similar to: Relase positive with log and zero of negative with 0

I have a matrix of frequency counts from 0-160. x<-as.matrix(c(0,1,0,0,1,0,0,0,1,0,0,0,0,1)) I would like to apply a function creating a new column (x[,2])containing values equal to: a) log(x[m,1]) if x[m,1] > 0; and b) for all x[m,1]= 0, log(next x[m,1] > 0 / count of preceding zero values +1) for example, x[1,2] should equal log(x[2,1]/2) = log(1/2) = -0.6931472 whereas x[3,2] should

Hi all, Suppose I want to set the values in a column to the log of the values of another column like so: object$LogDist <- log10(object$Distance) How do I loop through the objects if I have object1, object2, etc to perform this function? object1$LogDist <- log10(object1$Distance) object2$LogDist <- log10(object2$Distance) object3$LogDist <- log10(object3$Distance) I was trying to

I would expect that several math operations should always return values with a class of numeric. If the input is defined with multiple classes, however, the class attribute is preserved. I would think this may have some unintended side-effects. Here's an example: > sessionInfo()$R.version$version.string [1] "R version 3.4.0 (2017-04-21)" > x <- seq.int(5) >

I think you may be confusing (S3) class and ?mode. > x <- seq.int(1:3) > class(x) [1] "integer" > mode(x) [1] "numeric" > class(x+.5) ## coercion [1] "numeric" > mode(x+.5) [1] "numeric" But note: > y <- as.integer(1) > class(y) [1] "integer" > class(y) <- "foo" > mode(y) [1] "numeric" >

I am trying to fit a very simple broken stick model using the package "segmented" but I have hit a roadblock. > str(data) 'data.frame': 18 obs. of 2 variables: $ Bin : num 0.25 0.75 1.25 1.75 2.25 2.75 3.25 3.75 4.25 4.75 ... $ LnFREQ: num 5.06 4.23 3.50 3.47 2.83 ... I fit the lm easily: > fit.lm<-lm(LnFREQ~Bin, data=id07) But I keep getting an error

Thanks Bert, I think we agree on the current behaviour, but I'm still not sure if it's desirable. The mode isn't used for method dispatch. In the following example, I have to write `log.foo` in order for the correct method to be called. > x <- seq.int(5) > class(x) <- c("integer", "foo") > half <- function(x) UseMethod("half") >

Am I trying to perform multiple linear regressions on each 'VARIABLE2'. I figured out that there are different ways, using the following code: (data is given at the end of this message) reg <- lapply(split(TRY, VARIABLE2), function(X){lm(X2 ~ X3, data=X)}) lapply(reg, summary) Which produces the following: $`1` Call: lm(formula = X2 ~ X3, data = X) Residuals: Min

hello everyone, I am Maheshwar, a prefinal year Computer Science undergraduate student at BITS-Pilani, India. When i was going through the GSOC ideas , i felt interested in Quesry parser project. Till now i have implemented a couple of LL(1) parsers as a part of my assignment in Compiler construction course, so i would love to join and contribute to this project. So can any one tell me how to go

Hello, first of all, thanks to LT for \pkg{codeutils}. I agree that it is indeed very useful to identify errors and also to encourage re-thinking past solutions. My problem: I want to compare different sets of related sub-functions which should be used alternatively by the same top-level function. Sets of related functions should be bound together (as lists) and the workspace should be as clean

Hi I want to write a little function that takes a matrix X of size m-by-n, and a list L of length "m", whose elements are matrices all of which have the same number of columns but possibly a different number of rows. I then want to get a sort of dumbed-down kronecker product in which X[i,j] is replaced by X[i,j]*L[[j]] where L[[j]] is the j-th of the "m" matrices. For

Hi, I'm experimenting with a few learners that require a matrix as their input. (Currently svmpath, vbmp, etc.) I currently have a dataframe with 50 columns and 20,000 rows. I tried using: x <- as.matrix(my_data.frame) If I then as, "is.matrix(x)", I get TRUE. However everywhere I've tried to use the matrix returns errors. Is there a step I'm missing? Thanks! -N

I have found a strange scoping problem in Sweave. The following Rnw file doesn't produce the same output in Sweave as it does if I produce an R file using Stangle and execute that: \documentclass[12pt]{article} \begin{document} <<R>>= election <- data.frame(A=1:3, B=9:7, C=rep(0,3)) partytotal <- rep(0, ncol(election)) for (i in 1:ncol(election)) { partytotal[i] <-

Hi, This might be me missing something painfully obvious but why does the cube root of the following produce an NaN? > (-4)^(1/3) [1] NaN > As we can see: > (-1.587401)^3 [1] -4 Thanks! Greg

Hi look at the following session, in which I have a dataframe, and I want to extract the second row, without the first column. Everything works as expected until the last line, where I set the names of x to NULL, and get a non-desired object (I want c(4,3).). Three questions: (1) why is as.vector(a[2,-1]) not a vector? (2) How come setting names to NULL gives me bad weirdness? (3) Can I

I need to make a bunch of PDF files of histograms. I tried gatelist = unique(mdf$ArrivalGate) for( gate in gatelist) { outfile = paste("../", airport, "/", airport, "taxiHistogram", gate, ".pdf", sep="") pdf(file = outfile, width = 10, height=8, par(lwd=1)) title=paste("Taxi time for Arrival Gate", gate, "by

Hi, I've been trying to get this working for ages, but it causes R to hang. Here is my C code saved as test1.c # include <R.h> # include <Rmath.h> void test1 (double *x, double *result) { result[0] = rgamma(*x, 2.0); } This was compiled using R CMD SHLIB test1.c & loaded in R using: dyn.load("test1.dll") out <-

Hello! I am writing some functions and I repeatedly acces internal factor codes. I figured out that internal codes are 1:n where 1 represents 1st level, 2 2nd level etc. This is not documented and I wonder if this is on purpose and subject to change or would be a good idea to add this to documentation for factor? I can prepair a pacth if this is accepted. -- Lep pozdrav / With regards,

When a graph is saved as PostScript, the bounding box is often too big. A consequence is that when the graph is included in a LaTeX document, the spacing does not look good. Is this a recognized problem? Is someone working on it? Could I help? David

Full_Name: Myung Geun Kim Version: 2.4.0 OS: Window XP Submission from: (NULL) (210.110.8.105) For the data c1 of size 14, stem provides the following result. ************************************************************** >c1 [1] 14 39 70 11 38 20 37 15 41 74 74 34 48 51 ZZangi>stem(c1) The decimal point is 1 digit(s) to the right of the | 0 | 145 2 | 04789 4 | 181 6 | 044

I want to do the following: DEVw=500 DEVh=350 fname="my_plot" dev.print(file=fname, device=FOO, width=DEVw, height=DEVh, bg="transparent") How do I do this such that I can specify FOO to be one of several choices? (GDD, PNG, postscript, etc.) If I make FOO a character variable, then "dev.print" complains. I tried a simpled "substitute" but