Displaying 20 results from an estimated 6000 matches similar to: "Error: "Insufficient memory. Please close the console""
2009 Apr 23
2
update.packages(checkBuilt=TRUE) returns Error: invalid version specification NA in 2.9.0
I installed R-2.9.0 yesterday, and followed the instructions in the R for
Windows FAQ, 2.8 What's the best way to upgrade? It reads "run
update.packages(checkBuilt=TRUE, ask=FALSE) in the new R and then delete
anything left of the old installation." I did this but it returned an
error. It's the checkBuilt=TRUE which causes it, though I don't know why:
leaving it out or
2018 Aug 16
2
Xenial rpart package on CRAN built with wrong R version?
I manually downloaded the rpart package and installed it using dpkg, without removing the old rpart package first, and now everything works. During the installation, dpkg said:
Unpacking r-cran-rpart (4.1-13-1cran1xenial0) over (4.1-13-1cran1xenial0)
So again, it seemed that the new version had been installed, but it really wasn?t. I had no idea that something like this could happen. Huh.
2018 Aug 14
2
Xenial rpart package on CRAN built with wrong R version?
I?m not using the PPA, but the CRAN mirror from https://cran.r-project.org/bin/linux/ubuntu/#installation:
deb https://cloud.r-project.org/bin/linux/ubuntu xenial-cran35/
On 14 Aug 2018, at 12:25, George N. White III <gnwiii at gmail.com<mailto:gnwiii at gmail.com>> wrote:
qOn Tue, 14 Aug 2018 at 05:04, Ulrich KELLER <ulrich.keller at uni.lu<mailto:ulrich.keller at
2007 Jan 17
5
percent sign in plot annotation
Hello,
I would like to annotate a graph with the expression 'alpha = 5%' (the
alpha should be displayed as the greek letter).
I tried
> text(1,1,expression(alpha == 5%))
which gives a syntax error.
escaping the percent sign (\%) or doubling (%%) does not help.
What do I do?
Thanks,
Martin Keller-Ressel
--
Martin Keller-Ressel
Research Unit of Financial and Actuarial
2010 Mar 15
2
[R-SIG-Mac] How to interrupt an R process that hangs
+1--this is the single most-annoying issue with R that I know of.
My usual solution, after accomplishing nothing as R spins idly for a couple
hours, is to kill the process and lose any un-saved work. save.history() is
my friend, but is a big delay when you work with big data sets as I do, so I
don't run it after every command.
I have cc'd r-help here, however, because I experience this
2017 Dec 19
2
broadcom and centos 7
On Tuesday 19 December 2017 03:56:20 Keith Keller wrote:
> On 2017-12-19, Keith Keller <kkeller at wombat.san-francisco.ca.us> wrote:
> > https://elrepo.org/tiki/wl-kmod
>
> I decided to give this a go, and so far so good. I did need to rebuild
> the rpm after updating the kernel version from the previous one to the
> current one, but from the page above it sounds like
2011 Aug 19
1
how to merge distance data based on location
Hi all,
I have two data frames, two columns each, 1000s of rows. Each row
represents a segment of the genome where a deletion has occurred.
First column is start position of the deletion in genomic distance,
second is end position.
So, e.g., first 3 rows of data frame A is:
1003 1023
5932 6120
12348 12689
first 3 rows of data frame B is:
852 5305
1010 1015
8500 9500
10000 13000
I want to merge
2002 Feb 15
3
Bug(?) in predict.tree() --- Evaluation order of Boolean operators
Dear R users
I have a problem with predict.tree() when I want the fitted values
of a tree object to be returned (i.e. argument 'newdata' is missing).
Whatever I specify for argument 'type' the fitted model object is
returned.
Example:
library(tree)
data(kyphosis)
fit.tree <- tree(Kyphosis ~ Age + Number + Start, data=kyphosis)
p <- predict(fit.tree,
2005 Jul 05
1
timezone problems
Hi,
Im using R 2.1.1 and running Code that previously worked (on R 2.1.0 I
believe) using the 'timeDate' function from the fCalendar package. The
code now throws an error:
Error in if (Sys.timezone() != "GMT") warning("Set timezone to GMT!")
However I have read the documentation of the fCalendar package and I have
set my system variable TZ to GMT.
