similar to: Arrhenius plot with lattice

Hello, sorry for incomplete code... with this I read the file and calculate my stuff. I have a plenty of them 80-300K every 5 Kelvin. I start with 79K, 80K...300K test<-read.table("T300_both.txt",header=FALSE,sep="") RH2<-c(RH2,2.5e7*.32e-4/100e-6/5100*(test$V3[c(2)]-test$V3[c(1)]+test $V3[c(4)]-test$V3[c(3)])) n2<-c(n2,-1/(RH2[c(46)]*1.60217e-19))

Hi, I'm currently doing some analyses on time of failure of a product. I found on the internet some article about the Arrhenius equation, and I can calculate the results with R. Equation: k=A*exp(-Ea/R*T) I can fit a model with lm for this purpose, so far no problem. But for the confidence interval, how can I use the Weibull distribution? Or should I use the weibull distribution at all? Or

Hello, the only thing I found to fit a sin/cos is s.th like lm(a~cos+sin) But this is not what I want. I have a magnitude which is sinusoidal with offset and it doesn't start at phi=0. The data is: angle<-c(0,10,20,30,40,50,60,70,80,90,100,110,120,130,140,150,160,170,180) Voltage<-c(-45.07, -45.24, -43.61, -40.78, -36.48, -30.92, -23.83, -15.95, -7.53, 1.06, 11.24,19.85, 27.00,

I have problems with Tcl/Tk in R 2.4.1, when running it on Windows Vista (see error message below). Regards, Sofia > library(tcltk) Loading Tcl/Tk interface ... Error in fun(...) : Can't find a usable init.tcl in the following directories: {C:\Program\R\R-2.4.1/Tcl/lib/tcl8.4} {C:\Program\R\R-2.4.1/Tcl/lib/tcl8.4} C:/Program/R/R-2.4.1/Tcl/lib/tcl8.4

Hi! How do you guys solve windows security updates? Is there a way to force windows computers to be updated. Even more flexible is if one can update windows through login script. Peter Nyberg Institutionen f?r Biokemi och Biofysik (DBB) Sv.Arrhenius v?gen 12 106 91 Stockholm Tel: 08-16 24 69 Mobil: 070 339 24 69 Fax 08 153679

Hi! -I've separated samba-3.0.2a and openldap-2.1 on two computers with Slackware 9.1 -smbldap_populate.pl genertated all standard groups and the Administrator account -The ldap seams to work now ldapsearch -H ldap://l1.dbb.su.se/ -b dc=dbb,dc=su,dc=se -x ldap_bind: Confidentiality required (13) additional info: TLS confidentiality required -This is like it should be since the server

Hi! I know this should be asked to the Openldap mailing list but: I?m trying to set up a Samba/ldap environment were the Samba server is separated from the ldap server. Everything seams to work on the ldap server and when I do a ldapsearch like this: ldapsearch -H ldap://l1.dbb.su.se/ -b dc=dbb,dc=su,dc=se ?x Everything works on both. But when I do: ldapsearch -H ldaps://l1.dbb.su.se/ -b

Dear all, I have a probability of presence of distribution of a species of interest (varying from 0 to 1 in continuous form) and I have a set of points where I know that species really occurs. But I don´t have points of absence. So, for each true presence I know the estimated presence. I would like to know how can I compute AUC, taking account these Available data. Best wishes,

Dear all, For my PhD study I'm looking for relevant courses/workshops (short term) in ecological data anlysis with R in Europe. After 2 days searching I'm convinced that google is probably not the right medium to find this information. If anyone can help me I will be most grateful. Best regards - J. Capelle [[alternative HTML version deleted]]

Dear All, I have to install 'stats' package in my windows machine, could you let me know how to install the package? Look forward to your assistance, Ajay. ------------------------------------------------------------- Ajay Singh, Ph.D. |Tel: +91-22 25764785 Research Scientist, |Fax: 091-22-25722872 S.J.M. School of Management,

Hi all, I have a matrix with 5 rows and 10 columns, which represent the grids on a rectangular map. I used the code below to plot, but it gives me the map with the 10 columns as y-axis, and the 5 rows as the x-axis, and the (0,0) point is at the usual bottom left hand corner. My map starts with the (0,0) at the top left hand corner. How can I rotate the map 90 degrees clockwise so the (0,0)

How would I make a population histogram in R from an excel file? Thanks [[alternative HTML version deleted]]

Dear all I have a code like x<-1:10 y1<-x+runif(10)*2 y2<-seq(0,50,length.out=10)+rnorm(10)*10 par(mfrow=c(1,2)) plot(y1~x) plot(y2~x) Now I would like to plot y1 and y2 on the same graph, with its two scales (y1 on left and y2 on rigth side). Any help are welcome. Kind regards Miltinho Brazil [[alternative HTML version deleted]]

Dear all, I need to run a interactive procedure where the user will need click on the screen (over a XY plot) and I need to record the XY coordinate which the user clicked. Roughly I wrote a short code below. You see that I suppose that the user will choose four coordinates inside the region of intersection between three segmentes. On each click, I would like to record the position clicked in a

Dear all, I have a set of x,y,z points obtained from a lizard species and now I would like to estimate the three-dimensional use of space for this species. I know that 2D area I can estimate using adehabitat packages, but I don´t know how to estimate the volumetric space. Any help are welcome. Miltinho Brazil [[alternative HTML version deleted]]

Hi there, I´m trying to use "simecol" package but I got the error showed below. I´m runnig R version 2.4.0 (2006-10-03). Kind regards, miltinho Brazil --- > require(simecol) Loading required package: simecol Error in loadNamespace(package, c(which.lib.loc, lib.loc), keep.source = keep.source) : in 'simecol' methods specified for export, but

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I am trying to produce a simple plot where the points in the plot are actually integers from my data. That is, I am making a length/width plot and I would like the points, rather dots or triangles, appear as different numbers corresponding to a column in my data. I have tried using this: ...,pch="column title" but this merely returns the first letter of the column title, B. Is there

Hi, how can I treat data organised in classes and frequencies? Ex. class frequency 20-23 9 23-25 7 26-28 5 29-31 5 32-34 3 Thanks Angelo Scozzarella