now I have following calculation: > fn(-3, -3) [[1]] [1] NA [[2]] [1] NA > fn(3, -3) [[1]] [1] "a" [[2]] [1] NA Here I can not understand why in the second case, I get

I would be more strong on this advice: learn to think in R, rather than thinking in Python, when programming in R. R has atomic vectors... Python does not (until you import a package that implements them). I find that while it is possible to import R thinking into Python, Python programmers seem to object for stylistic reasons even though such thinking speeds up Python also. A key step in that

Hi dear list, If anybody could help me, it would be great! I have two files: File 1 is a list (one column and around 100000 rows) File 2 is a list with all the names from file one and a few more (one column and more than 100000 rows) What I want is to add a column in file 2 that says which name appeared in file 1 and which doesn't (yes and no would work as a code) It's very important to