I tracked the
2011 Jun 21
2
par code help
I am making a barplot using barplot2 from gplots where each bar
represents a specific tree species. I have formatted the species names
on the x-axis so that the genus name is above the species name and
have then rotated the labels 45 degrees to save room. This is my code:
>columncolor<-c("grey20", "grey20", "grey20", "grey70",
2011 Jul 26
1
adjusting x-axis labels
I am trying to tweak how my categorical x-axis labels are formatted in
my bar graph. Specifically, I would like to a) decrease the spacing
between lines (e.g. spacing between Dialium and guianensis) b) right
justify the text and c) have each species name align with the center
of the corresponding bar graph.
A simplified version of my code thus far is as follows. I am using
RStudio v.
2010 Apr 25
4
how to make read in a vector of 0s and 1s with no space between them
Hi all,
Probably a rudimentary question. I have a flat file that looks like
this (the real one has ~10e6 elements):
10110100101001011101011
and I want to pull that into R as a vector, but with each digit being
it's own element. There are no separators between the digits. How can
I accomplish this? Thanks in advance!
Matt
--
Matthew C Keller
Asst. Professor of Psychology
University of
2011 May 23
2
Formatting names.arg
I am making a barplot using barplot2 from gplots and would like to
format the names of my categorical variables (tree species) on the x-
axis so that the genus name is above the species name (to save room).
My code so far is:
speciesnames<-c("Dialium guianensis", "Inga alba", "Tachigali
versicolor", "Brosimum utile", "Caryocar
2017 Oct 26
0
<p>R encountered a fatal error. </p> The session was terminated. + *** caught illegal operation ***
How about going back to earlier versions if you don't need the latest ones?
On Thu, Oct 26, 2017 at 12:59 PM, Klaus Michael Keller <
klaus.keller at graduateinstitute.ch> wrote:
> Dear all,
>
> I just installed the "Short Summer" R update last week. Now, my R Studio
> doesn't open anymore!
>
> --> <p>R encountered a fatal error. </p> The
2018 Aug 14
2
Xenial rpart package on CRAN built with wrong R version?
Hello,
I just upgraded my Ubuntu Xenial system to R 3.5.1 (from 3.4.?) by changing the sources.list entry and doing an "apt-get dist-upgrade". Everything works except loading the rpart package in R:
> library(rpart)
Error: package or namespace load failed for ?rpart?:
package ?rpart? was installed by an R version with different internals; it needs to be reinstalled for use with
2016 Jul 21
3
Openssh use enumeration
On Thu, Jul 21, 2016 at 12:31 PM, Selphie Keller
<selphie.keller at gmail.com> wrote:
> Ahh i see, just got up to speed on the issue, so seems like the issue is
> related to blowfish being faster then sha family hashing for longer length
> passwords,
or the system's crypt() not understanding $2a$ -style salts, which
most glibcs don't. On those, crypt fails immediately due
2016 Sep 08
5
DNF update
On 9/7/2016 7:02 PM, Keith Keller wrote:
>> Staying with excellent C6 until the end.
> CentOS 7 is yum based, not dnf.
"Always Learning" seems to have a distaste for anything new or different
than what he already knows.
--
john r pierce, recycling bits in santa cruz
2017 Oct 26
2
<p>R encountered a fatal error. </p> The session was terminated. + *** caught illegal operation ***
I've seen similar issues reported on the RStudio community site:
https://community.rstudio.com/. You might want to check in there, as I
think this may well be an RStudio issue rather than a problem with R itself.
Dave
On 26 October 2017 at 12:11, Eric Berger <ericjberger at gmail.com> wrote:
> How about going back to earlier versions if you don't need the latest ones?
>
2004 Apr 06
2
R loosing history
Hello,
Im running R 1.8.1 on Win2000 and frequently using the function history()
to keep track of what I did in my R session.
In a recent session I typed history(max=Inf) and to my surprise there were
only 15 lines of code where there should have been approx. 300 lines and I
lost a lot of valuable work.
Do you have any idea what caused this behaviour? help(history) didn't make
me any
2010 Jun 05
1
selecting only specific rows in R
Hi, I have a data frame with columns as follows: tree species
(independent variable) and several dependent variables (e.g. carbon,
nitrogen, phosphorus). Each row represents one tree sample. Some tree
samples are unique species in the data frame while other species were
replicated (i.e. rows 1,2,3 may be identical for the "tree species"
column but have different values for the