similar to: ow to have R automatically print traceback upon errors

I would like to have an automatic traceback printed on error. Is there a way to do this? options(error=traceback) seems to print the previous error, not the current error. I'm guessing this is because the traceback is not set until the error handler is done running. > options(error=traceback) > stop("1") Error: 1 No traceback available > stop("2") Error: 2 1:

Hi I am using R scripts which are running remotely. To make debugging easier, I would like to have the possibility to execute traceback() automatically when an error occurs. Is this possible? OS: Linux Thanks Rainer -- Rainer M. Krug, PhD (Conservation Ecology, SUN), MSc (Conservation Biology, UCT), Dipl. Phys. (Germany) Centre of Excellence for Invasion Biology Faculty of Science Natural

Dear all, I wrote the following batch script on a iMac, and ran it on a linux mosix cluster. tu <- read.table("cage.mm5.tags.rna_lib.CAA-CAJ.tu-reshape.table") tu_reshaped <- t(reshape(tu[1:50,], direction="wide", timevar="tu", idvar=c("rna","lib"))) write.table(tu_reshaped, "cage.mm5.tags.rna_lib.CAA-CAJ.tu-reshaped.table")

Hello, I am having a some problems getting SSHD to run on the Ipv6 interface. Interface/Ipv6 Address: ipv6.open-systems.org [kevin at satan kevin/xp-0.0.15] 536 $ping6 ipv6.open-systems.org PING6(56=40+8+8 bytes) 3ffe:1200:3028:ff01::cab --> 3ffe:1200:3028:ff01::caa 16 bytes from 3ffe:1200:3028:ff01::caa, icmp_seq=0 hlim=64 time=73.96 ms sshd_config: ListenAddress

On Sun, 19 Jan 2025, Ivo Welch wrote: > Hi Duncan ? Wonderful. Thank you. Bug or no bug, I think it would be > a huge improvement for user-friendliness if R printed the last line by > default *every time* a script dies. Most computer languages do so. > > Should I file it as a request for improvement to the R code > development team? Maybe R can be improved at a very low cost

Hi, Is there a way to get the enclosing function name within a function? For example, I would like to have a function getEnclosingFunctionName(). It works like below f = function(){ print(getEnclosingFunctionName()) } f() # will print "f" Thanks Jeff

Hello everyone, I am trying to "parse" a part of LLVM IR. More exactly, from @.str = private unnamed_addr constant [3 x i8] c"DS\00", section "llvm.metadata" I want to get "DS". It is the single place in the whole bytecode from where I can get it. I have : ... Value *VV = cast<Value>(LD100->getOperand(1)->getOperand(0));

Thanks for pointing out the options. Using options(show.error.locations = TRUE) works on Ivo's example, but it doesn't show a location if the error happens in a function that doesn't have srcrefs, because the known location isn't on the top of the stack. Perhaps TRUE (and maybe "top"?) should look back through the stack until it finds a known location, and

PowerDNS supports CAA records beginning with version 4.0, but the pdns package in EPEL for most recent centos versions is stuck at around version 3.4 (3.4.11 is what I have). Do I have no other choice but to manually compile and maintain my own pdns installation? I prefer to avoid this but I need up-to-date features. Perhaps there is a PowerDNS specific work-around? Maybe the EPEL

I've posted a patch to bugs.r-project.org that fixes the traceback() issue. It's not specific to findFun3; you get the same problem with errors from expressions like 1 + "a" In my testing, I occasionally saw cases where show.error.locations = TRUE didn't work. I'll try to track down a reproducible case, and perhaps a patch to fix it. Duncan Murdoch On

Sorry, I'm not seeing the first problem now: options(show.error.locations = TRUE) works fine. Not sure what I did wrong before. I'm still seeing `traceback()` failing to report the attempt to call nofunction(). I suppose this is because a context is never set up for the failed call. Perhaps findFun3 could set up a fake context so that traceback() adds one more entry? Duncan

Hi, Is this method broken in R? I am using it to find roots of the following function: f(x) = 2.5*exp(-0.5*(2*0.045 - x)) + 2.5*exp(-0.045) + 2.5*exp(-1.5*x) - 100 It is giving an answer of -38.4762403 which is not even close (f(x) = 2.903809e+25 for x=-38.4762403). The answer should be around 0.01-0.1. This function should converge.. Even for a simple function like f(x) = exp(-x) * x, it gives

Dear Sirs/Madam, I am a beginner to R, and I am currently working on a data matrix which looks like this: > head(oligo) ko:K00001 ko:K00003 ko:K00005 ko:K00008 ko:K00009 ko:K00010 ko:K00012 AAA 370 631 365 67 164 455 491 KAA 603 1208 170 157 68

understood. but, please, consider not people like me but unwary beginners and students of R. I have used R now for decades, and even I am baffled by it. Couldn't you make R code easier to debug not only for people like me (who can indeed tweak their environments) but also for novice users? On Sun, Jan 19, 2025 at 8:46?AM <luke-tierney at uiowa.edu> wrote: > > On Sun, 19 Jan

Hi, I have a data set similar to the following State Gender Quantity TX Male 1 NY Female 2 TX Male 3 NY Female 4 I need to calculate cumulative sum of the quantity by State and Gender. The expected output is State Gender Quantity CumQuantity TX Male 1 1 TX Male 3 4 NY Female 2 2 NY Female 4 6 I highly appreciate if someone can give me some hints on solving that in R. Hao -- View this

And now I've found the elusive bug in show.error.locations = TRUE as well, and posted a patch for that too. Back to the original topic of this thread: I think most users should routinely use options(show.error.locations = TRUE) e.g. in their .Rprofile. That will often speed up bug fixes, especially if my patch is incorporated. Duncan Murdoch On 2025-01-20 5:56 p.m., Duncan Murdoch

Am 05.03.2018 um 13:04 schrieb Nicolas Kovacs <info at microlinux.fr>: > > Le 28/02/2018 ? 22:23, Nicolas Kovacs a ?crit : >> So far, I've only been able to filter HTTP. >> >> Do any of you do transparent HTTPS filtering ? Any suggestions, >> advice, caveats, do's and don'ts ? > > After a week of trial and error, transparent HTTPS filtering

Hi, I have a vector with lots of NAs. e.g. vec = c(NA, NA, 2, NA, NA, 5, NA, 6, NA) > vec [1] NA NA 2 NA NA 5 NA 6 NA I would like to replace NAs with their immediately previous non NA number. After replacement, the above vector will become > vec [1] 0 0 2 2 2 5 5 6 6. I understand how to do that with a loop but the actual vector is very long and the loop takes too much time in R.

Hi, I would like to extract the last row of each group in a data frame. The data frame is as follows Name Value A 1 A 2 A 3 B 4 B 8 C 2 D 3 I would like to get a data frame as Name Value A 3 B 8 C 2 D 3 Thank you for your suggestions in advance Jeff

Hi, I have a a vector and a data frame with two columns vec = c("C", "A", "B") dataDF = data.frame(A1 = c("B", "A", "C"), A2 = c(1,2,3)) I would like to sort the data frame by column A1 such that the order of elements in A1 is as the same as in vec. After the ordering, the data frame would be A1 A2 C