similar to: Method

Greeting Listserv Readers, At http://r4stats.com/popularity I have added plots, data, and/or discussion of: 1. Scholarly impact of each package across the years 2. The number of subscribers to some of the listservs 3. How popular each package is among Google searches across the years 4. Survey results from a Rexer Analytics poll 5. Survey results from a KDnuggests poll 6. A rudimentary analysis

Dear R helpers Suppose I have a vector as vect1 = as.character(c("ABC", "XYZ", "LMN", "DEF")) > vect1 [1] "ABC" "XYZ" "LMN" "DEF" I want to reverse the order of this vector as vect2 = c("DEF", "LMN", "XYZ", "ABC") Kindly guide Regards Vincy [[alternative HTML

Hi, I wonder if anyone knows how to generate a list of objects, e.g. ten vectors with names: vect1, vect2, ... , vect10. My own idea was to use something like: for (i in 1:10) print(paste("vect", i,"<-NULL",sep="")) but the result is: "vect1<-NULL" ... "vect10<-NULL" and not vect1<-NULL ... vect10<-NULL as I would

Hello, I would like to ask you a question.I have a program in R and I use the readline method to ask the user some things,but i don?t use the R console but I use Win console then not appear what I put.I put the code as you look for: cat("1- 24horas\n") cat("2- 12horas\n") cat("3- 8horas\n") selection<-readline(prompt="\nSelecciona numero de horas:")

Hi everybody, I am currently working on mixtures of two densities ( f(xi,teta)= (1-teta)*f1(xi) + teta*f2(xi) ), particularly on the behavior of the variance for teta=0 (so sample only comes from the first distribution). To determine the maximum likelihood estimator I use the Newton-Rapdon Iteration. But when computing the first derivative I get a none linear function (with several asymptotes)

Hi R users: I have de following data frame (called "Sx") Descripcion Nitratos Cont85g 72.40 Cont85g 100.50 Cont85g 138.30 Cont80g 178.33 Cont80g 79.01 Cont80g 74.16 Cont75g 23.70 Cont75g 15.80 Cont75g 16.20 Patron80g

Dear all, I have a large vector (lets call it myVector) and I want to plot its value with the logic below yaxis<-myVector[1] yaxis<-c(xaxis,mean(myvector[2:3]) yaxis<-c(xaxis,mean(myvector[4:8]) yaxis<c(xaxis,mean(myvector[9:16]) yaxis<c(xaxis,mean(myvector[17:32]) this has to stop when the new ..... yaxis<c(xaxis,mean(myvector[1024:2048]) will not find the correspondent number

Hi, set.seed(29) myVector<- rnorm(100) ?seq(1,100,by=2) # [1]? 1? 3? 5? 7? 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 #[26] 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 99 myVector[seq(1,100,by=2)] rev(myVector) ?sum(myVector>0) #[1] 46 #or ?table(myVector>0) # #FALSE? TRUE ?#? 54??? 46 A.K. Hey guys, this is my first week

>From: Johannes Graumann <johannes_graumann at web.de> >Date: 2007/12/18 Tue PM 04:40:37 CST >To: r-help at stat.math.ethz.ch >Subject: [R] All anchored series from a vector? lapply(1:length(myvector) function(.length) { c(myvector[1}:myvector[.length]) }) but test it because i didn't. >Hi all, > >What may be a smart, efficient way to get the following result:

Yes, I am a newbie. I have a data.frame (MyTable) of 1445846 rows and 15 columns with character data. And a character vector (MyVector) of 473491 elements. I want simply to get a data.frame with the count of how many times each element of MyVector appears in MyTable. I've tried a loop with : for (i in 1 : length (myvector)) sum (MyTable== i) but it crashes my computer. I've also

Hi, all I didn't get any response from swig for my question. see if I can get some help here Thanks ---------- Forwarded message ---------- From: charlie <charlie.xia.fdu@gmail.com> Date: Tue, Nov 4, 2008 at 1:55 PM Subject: SWIG with R and C++ STL To: swig-user@lists.sourceforge.net Hi all, I am new to SWIG. I encountered some problem when I try to SWIG to R some C++ modules. Here

I have a set of character vectors of uneven length that I have stored in a list. I can easily enough get any column of them using lapply but what I want is to be able to create a matrix of them. Other than some kind of brute force looping approach I have drawn a blank. Would somebody please suggest something? Thanks Example. mylist <- list(aa=c("cat","peach" ),

I have two objects, one matrix and one vector. I want to use my vector to subset certain values out of my matrix. For example: I want to tell R, to select out all rows in myMatrix into a new myMatrix2 IF that corresponding row is less than a 0.5 in myVector. So: myMatrix = a matrix of 8000 by 20 myVector = vector of 8000 myMatrix2 = a matrix of < 8000 by 20 (based on selection criteria in

Hello, Let's assume I have a vector of integers : > myvector <- c(1, 2, 3, 2, 1, 3, 5) My purpose is to obtain the cumulative distribution of these numerical data, i.e. something like : value nb_occur. <=1 2 <=2 4 <=3 6 <=4 6 <=5 7 For this, I create a table with ; > mytable <- table(myvector) 1 2 3 5 2 2 2 1 However, table() returns an array

I have been trying to write a new class that reimplements the vector class. As a test of my overloading I decided to try and and call t.test on two vectors which were objects of my class rather than the default class. The overloaded length I wrote seems to work correctly. I used setMethod("length", "myvector", ...) setMethod("mean", "myvector", ...)

Dear all, I have a vector with number that some of them are part of the   seq(1,800,4). How can I check which of the numbers belong to the seq(1,800,4)   LEt's say that is called myvector the vector with the numbers. Is there in R something like this? is.member(myvector,seq(1,800,4))   I would like to thank you in advance for your help   B.R Alex [[alternative HTML version deleted]]

Hello, I have an expression that I want to substitute for something else. myvector<-c("ajkhfkiuwe","Variable(kg/min)") if I use the following code to extract "variable(kg/min)" and substitute it for "va" gsub(myvector[grep("var", myvector, ignore=T)], "va", myvector) grep identifies the element of the vector that matches my

HI, R user, I generate the vectors with the same length. I want to put each vector into each column of data frame. Why it doesnt work`? rm<-data.frame() for(a in 1:6){ rm[,a]<-getmeasure(p1,a,speech) } thanks a lot Tammy _________________________________________________________________ Share your memories online with anyone you want.

Dear People, I have got the following example for a vector and the index of the TRUE element: Myvector <- c(FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,TRUE) which(Myvector) Now I would like to find out the same for a list: Mylist <- list(FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,TRUE) ... Does anyone know how to do this? Thank you very much in advance, Marion [[alternative HTML

Hello dear R-helpers, I haven't been able to figure out of find a solution in the R-help archives about how to delete all the characters contained in groups of parenthesis. I have a vector that looks more or less like this: myvector<-c("something (80 km/h, sd) & more (6 kg/L,sd)", "somethingelse (48 m/s, sd) & moretoo (50g/L , sd)") I want to extract all