similar to: Re-arrange Columns in data frame

Dear all, I'm trying to process a log file which logs the date, the username and the computer number accessed. The table looks like this: >table.users          Date UserName Machine 1  2008-11-25     John     641 2  2008-11-25    Clive     611 3  2008-11-25   Jeremy     641 4  2008-11-25     Walt     722 5  2008-11-25     Tony     645 6  2008-11-26     Tony     645 7  2008-11-26    

Dear R Help, I have a set of data of heights of trees described by area that they are in. The areas are numerical (0 to 7). ht area 1 320 3 2 410 4 3 230 2 4 360 3 5 126 1 6 280 2 7 260 2 8 280 2 9 280 2 10 260 2 ....... 180 450 4 181 90 1 182 120 1 183 440 4 184 210 2 185 330 3 186 210 2 187 100 1 188 0 0 I want to convert the

NAME ID a b c d 1 Control_1 probe~B01R01C01 381 213 345 653 2 Control_2 probe~B01R01C02 574 629 563 783 3 Control_1 probe~B01R09C01 673 511 521 967 4 Control_3 probe~B01R09C02 53 809 999 50 5 MM0289~RFU:11810.15 probe~B29R13C06 681 34 115 587 6 MM0289~RFU:9238.41 probe~B29R13C05 784 443 20 784 7 MM16597~RFU:36765.38 probe~B44R15C20 719 251 790 445 8 MM16597~RFU:41258.94 probe~B44R15C19 677

I'd like to "step" through 24 histograms by using the return or click button option, as shown in the demo(graphics) demonstration. I've searched for "interactive graphics", and "waiting for page change" in R documentation but with no result. I'm sure that this is a relatively straightforward procedure. Can anyone point me to the correct solution?   Jabez

Dear all, please help with what must be a straightforward question which I can't answer. I add a column of my dataframe as factor of an existing column e.g. df[,5] <- factor(df[,2]) and can test that it is by is.factor() but if I did not know in advance what "types" the columns were, is there a function to tell me what they are. i.e. instead of

Dear list, I have read an excel table into R using read.table() and headers=T. The table is 7 columns of figures. Is there any way to gain access to the header information? Say the table headers are Mon, Tue etc I can get to the data with myTable$Tue, but how do I get the headers themselves. TIA Jab [[alternative HTML version deleted]]

Hi, I've read in a csv file (test.csv) which gives me the following table: Hin1 Hin2 Hin3 Hin4 Hin5 Hin6 HAI1 9534.83 4001.74 157.16 3736.93 484.60 59.25 HAI2 13272.48 1519.88 36.35 33.64 46.68 82.11 HAI3 12587.71 5686.94 656.62 572.29 351.60 136.91 HAI4 15240.81 10031.57 426.73 275.29 561.30 302.38 HAI5 15878.32 10517.14 18.93 22.00 16.91

there are really two related problems here I have a 2D matrix A <- matrix(1:100,nrow=20,ncol =5) S <- matrix(1:10,nrow=2,ncol =5) #I want to subtract S from A. so that S would be subtracted from the first 2 rows of #A, then the next two rows and so on. #I have a the same problem with a 3D array # where I want to subtract Q for every layer (1-10) in Z # I thought I solved this one

Thank you for help with the first part. The second part I do not understand. All I get is "3" "3". Presumably this is the factor that you refer to. Is there no simple way of extracting the text alone ----- Forwarded Message ---- From: Peter Alspach <PAlspach@hortresearch.co.nz> To: Jabez Wilson <jabezwuk@yahoo.co.uk> Sent: Tuesday, 7 November, 2006 7:46:02 PM

i have the following constructed and running very well,, thanks to Gabor Grothendieck for his help. >data.info <- c("station.id", "year", "date", "max.discharge") > > for(i in 1:num.files) { + station.id <- substring(data[i], 1,8) + DF <- read.table(data[i], sep=",", blank.lines.skip = TRUE) + z <- zoo(DF[,4],

Greetings, My goal is to create a Markov transition matrix (probability of moving from one state to another) with the 'highest traffic' portion of the matrix occupying the top-left section. Consider the following sample: inputData <- c( c(5, 3, 1, 6, 7), c(9, 7, 3, 10, 11), c(1, 2, 3, 4, 5), c(2, 4, 6, 8, 10), c(9, 5, 2, 1, 1) ) MAT <- matrix(inputData,

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I have some square matrices with na values in corresponding rows and columns. M<-matrix(1:2,10,10) M[6,1:2]<-NA M[10,9]<-NA M<-as.matrix(as.dist(M)) print (M) 1 2 3 4 5 6 7 8 9 10 1 0 2 1 2 1 NA 1 2 1 2 2 2 0 1 2 1 NA 1 2 1 2 3 1 1 0 2 1 2 1 2 1 2 4 2 2 2 0 1 2 1 2 1 2 5 1 1 1 1 0 2 1 2 1 2 6 NA NA 2 2 2 0 1 2 1 2 7 1 1 1 1 1 1 0 2 1 2 8

Hi, I have a dataframe with around 100 columns. Now I want to redefine some of the columns as factors (using as.factor). Luckily all the names of the columns I want to redefine start with "crast". Thus I thought I can use grep() for that purpose... ...I found an example for redefining a single column as factor but that is not working with multiple columns I get from grep()... what I

Dear R-helpers, I'm not a speciallist in writing complex functions, and the function still very rusty (any kind of suggestions are very welcome). I want to implement Gale-Shapley algorithm for R Language. It is based on http://www.jstor.org/stable/10.2307/2312726 Gale and Shapley (1962) , and it has evolved to

Hi, I'm new to R and I'm stuck trying to import some data from a .dat file I've been given. The tricky bit for me is that the data has both variable values and labels? The data looks like this, Id=1 time=2011-03-27 19:23:40 start=1.4018 end=1.4017 Id=2 time=2011-03-27 19:23:40 start=1.8046 end=1.8047 Id=1 time=2011-03-27 19:23:50 start=1.4017 end=1.4018 Id=2

Hi I have a matrix a = 1 2 3 1 2 3 1 2 3 1 2 3 1 2 3 1 2 3 b = 5 6 7 8 9 10 I want output as c = 5 2 3 8 2 3 1 6 3 1 9 3 1 2 7 1 2 10 Please any on help to avoid reduncy of my code ----- Thanks in Advance Arun -- View this message in context:

i have a data frame with 2 columns of dates. with str(dataframe) i have ensured myself that they were indeed formatted as dates. one column has NA's in it. the aim is now to make a third column that chooses date1 if it is a date, and choose date2 if it is a NA. i am trying df$date3=ifelse(is.na(df$date1), df$date2, df$date1). this leads to unexpected behaviour: the resulting column is

Dear R help, I have a data frame column in which I would like to replace some of the numbers dependent on their value. data frame = zz AveExpr t P.Value FC 7.481964 7.323950 1.778503e-04 2.218760 7.585783 12.233056 6.679776e-06 2.155867 6.953215 6.996525 2.353705e-04 1.685733 7.647513 8.099859 9.512639e-05 1.674742 7.285446 7.558675 1.463732e-04 1.584071

Hi, I'm having difficulty with getting a table to show with multiple rows and columns. Below is the commands that I've typed in and errors that I am getting. Thank you. Laura Table trying to enter: Diet: Binger-yes: Binger-No: Total: None 24 134 158 Healthy 9 52 61 Unhealthy 23 72 95 Dangerous 12 15 27 >